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RS Aggarwal Class 10 Solutions - Triangles

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Triangles Solutions for RS Aggarwal Class 10 Chapter 4

Unable to formulate the answers to all the questions of RS Aggarwal textbook? Do not panic! We're here for you, bringing to you detailed solutions not only for the questions to Chapter 4 Triangles but all the Chapters and every single Question. The RS Aggarwal Class 10 Triangles Solutions are formulated by our mathematics experts at Vedantu who have been in the profession for years now. By following these solutions PDF, you shall receive the right guidance. Following these RS Aggarwal Solutions to Chapter 4 Triangles, you will learn how to approach the problems stepwise and solve them perfectly! You can download NCERT Solutions for Class 10 Maths and NCERT Solution for Class 10 Science to help you to revise the complete syllabus and score more marks in your Examinations. Every NCERT Solution is provided to make the study simple and interesting on Vedantu. Stuck at a question? Don't worry, Vedantu has got your back!

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RS Aggarwal Solutions for Class 10 Maths Chapter 4

We have provided step by step solutions for all Exercise questions given in the PDF of Class 10 RS Aggarwal Chapter 4 - Triangles. All the Exercise questions with solutions in Chapter 4 - Triangles are given below:

Exercise (Ex 4A) 4.1

Exercise (Ex 4B) 4.2

Exercise (Ex 4C) 4.3


Class 10 Chapter 4: Triangles

As kids, we see numerous shapes in our surroundings in day to day life. However, we never really cared to discover more about the properties of these shapes. Hence, we learn about all these properties as we progress through higher school. Triangles are one of the most common shapes we've been seeing in our surroundings. In our portions, we study Triangles in-depth and understand every little aspect of them.


Important Points RS Aggarwal Solutions Class 10 Chapter 4 Triangles

There are three different types of Triangles when segregated based on angles within a Triangle, 

  • Acute Triangle: An acute Triangle is a Triangle where each of the angles within a Triangle is less than 90 degrees, implies that the measure of each angle within the Triangle is less than 90 degrees


  • Obtuse Triangle: An obtuse Triangle is a Triangle wherein the measure of at least one angle of the Triangle exceeds 90 degrees


  • Right Triangle: A right-angled Triangle is a Triangle in which at least one of the angles of the Triangle is equal to 90 degrees.


Based on the lengths of the sides of a Triangle, there are three kinds as well:

  • An isosceles Triangle is a special variety of Triangle in which two sides of the Triangle are equal and two angles are equal as well.


  • A right Isosceles Triangle is a Triangle in which two angles of the Triangle are equal to 45 degrees and one angle is equal to 90 degrees.


  • An equilateral Triangle is a Triangle in which each of the sides is equal and all the angles are equal to 60 degrees.


Pythagoras Theorem: The Pythagoras theorem is one of the most important theorems in right-angled Triangles. It is a very useful theorem to approach problems of Class 10 Chapter 4 Triangles. The theorem states that the square of the length of the longest side, that is the hypotenuse, will be equal to the sum of squares of the lengths of the other two sides.


Median of a Triangle: The medians of a Triangle are the line segments drawn from one vertex to the midpoint of the opposite side. 


Centroid: The point of intersection of all the medians is called the centroid of the Triangle. Interestingly the centroid of the Triangle also divides each median in a ratio of 2:1.


Altitude: Altitudes of a Triangle are the line segments drawn from the vertices of the Triangles to the side opposite to the Triangle such that the line segment makes a right angle with the side it intersects.


Orthocentre: The orthocenter is the point of intersection of all the altitudes within a Triangle.


Angular Bisectors: The line segment bisecting each angle of a Triangle and meeting the opposite side is called an angular bisector of the Triangle.


Incentre: The incentre of a Triangle is the point of intersection of all the angular bisectors of the Triangle.


  • Interestingly, in an equilateral Triangle, the median, the altitude, and the angular bisectors are the same, and hence all the points, incentre, orthocentre and centroid are concurrent to each other.

  • The sum of all the internal angles of a Triangle is always equal to 180 degrees.

  • The sum of lengths of two sides is always greater than the length of the third side of the Triangle.


Heron's Formula: A formula to find the area of any Triangle by just knowing the length of each side of a Triangle.

s(semiperimeter):(a+b+c)/2

Where a,b,c are the lengths of sides of the Triangle respectively.

Area = √s(s–a)(s–b)(s–c)

Area of Triangle: ½*b*h where b is the base of the Triangle and h is the height or the altitude of the Triangle.

Area of an Isosceles Triangle:

A = (1/4) × b × √(4a2 – b2)

Where b is the length of the unequal sides of the Triangle and a is the length of sides that are equal.

Area of an Equilateral Triangle

Area of Equilateral Triangle = √3a2/4

Where a is the length of a side of the Triangle


Preparation Tips

While preparing for the topic Triangles, you must ensure to be thorough with all the important theorems and formulae. While solving the problems you need to implement the right property at the right place. This will make your problem solving much simpler. Following Vedantu solutions to RS Aggarwal will make your problem solving more systematic and simple!


