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RS Aggarwal Class 10 Solutions Chapter 17 Perimeter and Areas of Plane Figures

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Introduction to Perimeter and Areas of Plane Figures Solutions Class 10 Chapter 17 from Vedantu

Mathematics consists of many concepts to clear them and perform well in the tests refer to best-guiding books or online websites. Mathematics class 10th chapter 17 is about volume and surface area. Under this chapter, students will learn about calculating the surface area of the solid and its derivations. Also the conversion from one shape to another and finding its area and volume. Students should download the rs Aggarwal solutions class 10 chapter 17 from Vedantu’s website or app and study for exams to prepare for the test. The complete chapter talks about the volume and surface of the cone, cylinder, cube, cuboid, and much more.


Register Online for Class 10 Science tuition on Vedantu.com to score more marks in the CBSE board examination. Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. Maths Students who are looking for better solutions can download Class 10 Maths NCERT Solutions to help you to revise the complete syllabus and score more marks in your examinations.


We have provided step by step solutions for all exercise questions given in the pdf of Class 10 RS Aggarwal Chapter 17 - Perimeter and Areas of Plane Figures. All the Exercise questions with solutions in Chapter 17 - Perimeter and Areas of Plane Figures are given below:


At Vedantu, students can also get Class 10 Maths Revision Notes, Formula and Important Questions and also students can refer to the complete Syllabus for Class 10 Maths, Sample Paper, and Previous Year Question Paper to prepare for their board exams more effectively.

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RS Aggarwal Solutions for Class 10 Maths Chapter 17

RS Aggarwal Chapter 17 Solutions: A Complete Guide for Students to Learn Volumes and Surface Areas


Students who are facing some issues in understanding the topic and want their concepts to be clear should download RS Aggarwal solutions class 10 chapter 17. By downloading the class 10 maths RS Aggarwal ch 17 volume and surface area all your concepts will be extremely clear and you can easily answer all the questions related to this topic.


Here we have provided the solution for the perimeter and area of plane figures class 10 RS Aggarwal. Students can download the pdf from Vedantu’s website and start preparing for the exams. Students who are preparing for the exam can download RS Aggarwal class 10 chapter 17 solutions.


Chapter 17 is based on the volume and surface area of different solids like cubes, cylinders, spheres, etc. Under this chapter, students can learn about interesting topics and understand the concepts easily.


Students can download Perimeter and area of plane figures class 10 RS Aggarwal solutions. You can know how to solve every type of question so that they can know how to solve each type of question easily. The subject experts at Vedantu have curated solutions for premier and area of plane figures class 10 to understand the concepts of chapter 17. 


Class 10 Maths RS Aggarwal Solutions Chapter 17  has a detailed explanation of the following problems. Chapter 17 has the following exercises. 

1. Exercise 17 A: Exercise 17 A of chapter 17 contains the following concepts:

  • Volume and Surface Area of Cuboid

  • Volume and Surface Area of Cube

2. Exercise 17 B: Under this exercise students will learn about the conversion of solids from one shape to another and other mixed problems.

3. Exercise 17 C: Under this exercise will teach students about

  • Volume and surface area of a cone

  • Derivation of volume and surface area of a cone

4. Exercise 17 D: RS Aggarwal solutions class 10 ch 17 exercises 17.D. Under this exercise, students will learn about

  • Volume and Surface Area of Sphere and Hemisphere

  • Volume and Surface Area of Combination of Solids.


Important Shapes in Chapter 17 Fraction 

  • Circle – If r is the circle's radius, and d is its diameter, then:


 Area = πr²


Circle Circumference = 2πr = πd


With the formula = Area of the outer circle - Area of the inner circle, you can find the ring's area.

  • Parallelogram – If b is the base and h is the height of a parallelogram, then the height of the parallelogram 


Area = b * h


Perimeter value = 2*(b + h)


  • Rhombus – If an is the side of a rhombus and d1 and d2 are the diagonals of a rhombus, then 


Area = 1⁄2 *d1*d2 


Perimeters = 4*a


In online learning, you will get the solutions for the perimeter and area of the aircraft in the class 10 RS Aggarwal, which can be downloaded from our site in pdf format to begin the preparation of examinations. You can download chapter 17 solutions 24/7 from the Vedantu online learning portal for all classes. 


Class 10 Maths Chapter 17: Preparation Tips

Chapter 17 is one of the important topics that is asked in the class 10 examinations. All the students are advised to study this chapter carefully to score well in the exams. Make sure to follow the following tips to ace the topic and score well in the exams.

