Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

CBSE Class 9 Maths Chapter 5 Introduction to Euclid’s Geometry – NCERT Solutions 2025–26

ffImage
banner

Get Free PDF for Class 9 Maths Chapter 5 Introduction to Euclid’s Geometry Exercise 5.1 Solutions

NCERT for Exercise 5.1 Class 9 Maths solutions Chapter 5 on Introduction to Euclid's Geometry by Vedantu, introduces valuable resources to solidify your understanding of fundamental concepts in Euclidean geometry. This exercise lays the groundwork for your journey through geometric shapes, their properties, and proofs. Recognizing points, lines, and planes in diagrams. Distinguishing between true and false statements related to geometric properties (e.g., only one line can pass through a single point).

toc-symbolTable of Content
toggle-arrow


This exercise focuses on foundational concepts in Euclidean geometry. With Vedantu's Class 9 Maths NCERT Solutions, you'll find step-by-step explanations of all the exercises in your textbook, ensuring that you understand the concepts thoroughly. 


Glance on NCERT Solutions Class 9 Maths Chapter 5 Exercise 5.1 | Vedantu

  • A Point is a location in space without any dimensions. A point indicates a location in space. It has no length, width, or thickness. Example: A, B, C.

  • Line: A breadthless length that extends infinitely in both directions.

  • A Line Segment is a part of a line with two endpoints.

  • Ray is a part of a line that starts at one point and extends infinitely in one direction.

  • Plane: A flat, two-dimensional surface that extends infinitely in all directions.

  • A straight line segment can be drawn joining any two points.

  • A terminated line can be extended indefinitely.

  • NCERT Solutions for Maths Exercise 5.1 Class 9 Chapter 5 contains 7 Questions with Solutions.

Competitive Exams after 12th Science
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow

Access NCERT Solutions for Maths Class 9 Chapter 5- Introduction to Euclid's Geometry Exercise 5.1

1. Which of the following statements are true and which are false?  give reasons for your answers.

(i) Only one line can pass through a single point.

Ans: False 

Because an endless number of lines can pass through a single point \[\text{ }\!\!'\!\!\text{  P  }\!\!'\!\!\text{ }\] below. There exists an infinite number of lines travelling through a single point \[\text{P}\], as shown in the diagram below.


an endless number of lines can pass through a single point P


(ii) There are an infinite number of lines which pass through two distinct points

Ans: False 

Only one line can pass through two points. There is only one single line that can travel between two separate points \[\text{P}\] and \[\text{Q}\], as shown in the following diagram.


one line can pass through two points


(iii) A terminated line can be produced indefinitely on both the sides

Ans: True  

  • On both the sides, a terminated line can be produced indefinitely.

  • Assume that \[\text{AB}\] is a terminated line. It can be seen that it can be produced indefinitely on both the sides.


AB is a terminated line. It can be seen that it can be produced indefinitely on both the sides.


(iv) If two circles are equal, then their radii are equal.

Ans: True 

If two circles are equal, then the centers and circumferences of the two circles are the same, the radii will be equal.

(v) In the following figure, if $\text{AM=PQ}$ and $\text{PQ=XY}$ ,then $\text{AB=XY}$

Ans: True


AM=PQ and PQ=XY ,then AB=XY


  • It is assumed that \[\text{AB}\] and \[\text{XY}\] are two terminated lines (Line segments) and that they are both equal to \[\text{PQ}\], a third line.

  • Euclid's first axiom stats that things which are equal to the same thing are equal to one another.

  • Therefore, the lines \[\text{AB=PQ}\] and \[\text{PQ=XY}\] , hence $AB=XY$ will be equal to each other.


2. Give a definition for each of the following terms. Are there other terms that need to be defined first ? what are they, and how might you define them ?

  1. Parallel lines

  2. Perpendicular lines

  3. Line segment

  4. Radius of  a circle

  5. Square

Ans:

The following terms are required for the desired definition:

  • Point:

  • A point can be approximated by a little dot formed with a sharp pencil on a sheet of paper.

  • A point does not have any dimensions; it simply has a position.

  • Line: 

  • A straight line made by folding a piece of paper, a straight string pulled at both ends, and the edge of a ruler are all examples of geometrical lines.

