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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2 | Exploring Algebraic Identities 2026-27

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NCERT Class 9 Maths Chapter 4 Exercise 4.2 Solutions with Step-by-Step Answers

Class 9 Maths Chapter 4: Exploring Algebraic Identities Exercise 4.2 solutions help students understand the concepts covered in the exercise through clear, step-by-step explanations. 

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Based on the NCERT textbook, these solutions make it easier to approach each question, understand the solving method, and revise important concepts.


Students can refer to these solutions after attempting the questions on their own to check their answers and identify any mistakes. For complete chapter-wise explanations, students can also explore NCERT Solutions for Class 9 Maths to strengthen their preparation and improve problem-solving skills.

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Class 9 Maths Chapter 4 - Exploring Algebraic Identities Exercise 4.2 Solutions PDF Download

Think and Reflect

What if we replace b by – b in (a + b)2 = a2+ 2ab + b2?

Solution:

We get (a – b)2 = a2 – 2ab + b2, which is also an identity and can be used in ways similar to (a + b)2 = a2 + 2ab + b2


Exercise Set 4.2

Question 1.

Factor completely:


(i) 9x2 + 14xy + 16y2

Solution:

9x2 + 14xy + 16y2

= (3x)2 + 2 × (3x) × (4y) + (4y)2

= (3x + 4y)2 [∵ (a + b)2 = a2 + 2ab + b2]


(ii) 4s2 + 20st + 25t2

Solution:

4s2 + 20st + 25t2
= (2s)2 + 2 × (2s) × (5t) + (5t)2
= (2s + 5t)2 [∵ (a + b)2 = a2 + 2ab + b2]


(iii) 49x2 + 28xy + 4y2

Solution:

49x2 + 28xy + 4y2
= (7x)2 + 2 × (7x) × (2y) + (2y)2
= (7x + 2y)2 [∵ (a + b)2 = a2 + 2ab + b2]

(iv) 64p2 + 323 pq +49q2


Solution:

64p2 + 323 pq +49q2

= (8p)2 + 2 × (8p) × 23q+ 23q2

= (8p + 23q)2


(v) 3a2 + 4ab + 43 b2

Solution

3a² + 4ab + 4/3 b²
= 1/3(9a² + 12ab + 4b²)
= 1/3(3a + 2b)²

Answer: (3a + 2b)²/3

(vi) 95 s² + 6sv + 5v2


Solution

= 35s2+ 2 35s (√5v) + (√5v)2

(∵ 6 = 2 × 35 √5)

35 s + 5v2

[∵ (a + b)2 = a2 + 2ab + b2]


Question 2.

Find the values of the following using the identity (a – b)2 = a2 – 2ab + b2.

(i) (79)2

(ii) (193)2

(iii) (299)2

Solution:

(i) (79)2 = (80 – 1)2

= (80)2 + (1)2 – 2(80)(1)

[∵ (a – b)2 = a2 + b2 – 2ab]

= 6400 + 1 – 160

= 6401 – 160

= 6241


(ii) We have, (193)2 =(200 – 7)2

= (200)2 + (7)2 – 2(200) (7)

[∵ (a -b)2 = a2 + b2 – 2ab]

= 40000 + 49 – 2800

= 40049 – 2800

= 37249

(iii) We have (299)2 =(300 – 1)2

= (300)2 + (1)2 – 2(300) (1)

[∵ (a – b)2 = a2 + b2 – 2ab]

= 90000 + 1 – 600

= 90001 – 600

= 89401


How Vedantu’s Class 9 Maths Chapter 4 Exercise 4.2 Solutions Help Students?

Class 9 Maths Chapter 4 Exercise 4.2 solutions make it easier to understand the concepts and solve each question with a clear approach. 


Students can try the questions on their own first, then use the solutions to check their answers, understand difficult steps, and correct mistakes.

These NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2 are helpful for:


  • Understanding concepts: Follow the steps to see how each question is solved.

  • Clearing doubts: Revisit questions that seem difficult or confusing.

  • Improving accuracy: Compare your working with the explained solutions.

  • Revising quickly: Review important concepts from Class 9 Maths Chapter 4 Solutions Exercise 4.2 before tests and exams.

  • Building confidence: Practise similar questions using the methods explained in the NCERT Class 9 Maths Chapter 4 Exercise 4.2 Solutions.


Regular practice, combined with these solutions as a reference, can help students develop stronger problem-solving skills and mathematical understanding.


Access Exercise-wise NCERT Solutions for Chapter 4 Maths Class 9


CBSE Class 9 Maths Chapter 4 Exploring Algebraic Identities Study Materials

S. No

Important Links for Chapter 4 Exploring Algebraic Identities

1

Class 9 Exploring Algebraic Identities Important Questions

2

Class 9 Exploring Algebraic Identities Revision Notes

3

Class 9 Exploring Algebraic Identities NCERT Exemplar Solution

4

Class 9 Exploring Algebraic Identities RS Aggarwal Solutions


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FAQs on NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2 | Exploring Algebraic Identities 2026-27

1. What is the main concept students learn from Class 9 Maths Chapter 4 Exercise 4.2?

Exercise 4.2 focuses on applying algebraic identities to simplify and solve expressions. Students learn to recognise patterns in expressions and use the appropriate identity to solve efficiently.

2. Which identity is used for expanding (a-b)2 in Exercise 4.2

The identity used is:

(a – b)2 = a2 + b2 – 2ab

It helps students expand expressions involving the difference of two terms and applies to several algebraic problems.

3. How can students identify the correct identity from an algebraic expression?

Students should compare the given expression with the standard form of the identities. For example, a2 + b2 + 2ab matches (a+b)2, while a2 + b2 – 2ab matches (a-b)2. Recognising these patterns makes the calculations quicker and more accurate.

4. What is the best way to practise Class 9 Maths Chapter 4 Exercise 4.2?

Students should first revise the relevant identities and then attempt each question without looking at the answer. Once completed, they can refer to the Class 9 Maths Chapter 4 Exercise 4.2 solutions to understand the correct method and review any mistakes.

5. Are the NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2 useful for understanding the solving steps?

Yes. The NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.2 explain the work involved in each question, helping students understand how to select and apply an identity rather than relying only on the final answer.