Maths Class 6 Chapter 2 Questions and Answers - Free PDF Download
In Ncert Solutions Class 6 Maths Chapter 2 Exercise 2 7, you’ll discover how lines and angles work together in everyday life. This exercise focuses on rotating arms and how they form different types of angles, like right, acute, and obtuse angles. It's a fun way to see how geometry is used all around us, from the corners of windows to folding paper to make new shapes!
Table of Content
If you want a clear path to mastering these questions, Vedantu’s NCERT Solutions break down every problem into easy steps. You’ll understand exactly how to measure, compare, and identify angles—just like in your classroom or at home. For even more help, check out the easy-to-read Class 6 Maths syllabus to know what else you’ll learn this year.
Download the free NCERT Solutions PDF anytime, practise at your own pace, and build the confidence you need for classroom questions and exams. These solutions make sure you’re never stuck and can keep learning new things about geometry every day!
Exercise 2.7
1. How many right angles do the windows of your classroom contain? Do you see other right angles in your classroom?
Ans: In general a window has 4 right angles
$\angle$1, $\angle$2, $\angle$3 and $\angle$4
Yes, At corners of the door and at corners of the blackboard etc.
2. Join A to other grid points in the figure by a straight line to get a straight angle. What are all the different ways of doing it?
Ans:
This can be done in one way.
3. Now join A to other grid points in the figure by a straight line to get a right angle. What are all the different ways of doing it?
Hint: Extend the line further as shown in the figure below. To get a right angle at A, we need to draw a line through it that divides the straight angle CAB into two equal parts.
Ans:
4. Get a slanting crease on the paper. Now, try to get another crease that is perpendicular to the slanting crease.
a. How many right angles do you have now? Justify why the angles are exact right angles.
Ans: We get 4 right angles.
For example let say M be the point of intersection of the two creases.
The 2 creases are perpendicular lines meeting at P.
Therefore, all the four angles are right angles.
b. Describe how you folded the paper so that any other person who doesn’t know the process can simply follow your description to get the right angle.
Ans:
Step 1: Start by taking a sheet of paper and fold it in half.
Step 2: Press firmly to create a crease along the fold.
Step 3: Fold the paper once more so that the two sections of the crease align perfectly.
Step 4: Press down again to form another crease.
Step 5: Unfold the paper completely to reveal both creases.
You will now see two perpendicular lines intersecting, forming four right angles.
Benefits of NCERT Solutions for Class 6 Maths Chapter 2 Exercise 2.7 Lines and Angles
Students gain a simple and clear understanding of making rotating arms.
Exercise 2.7 solutions help students visualise and comprehend how rotating arms form different angles, simplifying the concept of angle measurement.
The solutions provide a thorough explanation of how lines and angles are related, helping students understand the core concepts of geometry.
The concepts taught through rotating arms and angles can be applied to real-life situations, such as understanding the movements of objects and directions, making learning more relevant.
The solutions are based on the NCERT curriculum, ensuring that all the important topics are covered thoroughly.
Class 6 Maths Chapter 2: Exercises Breakdown
Important Study Material Links for Class 6 Maths Chapter 2 - Lines and Angles
Conclusion
The NCERT Solutions for Class 6 Maths Chapter 2 Lines and Angles Exercise 2.7 on Making Rotating Arms" provided by Vedantu provides a clear and detailed approach to understanding angle formation. By exploring how rotating arms create different types of angles, students can easily understand the key concepts of geometry. These solutions simplify learning with step-by-step explanations, making it easier for students to practise and build confidence in solving problems related to lines and angles. Aligned with the NCERT syllabus, these solutions ensure that students are well-prepared for exams and can develop a strong foundation in geometry for future topics. Vedantu’s solutions help make learning engaging, practical, and effective for all students.
Chapter-specific NCERT Solutions for Class 6 Maths
The chapter-wise NCERT Solutions for Class 6 Maths are given below. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.
Related Important Links for Class 6 Maths
Along with this, students can also download additional study materials provided by Vedantu for Maths Class 6.
FAQs on NCERT Solutions For Class 6 Maths Chapter 2 Lines And Angles Exercise 2.7 - 2025-26
1. Where can I find reliable and step-by-step NCERT Solutions for Class 6 Maths Chapter 2, Whole Numbers?
You can find comprehensive and accurate NCERT Solutions for Class 6 Maths Chapter 2 (Whole Numbers) right here. These solutions are prepared by subject experts and are fully aligned with the latest CBSE 2025-26 syllabus, providing clear, step-by-step methods for solving every problem in the textbook exercises.
2. What is the correct method to find the predecessor and successor of a whole number as per the NCERT textbook?
The correct method is straightforward:
- To find the successor of a whole number, you simply add 1 to it. For example, the successor of 99 is 99 + 1 = 100.
- To find the predecessor of a whole number (except 0), you subtract 1 from it. For example, the predecessor of 99 is 99 - 1 = 98.
3. How do the NCERT Solutions explain the use of a number line for adding whole numbers in Chapter 2?
The NCERT Solutions for Chapter 2 explain addition on a number line with these steps:
- Start at the first number on the number line.
- To add the second number, move that many steps to the right.
- The number you land on is the sum. For example, to solve 3 + 4, you start at 3 and move 4 steps to the right, landing on 7.
4. Why is the distributive property important for solving problems in Exercise 2.2?
The distributive property (of multiplication over addition) is crucial because it simplifies complex calculations. For a problem like 101 × 25, you can break it down as (100 + 1) × 25. Applying the property, you get (100 × 25) + (1 × 25) = 2500 + 25 = 2525. This method, detailed in the NCERT solutions, makes multiplication with larger numbers faster and less prone to errors.
5. How does the associative property help in finding the product by suitable rearrangement in Chapter 2?
The associative property allows you to regroup numbers in a multiplication problem to make it easier to solve mentally. For example, to solve 4 × 125 × 25, instead of multiplying in order, you can rearrange it as (4 × 25) × 125. Since 4 × 25 = 100, the problem becomes a simple 100 × 125 = 12500. This smart rearrangement is a key problem-solving technique in the chapter.
6. Why is zero (0) called the additive identity for whole numbers?
Zero is called the additive identity because when you add 0 to any whole number, the number’s value or 'identity' does not change. For any whole number 'a', a + 0 = a. This property is fundamental to the system of whole numbers and is a key concept explained in Chapter 2.
7. What is a common mistake students make when finding the product of the largest 3-digit number and the largest 2-digit number using properties?
A common mistake is performing direct long multiplication instead of using properties. The largest 3-digit number is 999 and the largest 2-digit number is 99. The correct NCERT approach is to use the distributive property: solve 999 × 99 as 999 × (100 - 1). This becomes (999 × 100) - (999 × 1) = 99900 - 999 = 98901. This method is much faster and more elegant.
8. Why is division of a whole number by zero not defined, a concept relevant to Chapter 2?
Division by zero is undefined because it leads to a contradiction. Division is the inverse of multiplication. If we say 6 ÷ 0 = x, it would mean that x × 0 = 6. However, any number multiplied by zero is always zero, never 6. Since no number 'x' can satisfy this condition, the operation is considered undefined in the system of whole numbers.