  • The basic concept about a line is that it should be straight and that it should extend in definitely in both the direction 

  • Plane:

  • Close examples of planes include the smooth surface of a wall or the smooth surface of a piece of paper.

  • Ray:

  • A ray\[\text{AB}\] is a segment of line l that has only one end point \[\text{A}\] and contains the point \[\text{B}\].

  • A point can be approximated by a little dot formed with a sharp pencil on a sheet of paper.

  • A point does not have any dimensions; it simply has a position.

  • A straight line made by folding a piece of paper, a straight string pulled at both ends, and the edge of a ruler are all examples of geometrical lines.

  • The fundamental principle of a line is that it should be straight and continue indefinitely in both directions.

  • Close examples of planes include the smooth surface of a wall or the smooth surface of a piece of paper.

  • A ray is a segment of line l that has only one end point and contains the point.

  • The union of two non-collinear rays with a common beginning point is called an angle .

  • Circle:

  • In a plane, a circle is the collection of all points whose distance from a fixed point is constant. 

  • The fixed point is called the centre of the circle

  • Quadrilateral:

  • A closed figure made of four lines segment is called quadrilateral.

(i) Parallel lines

Ans: 

  • Parallel lines are those in which the perpendicular distance between two lines is always the same.

  • To put it another way, parallel lines are lines that never cross one other.

  • To define parallel lines, we need to know about the point, the lines, and the distance between the lines and the intersection point.


Parallel lines


(ii) Perpendicular lines

Ans: 

  • If two lines intersect each other at \[\text{90 }\!\!{}^\circ\!\!\text{ }\] then these are called perpendicular lines.

  • Before defining perpendicular lines, we must first define the line and the angle.


Perpendicular lines


(iii) Line segment 

Ans: 

  • A line segment is a straight line drawn from one point to another point.

  • To define a line segment, we must first understand what a point and a line segment are.


Line segment


(iv) Radius of a circle

Ans: 

  • It is distance between the center of a circle to any point lying on the circle.

  • We must understand point and circle in order to define the radius of a circle.


Radius of a circle


(v) Square 

Ans: 

  • A square is a quadrilateral with all sides equal in length and all angles measuring \[\text{90 }\!\!{}^\circ\!\!\text{ }\].

  • To define square, we must know about quadrilateral, side, and angle.


Square


3. Consider the two 'postulates' given below:

  1. Given any two distinct points A and B, there exists a third point C, which is between A and B 

  2. There exists at least three points that are not on the same line.Do these postulates contain any undefined terms ? Are these postulates consists ? Do they follow from Euclid's postulates\[\text{?}\]Explain.

Ans: 

  • In the given postulates, there are several undefined terms.

  • Because the above postulates pertain to two different situations, they are consistent.

  • Furthermore, any assertion that contradicts a well-known axiom or postulate is impossible to infer.

  • The postulates of Euclid do not lead to these conclusions.

  • They follow from the axiom, "Given two distinct points, there is a unique line that passes through them"


4. If a point C lies between two points A and Bsuch that AC=BC then prove that \[\text{AC=}\frac{\text{1}}{\text{2}}\text{AB}\] Explain by drawing the figure.

Ans:

From the Figure,


AC=BC


Given that \[\text{AC=BC}\]

And point $C$ lies between two points \[\text{A}\] and \[\text{B}\]

Consider  c 

Adding \[\text{AC}\] on both sides we get

\[\text{AC+AC=BC+AC}\]

\[\Rightarrow \text{2AC=BC+AC}\]

Here we have \[\text{BC+AC=AB}\]

\[\Rightarrow \text{2AC=AB}\]

\[\Rightarrow \text{AC=}\frac{\text{1}}{\text{2}}\text{AB}\]


5.  In above question, point C is called a midpoint of line segment AB, prove that every line segment has one and only mid point

Ans:

From the Figure,


every line segment has one and only mid point


Easier solution

Now to we will prove line \[\text{AB}\] has only one midpoint such that 

Consider we have two midpoint \[\text{C}\] and \[\text{D}\] of line segment \[\text{AB}\]

Thus 

\[\text{AD=DB}\]         ......\[\left( \text{1} \right)\]

\[\text{AC = CB}\]          ...... \[\left( \text{2} \right)\]

Now subtracting equation \[\left( \text{1} \right)\text{-}\left( \text{2} \right)\] we get

\[\text{AD - AC = DB - CB}\]

Using figure we have 

\[\Rightarrow \text{CD = -DC}\]

\[\Rightarrow \text{2CD = 0}\]

\[\Rightarrow \text{CD = 0}\]

Therefore \[\text{C}\] and \[\text{D}\]  coincides.

