RD Sharma Class 12 Solutions Chapter 30 - Linear programming (Ex 30.2) Exercise 30.2 - Free PDF
FAQs on RD Sharma Class 12 Solutions Chapter 30 - Linear programming (Ex 30.2) Exercise 30.2
1. What is the primary method used to solve the problems in RD Sharma Class 12 Solutions for Chapter 30, Exercise 30.2?
The solutions for Exercise 30.2 primarily use the Graphical Method for solving Linear Programming Problems (LPPs). This method involves visually representing the problem's constraints as straight lines on a graph to identify a feasible region and then finding the optimal (maximum or minimum) value of the objective function within that region.
2. What are the essential steps to follow when using the graphical method for questions in Exercise 30.2?
To solve any LPP from Exercise 30.2 using the graphical method, you should follow these steps as per the CBSE curriculum:
- Step 1: Formulate the LPP by defining the objective function (Z = ax + by) and all the constraints (linear inequalities).
- Step 2: Plot each constraint as an equation on a graph (e.g., plot x + 2y = 10 for the constraint x + 2y ≤ 10).
- Step 3: Identify the feasible region, which is the common area shared by all constraints, including the non-negative constraints (x ≥ 0, y ≥ 0).
- Step 4: Determine the coordinates of the vertices (corner points) of this feasible region.
- Step 5: Substitute these corner point coordinates into the objective function to find the optimal value. The largest value is the maximum and the smallest is the minimum.
3. How do I identify the feasible region on the graph when solving problems from Exercise 30.2?
To identify the feasible region, first plot each constraint as a line. For each constraint (e.g., ax + by ≤ c), test a point (usually the origin, (0,0), if the line doesn't pass through it) to see if it satisfies the inequality. If it does, the region containing that point is the solution for that constraint. The feasible region is the overlapping area that satisfies all the constraints simultaneously.
4. Why is the 'Corner Point Method' crucial for finding the optimal solution in these exercises?
The Corner Point Method is crucial because of a fundamental theorem in linear programming. It states that if an optimal solution (maximum or minimum) for an LPP exists, it must occur at one of the vertices (or corner points) of the feasible region. This allows us to avoid checking infinite points within the region and instead only test a finite number of corner points, which simplifies the process of finding the best possible outcome significantly.
5. What is the difference between a bounded and an unbounded feasible region in the context of problems in Exercise 30.2?
A bounded feasible region is one that is completely enclosed by the constraint lines, forming a closed polygon. In this case, both a maximum and a minimum value for the objective function will exist at the corner points. An unbounded feasible region is one that extends infinitely in at least one direction. For unbounded regions, an optimal solution may or may not exist. A minimum might exist, but a maximum might not (or vice-versa), depending on the objective function.
6. How can I determine if a Linear Programming Problem from Exercise 30.2 has multiple optimal solutions?
A Linear Programming Problem can have multiple optimal solutions if the objective function line is parallel to one of the constraint lines that forms an edge of the feasible region. When you test the corner points, you will find that two adjacent vertices give the same optimal (max or min) value. In this case, every point on the line segment connecting these two vertices is also an optimal solution.
7. What does it mean if there is no feasible region after plotting the constraints for a problem?
If there is no overlapping area that satisfies all the given constraints simultaneously, it means there is no feasible region. This indicates that the Linear Programming Problem has no solution. The constraints are contradictory, and it's impossible to find any point (x, y) that meets all the required conditions at the same time.

