Importance of learning CBSE Class 10 Maths Chapter 4- Triangles

  • Triangles is an important Chapter as we learn about its different properties which will come in handy in the future Classes

  • Triangles form the very basis of some of the important theorems

  • Trigonometry becomes easier to understand

  • Complex calculations become much easier if one properly learns about Triangles

  • Areas such as Engineering, Astronomy,  Physics and Navigation become smoother to understand

  • Unknown quantities in geometry can be easily determined

  • Concepts of Euclid’s Geometry also becomes easier 

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FAQs on RS Aggarwal Class 10 Solutions - Triangles

1. What is the correct method for solving problems based on the Basic Proportionality Theorem (BPT) in RS Aggarwal Class 10, Chapter 4?

The solutions for RS Aggarwal Class 10 Chapter 4 demonstrate the correct step-by-step method for applying the Basic Proportionality Theorem (BPT). The key steps include:

  • Clearly identifying the triangle and the line parallel to one of its sides.
  • Stating the theorem as the reason for setting up the ratio of sides.
  • Substituting the known values into the proportion, such as AD/DB = AE/EC.
  • Solving the resulting equation to find the unknown side length.

Following this structured approach, as shown in the solutions, ensures you do not miss any steps and helps in scoring full marks.

2. How can I find the solutions for specific exercises like Exercise 4A or 4B in RS Aggarwal Class 10 Triangles?

Vedantu provides comprehensive, exercise-wise solutions for Chapter 4, Triangles, from the RS Aggarwal textbook. You can navigate through the chapter page to find detailed, step-by-step answers for every question in each exercise, such as Exercise 4A, 4B, and so on. This makes it easy to check your work or understand the method for a specific problem you are stuck on.

3. When solving a similarity problem, why is stating the criterion (e.g., AA, SAS, SSS) so important in the RS Aggarwal solutions?

Stating the similarity criterion (like AA, SAS, or SSS) is a crucial step that carries marks in an exam. The RS Aggarwal solutions emphasise this because:

  • It acts as the logical foundation for your proof, showing the examiner you understand why the triangles are similar.
  • It justifies the subsequent step of writing the corresponding sides in proportion.
  • Skipping this step can lead to a loss of marks, as it demonstrates an incomplete understanding of the geometric proof process as per the CBSE pattern.

4. How do the RS Aggarwal solutions help with questions on different types of triangles, like isosceles or right-angled triangles?

The RS Aggarwal solutions for Chapter 4 cover a wide variety of problems involving special triangles. For example, when solving a problem on an isosceles triangle, the solutions will guide you on how to correctly apply properties like equal sides and equal opposite angles along with similarity or Pythagoras theorems. For right-angled triangles, the solutions clearly demonstrate the application of the Pythagoras theorem and trigonometric ratios where applicable.

5. What are some common mistakes to avoid when applying the theorem on 'Areas of Similar Triangles' as per the solutions?

The RS Aggarwal solutions help clarify common pitfalls. When using the theorem on Areas of Similar Triangles, students often make these mistakes:

  • Forgetting to square the ratio of the corresponding sides. The theorem states that the ratio of areas is equal to the square of the ratio of sides.
  • Incorrectly matching corresponding sides, altitudes, or medians.
  • Applying the theorem to triangles that are not proven to be similar first.

The solutions guide you to first prove similarity and then correctly apply the area theorem.

6. What is the typical structure for solving a proof-based question in the Triangles chapter, according to RS Aggarwal solutions?

The RS Aggarwal solutions follow the standard CBSE format for proofs, which is essential for scoring well. The structure includes:

  • Given: Stating all the information provided in the question.
  • To Prove: Clearly mentioning what needs to be proven.
  • Construction: Describing any additional lines or points needed for the proof (if any).
  • Proof: A logical, step-by-step deduction with a valid reason (e.g., theorem, property, axiom) for each step.

This methodical approach helps in building a clear and convincing argument.

7. I'm confused between the Basic Proportionality Theorem (BPT) and the Mid-point Theorem. How do the solutions help differentiate their application?

The RS Aggarwal solutions clarify this common confusion. The Basic Proportionality Theorem (BPT) applies when a line is parallel to any one side of a triangle and intersects the other two sides at distinct points, establishing a ratio between the divided segments. The Mid-point Theorem (from Class 9) is a special case of BPT where the line joins the mid-points of two sides. The solutions demonstrate that while BPT gives a general ratio, the Mid-point Theorem specifically proves the line is parallel to the third side and is half its length.

8. How should I use the RS Aggarwal solutions for Class 10 Triangles for self-study and exam preparation?

For effective preparation for the 2025-26 exams using the RS Aggarwal solutions for Triangles, follow this method:

  • First, attempt to solve the exercise problems on your own.
  • If you get stuck or want to verify your answer, refer to the step-by-step solution provided.
  • Pay close attention to the theorems and properties cited in each step of the solution.
  • Do not just copy the answer; focus on understanding the 'how' and 'why' of the method to master the concepts for the board exams.