  • Practice every exercise of the chapter

  • Solve all the examples in RS Aggarwal

  • Practice and solve RS Aggarwal Chapter 17 solutions to get your concepts clear

  • Note Down and understand all the formulas

  • Understand the derivations

  • Concentrate on basics


Conclusion

To get good marks in the examination you must consider RS Aggrawal solutions provided on the site. All types of guidelines related to the chapters are available. You find the sample papers and videos for a better understanding of each chapter.

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FAQs on RS Aggarwal Class 10 Solutions Chapter 17 Perimeter and Areas of Plane Figures

1. How should I approach solving problems from RS Aggarwal Class 10 Chapter 17, Perimeter and Areas of Plane Figures?

To effectively solve problems in this chapter, follow a structured approach. First, carefully read the question to identify the shapes involved (e.g., circle, square, triangle) and what you need to calculate (perimeter, area, shaded region). Next, list all the given values like radius, side length, or angle. Then, select the correct formula for each part of the problem. Execute the calculations step-by-step, ensuring you use the value of π (pi) as specified in the question (22/7 or 3.14). Finally, double-check your units (cm, m, cm², m²) in the final answer.

2. What is the step-by-step method to find the area of a shaded region combining a square and a circle?

Finding the area of a combined shaded region involves a subtraction method. Follow these steps:

  • Step 1: Identify the larger, encompassing shape and the smaller shape(s) removed from it. For instance, a circle inscribed in a square.

  • Step 2: Calculate the total area of the larger shape. For a square, use the formula Area = side².

  • Step 3: Calculate the area of the smaller, unshaded shape(s). For a circle, use Area = πr².

  • Step 4: Subtract the area of the smaller shape from the area of the larger shape. The result, Area of Shaded Region = Area (Larger Shape) - Area (Smaller Shape), is your answer.

3. What are the key concepts covered in RS Aggarwal Class 10 Chapter 17 for the 2025-26 session?

As per the latest syllabus, RS Aggarwal Chapter 17 primarily focuses on mensuration of plane figures. The key concepts include:

  • Calculating the circumference (perimeter) and area of a circle.

  • Finding the area of a sector of a circle using the angle (θ).

  • Determining the area of a segment of a circle (Area of Sector - Area of Triangle).

  • Solving problems on finding the areas of combined plane figures, which involve combinations of circles, squares, rectangles, and triangles.

4. How do you calculate the area of a major sector of a circle as per the methods in RS Aggarwal?

To calculate the area of a major sector, you first need the angle of the minor sector (θ). The angle of the major sector will be (360° - θ). The step-by-step method is:

  • Method 1: Use the formula for the area of a sector directly with the major angle: Area = ((360 - θ) / 360) * πr².

  • Method 2: Calculate the area of the entire circle (πr²) and subtract the area of the minor sector. Area of Major Sector = Area of Circle - Area of Minor Sector.

Both methods will yield the correct answer; choose the one that seems more direct based on the given information.

5. Why is it important to use the specific value of π (e.g., 22/7 or 3.14) mentioned in an RS Aggarwal problem?

Using the specified value of π is crucial for accuracy and scoring full marks. The choice is often intentional to simplify calculations. For example, if the radius or diameter is a multiple of 7, using π = 22/7 allows for easy cancellation and results in a precise integer or fractional answer. Using 3.14 in such cases can introduce decimal errors. Adhering to the value given in the question ensures your final answer matches the one expected by the examiner, which is critical in the CBSE evaluation pattern.

6. How does the concept of a 'segment' of a circle differ from a 'sector', and why does it change the calculation method?

The difference is fundamental to solving problems in this chapter. A sector is a pie-shaped region enclosed by two radii and the connecting arc. Its area is a fraction of the circle's total area. In contrast, a segment is the region enclosed by a chord and the connecting arc. This distinction completely changes the calculation. To find the area of a segment, you must first calculate the area of the corresponding sector and then subtract the area of the isosceles triangle formed by the two radii and the chord. This makes the segment calculation a multi-step process (Area of Segment = Area of Sector - Area of Triangle).

7. What is a common mistake to avoid when calculating the perimeter of a combined plane figure in Chapter 17?

A very common mistake is to simply add the perimeters of all the individual shapes. This is incorrect. The perimeter is the length of the outer boundary of the final, combined shape only. When shapes are joined, their common sides are no longer part of the outer boundary. For example, to find the perimeter of a shape made by a semicircle attached to a square, you must add the lengths of the three sides of the square and the length of the curved arc of the semicircle, not the full perimeter of the square and the full perimeter of the semicircle.

8. What is the correct formula to find the length of an arc of a sector with angle θ?

The length of an arc is a fraction of the total circumference of the circle. The correct formula, as used in RS Aggarwal solutions for problems related to perimeter, is: Length of Arc = (θ / 360°) * 2πr, where θ is the angle of the sector in degrees and r is the radius of the circle. This formula is essential for finding the perimeter of sectors or combined figures involving arcs.