Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

RD Sharma Class 12 Solutions Chapter 21 - Areas of Bounded Regions (Ex 21.4) Exercise 21.4

ffImage
banner

Preparation with RD Sharma Class 12 Solutions Chapter 21

Free PDF Download of RD Sharma Class 12 Solutions Chapter 21 - Areas of Bounded Regions Exercise 21.4 solved by Expert Mathematics Teachers on Vedantu.com. All Chapter 21 - Areas of Bounded Regions Ex 21.4 Questions with Solutions for RD Sharma Class 12 Maths to help you revise the complete Syllabus and Score More marks. Register for online coaching for IIT JEE (Mains & Advanced) and other Engineering entrance exams.


Competitive Exams after 12th Science
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow

RD Sharma Class 12 Solutions Chapter 21 - Areas of Bounded Regions (Ex 21.4) Exercise 21.4

Introduction to Chapter

‘Areas of Bounded Region’ is Chapter 21 of RD Sharma Class 12 Maths which helps the students to learn about how to calculate the area of bounded regions. The very first step while calculating the area is identifying the region whose area is to be determined. Students also learn about the algorithm to find the area using horizontal and vertical stripes.

Students will talk about the application of integration in calculating the area of bounded regions. Integration is one of the most important parts of Maths. Therefore before beginning with the chapter ‘Areas of Bounded Region’, the integration concepts must be very clear to the student.


Sections of RD Sharma Maths Class 12 Chapter 21- Areas of Bounded Region

1. The area as a definite integral

 The area under, over, or below the curves can be found out using definite integrals. 

If a function is 

  • Positive- the area between the function and the s-axis is equal to the definite integral.

  • The negative- area will be -1 times the definite integral.

The area between two positive functions = Definite integral or higher function - Lower function

2. Area using Horizontal Stripes

Area bounded by x= g(y) and y-axis between line y=a, y=b can be given as

A = \[\int_{a}^{b} |x|.dy = \int_{a}^{b} |g(y)|.dy \]

3. Area using vertical stripes

Area bounded, if f(x) is continuous and non-negative function of x on the closed interval [a,b], between the x-axis and the vertical lines x=a and x=b can be given as

A = \[\int_{a}^{b} f(x)dx \]

4. Area between two curves

The formula for finding the area under two curves by using vertical elements

Area =  \[\int_{a}^{b} |y_{2} - y_{1}|dx\] 

Here \[y_{1}\] and \[y_{2}\] are functions of x

The formula for finding the area under the two curves by using horizontal elements

Area =  \[\int_{c}^{d} |x_{2} - x_{1}|dy\] 

Here \[x_{1}\] and \[x_{2}\] are functions of y


Exercise in RD Sharma Class 12 Maths Chapter 21- Areas of a Bounded Region

Exercise

Description

21.1

Questions regarding how to calculate the area bounded by the given curve, x-axis.

21.2

Questions regarding the calculation of area using horizontal stripes.

21.3

Questions regarding areas lying between two curves using vertical strips.

21.4

Questions regarding area lying between two curves using horizontal strips. 

WhatsApp Banner
Best Seller - Grade 12 - JEE
View More>
Previous
Next

FAQs on RD Sharma Class 12 Solutions Chapter 21 - Areas of Bounded Regions (Ex 21.4) Exercise 21.4

1. What is the first and most crucial step when solving problems from RD Sharma Class 12 Solutions for Exercise 21.4?

The first and most crucial step is to draw a rough sketch of the curves provided in the question. Visualising the bounded region helps in correctly identifying the points of intersection, the limits of integration, and which function represents the upper boundary versus the lower boundary.

2. How do you set up the definite integral for finding the area between a curve y = f(x) and the x-axis from x=a to x=b?

To find the area between a curve y = f(x) and the x-axis from x=a to x=b, you set up the definite integral as Area = ∫ₐᵇ y dx or Area = ∫ₐᵇ f(x) dx. It's important to take the absolute value of the result if the region lies below the x-axis, as area must be a positive quantity.

3. What is the correct method for finding the area bounded by two curves, like a parabola and a line, as shown in Chapter 21?

The step-by-step method to find the area between two curves, y = f(x) and y = g(x), is as follows:

  • Find intersection points: Solve the two equations simultaneously to find the x-coordinates of their intersection, say 'a' and 'b'. These will be your limits of integration.
  • Identify upper and lower curves: In the interval [a, b], determine which function has greater y-values (the upper curve) and which has lesser y-values (the lower curve).
  • Set up the integral: The area is calculated using the formula: Area = ∫ₐᵇ [f(x) - g(x)] dx, where f(x) is the upper curve and g(x) is the lower curve.

4. Why is sketching the graph so essential before calculating the area of a bounded region?

Sketching the graph is essential because it prevents common errors and clarifies the problem. A sketch helps you to:

  • Correctly identify the exact enclosed region whose area needs to be calculated.
  • Visually confirm the points of intersection, which define the limits of integration.
  • Clearly distinguish the upper boundary curve from the lower boundary curve over the entire interval, which is critical for setting up the integral `∫(upper curve - lower curve)dx` accurately.
Without a sketch, it is easy to misinterpret the boundaries and limits.

5. How do you decide whether to integrate with respect to x (using vertical strips) or with respect to y (using horizontal strips)?

The choice depends on which method simplifies the calculation:

  • Use vertical strips (dx) when the region's upper and lower boundaries are consistently defined by functions of x (i.e., y = f(x) and y = g(x)). This is the most common approach.
  • Use horizontal strips (dy) when the region's right and left boundaries are more easily defined by functions of y (i.e., x = f(y) and x = g(y)). This is particularly useful for parabolas that open sideways, like y² = 4ax.

6. What is a common mistake students make when finding the area between two intersecting curves using the solutions for Exercise 21.4?

A very common mistake is incorrectly identifying the upper and lower curves. If the curves intersect and switch positions (i.e., the upper curve becomes the lower curve), the integral must be split into multiple parts at the point of intersection. Forgetting to do this and using a single integral `∫(f(x) - g(x))dx` over the entire range will lead to an incorrect answer.

7. Do the solutions for RD Sharma Exercise 21.4 cover finding the area of regions bounded by standard shapes like circles and ellipses?

Yes, the solutions for RD Sharma Class 12 Chapter 21, including Exercise 21.4, provide solved examples for finding the area of regions bounded by standard curves. This includes problems involving circles, parabolas, and ellipses, often in combination with lines, which aligns with the CBSE 2025-26 syllabus for Applications of Integrals.