Hence required is proved.

Lengthy solution 

\[\text{AC = CB}\]          ...... \[\left( \text{1} \right)\]

Now adding \[\text{AC}\] on both sides of equation \[\left( \text{1} \right)\]  we get

\[\text{AC+AC = AC+CB}\]        ...... \[\left( \text{2} \right)\]

From the figure we have 

\[\text{AC+CB=AB}\]

Now from equation \[\left( \text{2} \right)\] we have

\[\text{2AC = AB}\]        ...... \[\left( \text{3} \right)\]

Similarly we have 

\[\text{2AD = AB}\]        ...... \[\left( \text{4} \right)\]

Now equalizing equation \[\left( \text{3} \right)\] and \[\left( \text{4} \right)\] we get

\[\text{2AC = 2AD }\]

\[\Rightarrow \text{AC = AD }\]

Therefore \[\text{C}\] and \[\text{D}\]  coincides.

Hence required is proved.


6. In the following figure, if AC = BD, then prove that AB = CD


AB = CD


Ans:

We are asked to prove \[\text{AB = CD}\]

Let 

 \[\text{AB = CD}\]       ...... \[\left( \text{1} \right)\]

Now adding \[\text{BC}\] on both sides of equation \[\left( \text{1} \right)\]  we have 

\[\text{AB+BC = CD+BC}\]

From the figure we have 

\[\text{AC = BD}\]       ...... \[\left( \text{2} \right)\]

Now from the figure we have 

x\[\text{AC = AD - CD}\]        ...... \[\left( \text{3} \right)\]

\[\text{BD = AD - AB}\]        ...... \[\left( \text{4} \right)\]

Using above equation\[\left( \text{2} \right)\], \[\left( \text{3} \right)\] and  \[\left( \text{4} \right)\]  we have

\[\text{AD - CD = AD - AB}\]

\[\Rightarrow \text{- CD = - AB}\]

\[\Rightarrow \text{AB = CD}\]

Hence required is proved 


7. Why is Axiom in the list of Euclid's axioms, considered a 'universal truth'\[\text{?}\](Note that the question is not about the fifth postulate.)

Ans:

Axiom $\text{5}$  states that the whole is greater than the part.

This axiom is known as a universal truth because it holds true because it holds true in any field, and not just in the field of mathematics 

Let us take two cases one in the field of mathematics, and one other than that 

  • Case one

  • Let $\text{t}$ represent a whole quantity and only $\text{a,b,c}$ are parts of it.

  • $\text{t = a + b + c}$

  • Clearly $\text{t}$ will be greater than all its parts $\text{a,b,c}$.

  • As a result, it is correct to say that the whole is greater than the part

  • Case two

  • Let us consider the continent Asia.

  • Now consider the country of India, which is located in Asia.

  • Although India is a part of Asia, it is also true that Asia is larger than India.

  • As a result, we might conclude that the whole is greater than the part.

  • This holds true in any corner of the world, making it a universal truth.


Conclusion

NCERT Solutions for Class 9 Math Exercise 5.1 Introduction to Euclid's Geometry is essential for building a strong foundation in geometry. Exercise 5.1 explores the definitions put forward by Euclid to give the students a clear understanding of the concept. This exercise lays the foundation for understanding geometric principles through the work of Euclid, an ancient Greek mathematician known as the "father of geometry". To excel in this topic, students should practice solving different types of problems and understand the underlying principles. Regular practice and thorough understanding will help students tackle any question related to comparing quantities confidently.


CBSE Class 9 Maths Chapter 5 Other Study Materials


Chapter-Specific NCERT Solutions for Class 9 Maths

Given below are the chapter-wise NCERT Solutions for Class 9 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.



Important Study Materials for Class 9 Maths

WhatsApp Banner
Best Seller - Grade 11 - JEE
View More>
Previous
Next