
The number of significant figures in \[6.02 \times {10^{23}}\] is :
A. 23
B. 3
C. 4
D. 26
Answer
146.7k+ views
Hint: Significant figures in any expression or numeral or decimal are just the number of significant digits from 0-9. When a number is expressed in scientific notation, the expressions in which all the zeros to the right-hand side of the decimal point are significant.
Complete Step by Step Solution:
Whether a number is significant or not is governed by some rules. One of the rules states that non-zero numbers are significant.
If we consider the number 55.78, there is a count of four significant figures.
Another rule states that if zeroes are there between any no.of significant numbers then the zeroes have significance.
So, for the given question, 6.02 has a total of four significant digits as the zero between six and two is also considered a significant number.
When numbers are expressed in scientific notation, these expressions of all the zeros to the right-hand side of the decimal point are significant.
For instance, \[6.5 \times {10^3}\] has two significant figures.
\[6.50 \times {10^3}\] has three significant figures.
Lastly, \[6.500 \times {10^3}\] has four significant figures.
So, the no.of significant numbers in \[6.02 \times {10^{23}}\] is 3.
So, option B is correct.
Note: Exact numbers have or demonstrate an infinite number of significant figures. For instance, in 60 pencils or 100 copies, there are unlimited significant figures present as these are exact numbers and can be indicated or represented by documenting an unlimited no.of zeros after positioning a decimal i.e. 50 = 50.000000 or 100 = 100.000000.
Complete Step by Step Solution:
Whether a number is significant or not is governed by some rules. One of the rules states that non-zero numbers are significant.
If we consider the number 55.78, there is a count of four significant figures.
Another rule states that if zeroes are there between any no.of significant numbers then the zeroes have significance.
So, for the given question, 6.02 has a total of four significant digits as the zero between six and two is also considered a significant number.
When numbers are expressed in scientific notation, these expressions of all the zeros to the right-hand side of the decimal point are significant.
For instance, \[6.5 \times {10^3}\] has two significant figures.
\[6.50 \times {10^3}\] has three significant figures.
Lastly, \[6.500 \times {10^3}\] has four significant figures.
So, the no.of significant numbers in \[6.02 \times {10^{23}}\] is 3.
So, option B is correct.
Note: Exact numbers have or demonstrate an infinite number of significant figures. For instance, in 60 pencils or 100 copies, there are unlimited significant figures present as these are exact numbers and can be indicated or represented by documenting an unlimited no.of zeros after positioning a decimal i.e. 50 = 50.000000 or 100 = 100.000000.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Concept of CP and CV of Gas - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
