

How to Derive the Formula for the Time Period of SHM with Examples
The time period of SHM describes how long it takes for an oscillating system to complete a single, full vibration or cycle. For JEE Main Physics, mastering the formula, meaning, and variations of the time period is critical for tackling questions on oscillations, springs, pendulums, and advanced mechanics. Many real-world physics setups, like a mass on a spring or a simple pendulum in a lab, follow simple harmonic motion (SHM) with uniform time periods under ideal conditions.
For instance, a block attached to a spring on frictionless ice or a bob swinging as a simple pendulum exhibits SHM, each with a specific time period determined by system parameters. The concept is widely tested in questions requiring quick formula recognition, derivation skills, or the ability to predict how mass, spring constant, or external forces affect the oscillation period.
Time Period of SHM: Formula, Symbols, and Units
The time period T of an object in simple harmonic motion is defined as the time for one complete oscillation from its starting position, back to the same spot, moving in the same direction. In SI units, T is measured in seconds (s).
| Physical Quantity | Symbol | SI Unit |
|---|---|---|
| Time Period | T | s |
| Angular Frequency | ω | rad/s |
| Frequency | f | Hz |
The key formula, essential for JEE, is:
T = \(\frac{2\pi}{\omega}\)
where ω (omega) is the angular frequency.
Derivation: Time Period of SHM for Key Systems
For a mass-spring system, the restoring force is F = -kx (by Hooke’s Law), giving the equation of motion: m\(\ddot{x}\) = -kx.
Dividing by m and rearranging: \(\ddot{x}\) + (k/m)x = 0, which matches the standard SHM equation \(\ddot{x}\) + \(\omega^2\)x = 0. Thus, \(\omega = \sqrt{\frac{k}{m}}\) and the time period becomes:
T = 2\(\pi\) \(\sqrt{\frac{m}{k}}\)
For a simple pendulum (length L, mass m), the restoring torque leads to \(\omega = \sqrt{\frac{g}{L}}\) so time period is
T = 2\(\pi\) \(\sqrt{\frac{L}{g}}\). These standard results are directly applied in JEE Main.
Relationship: Time Period, Frequency, and Angular Frequency in SHM
A major SHM doubt is the relation between period, frequency, and angular frequency. These are linked as follows:
| Quantity | Formula | Unit |
|---|---|---|
| Time period T | T = 2\(\pi\)/\(\omega\) | s |
| Frequency f | f = 1/T | Hz |
| Angular frequency ω | ω = 2\(\pi\)f | rad/s |
Remember: While frequency is cycles per second, angular frequency uses radians per second, but all three quantities are interconnected in JEE Main problems. Recognising the form T = 2\(\pi\)/\(\omega\) allows quick conversions and checks for all oscillatory systems.
What Determines the Time Period of SHM?
The time period of SHM depends entirely on system parameters, not on amplitude (for ideal systems). For JEE Main, commonly tested factors include:
- For springs: Mass (m) and spring constant (k)
- For pendulums: Length (L) and acceleration due to gravity (g)
- In electric field systems: charge (q) and field strength (E)
- For a tunnel through the Earth: Earth’s radius (R) and gravity variation
- Changing gravity (e.g., on Moon) alters T for pendulums but not springs
Notice that increasing amplitude does not affect the time period for standard SHM systems, unless non-linear effects or large angles (for pendulums) come into play—this is a common exam trap.
Worked Example: Calculating the Time Period of SHM
Example: A 0.5 kg mass is attached to a spring with k = 200 N/m. Find the time period of oscillation.
- Given: m = 0.5 kg, k = 200 N/m
- Use T = 2\(\pi\)√(m/k)
- T = 2\(\pi\)×√(0.5/200) = 2\(\pi\)×√(0.0025) = 2\(\pi\)×0.05
- T ≈ 0.314 s
In this calculation, only mass and spring constant matter; no effect from amplitude or direction. This approach is standard for most JEE Main time period questions involving mechanical SHM.
Visual Interpretation: SHM Graphs and Reading the Time Period
Displacement-time graphs for SHM are sinusoidal. The time period T is the interval for the function to repeat its value and direction. Measure the distance between two adjacent peaks or troughs to determine T from a graph.
