
A college offers 7 courses in the morning and 5 in the evening. Find a possible number of choices with the student who wants to study one course in the morning and one in the evening.
A) $35$
B) $12$
C) $49$
D) $25$
Answer
129k+ views
Hint: First find the possible combination of selecting one course in the morning and selecting one course in the evening, then find the possible number of choices with the student who wants to study one course in the morning and one course in the evening by finding the product of both the possible selections of morning and evening.
Complete step-by-step answer:
It is given that the college offers 7 courses in the morning.
So, we can select 1 course in 7 ways.
Therefore, the selection of one course in the morning is given in the form of combination as:
$ = {}^7{C_1}$
Simplify the value of ${}^7{C_1}$getting the possible selection of one course in the morning.
${}^7{C_1} = \dfrac{{7!}}{{1! \times \left( {7 - 1} \right)!}}$
${}^7{C_1} = \dfrac{{7!}}{{6!}} = 7$
So, there are $7$ possible ways to select one course in the morning.
It is also given that the college offers 5 courses in the evening.
It means that we can select 1 course in 5 ways.
Therefore, the selection of one course in the evening is given in the form of combination as:
$ = {}^5{C_1}$
Simplify the value of ${}^5{C_1}$getting the possible selection of one course in the morning.
${}^5{C_1} = \dfrac{{5!}}{{1! \times \left( {5 - 1} \right)!}}$
${}^7{C_1} = \dfrac{{5!}}{{4!}} = 5$
So, there are $5$ possible ways to select one course in the evening.
Therefore, the selection one course in the morning and one in the evening is given as the product of both possible combinations.
$ = $ selection of one course in the morning $ \times $ selection of one course in the evening
$ = {}^7{C_1} \times {}^5{C_1}$
Substitute the value of both the combinations:
$ = 7 \times 5$
$ = 35$
Therefore there are 35 choices with the student to study one course in the morning and one in the evening.
Therefore the option $\left( A \right)$ is correct.
Note: It is given that there are 7 courses available in the morning and we have to choice of these course at one time then the possible number of choices is given as $^7{C_1}$ and similarly, there are five courses available in the evening then the possible number of choosing one course is given as $^5{C_1}$.
Complete step-by-step answer:
It is given that the college offers 7 courses in the morning.
So, we can select 1 course in 7 ways.
Therefore, the selection of one course in the morning is given in the form of combination as:
$ = {}^7{C_1}$
Simplify the value of ${}^7{C_1}$getting the possible selection of one course in the morning.
${}^7{C_1} = \dfrac{{7!}}{{1! \times \left( {7 - 1} \right)!}}$
${}^7{C_1} = \dfrac{{7!}}{{6!}} = 7$
So, there are $7$ possible ways to select one course in the morning.
It is also given that the college offers 5 courses in the evening.
It means that we can select 1 course in 5 ways.
Therefore, the selection of one course in the evening is given in the form of combination as:
$ = {}^5{C_1}$
Simplify the value of ${}^5{C_1}$getting the possible selection of one course in the morning.
${}^5{C_1} = \dfrac{{5!}}{{1! \times \left( {5 - 1} \right)!}}$
${}^7{C_1} = \dfrac{{5!}}{{4!}} = 5$
So, there are $5$ possible ways to select one course in the evening.
Therefore, the selection one course in the morning and one in the evening is given as the product of both possible combinations.
$ = $ selection of one course in the morning $ \times $ selection of one course in the evening
$ = {}^7{C_1} \times {}^5{C_1}$
Substitute the value of both the combinations:
$ = 7 \times 5$
$ = 35$
Therefore there are 35 choices with the student to study one course in the morning and one in the evening.
Therefore the option $\left( A \right)$ is correct.
Note: It is given that there are 7 courses available in the morning and we have to choice of these course at one time then the possible number of choices is given as $^7{C_1}$ and similarly, there are five courses available in the evening then the possible number of choosing one course is given as $^5{C_1}$.
Recently Updated Pages
The probability density function pleft x right cannot class 9 maths JEE_Main

The weight of a fruit bun Nisha bought was equal to class 9 maths JEE_Main

Ansgar is writing a novel He writes seven days a week class 9 maths JEE_Main

A college offers 7 courses in the morning and 5 in class 9 maths JEE_Main

Add the following algebraic expression using both horizontal class 9 maths JEE_Main

A box contains 5 times 102 paper clips Each paper clip class 9 maths JEE_Main

Trending doubts
JEE Main Marks Vs Percentile Vs Rank 2025: Calculate Percentile Using Marks

JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Mains 2025 Cutoff: Expected and Category-Wise Qualifying Marks for NITs, IIITs, and GFTIs

JEE Main Marks vs Rank 2025

JEE Main 2025 22 Jan Shift 1 Question Paper with Solutions

NIT Cutoff Percentile for 2025

Other Pages
NCERT Solutions for Class 9 Maths Chapter 9 Circles

NCERT Solutions for Class 9 Maths Chapter 11 Surface Area and Volume

NCERT Solutions for Class 9 Maths Chapter 11 Surface Areas And Volumes Ex 11.3

NCERT Solutions for Class 9 Maths Chapter 12 Statistics

NCERT Solutions for Class 9 Maths Chapter 10 Heron'S Formula

NCERT Solutions for Class 9 Maths In Hindi Chapter 1 Number System