Pay attention to units on axes. The graphical method is especially useful in JEE for matching equations to experimental data or visual MCQ options.
Typical Pitfalls and Special Cases with Time Period of SHM
Always use SI units, and check whether the question asks for time period, frequency, or angular frequency. Avoid these pitfalls:
- Mixing up frequency (Hz) and period (s) in calculations
- Applying T = 2\(\pi\)/\(\omega\) where ω is not angular frequency
- Using large angles (θ > 15°) for pendulums, which violate the SHM approximation
- Assuming amplitude affects T in all systems—it does not for linear SHM
- For tunnel through Earth or charged particle in electric field, check for relevant force laws
Mastering these avoids losing marks on common trick questions. For advanced practice, link this topic to Superposition of SHM and Resonance Column Tube.
Further Applications and SHM Resources on Vedantu
Strong grip on the time period of SHM is vital for succeeding in JEE Main physics. It connects directly to advanced topics like Simple Harmonic Motion, Spring-Mass System, Spring-Block Oscillations, and Time Period of Simple Pendulum. For in-depth formulae and concepts, explore the Physics Formulas and Preparation Tips pages.
Relevant pages like Oscillation, Series and Parallel Combination of Springs, and Energy in SHM extend the understanding of time period in various JEE contexts. This page is regularly reviewed by experienced educators for JEE alignment. Vedantu’s content is designed for accuracy, clarity, and straightforward application to exam problems.
FAQs on Time Period of Simple Harmonic Motion (SHM): Complete Guide
1. What is the formula for the time period of SHM?
The formula for the time period (T) of simple harmonic motion (SHM) is:
- T = 2π/ω, where ω (omega) is the angular frequency of oscillation.
- Alternatively, for a spring-mass system, T = 2π√(m/k) where m is mass and k is spring constant.
- For a simple pendulum, T = 2π√(l/g) where l is length and g is acceleration due to gravity.
This formula is essential for solving exam problems related to the time period of SHM, oscillation period, and their relationship with frequency and angular frequency.
2. How do you calculate the time period of an oscillation?
To calculate the time period (T) of an oscillation, use the appropriate SHM formula based on the system:
- For spring-mass system: T = 2π√(m/k)
- For simple pendulum: T = 2π√(l/g)
- For general SHM: T = 2π/ω
Determine system parameters (mass, length, gravity, spring constant, or angular frequency) and substitute them into the formula.
This approach is crucial for JEE, NEET, and board exam problems involving SHM and related oscillations.
3. How is the time period of SHM related to angular frequency?
The relationship between time period (T) and angular frequency (ω) in SHM is:
- T = 2π/ω
- As angular frequency increases, the time period decreases.
- The relationship also links to frequency (f): T = 1/f and ω = 2πf.
Understanding this connection helps distinguish between frequency, period, and angular frequency in exam problems and concept questions.
4. What does the time period of SHM depend on?
The time period of SHM depends on the physical system and its properties:
- For a spring-mass system: mass (m) and spring constant (k)
- For a pendulum: length (l) and acceleration due to gravity (g)
- In fields: sometimes mass, electric field strength, charge, or force constant
- Amplitude does NOT affect time period in ideal, linear SHM
This knowledge is vital for exam variations and physics applications.
5. How do you determine the time period from a SHM displacement vs time graph?
To find the time period from a SHM displacement-time graph:
- Identify two consecutive points where the curve repeats its pattern
- Measure the time interval between these corresponding points
- This interval is the time period (T)
Graph interpretation helps solve frequency and period questions conceptually and visually in exams.
6. Is the time period the same for all types of SHM, like springs and pendulums?
No, the time period of SHM varies depending on the system and physical parameters:
- Spring-mass system: T = 2π√(m/k)
- Pendulum: T = 2π√(l/g)
- Other systems: Factors like electric fields, charge, or tunnel length may affect T
Each type of SHM has its specific formula based on system conditions, reflecting exam-specific problems.
7. Does changing the amplitude affect the time period of SHM?
In ideal (linear) SHM, changing amplitude does not affect the time period:
- The time period (T) remains constant, independent of amplitude
- This is valid for small oscillations
- In real systems or large amplitudes, slight variation may occur
This fact is important for concept clarity and avoiding common exam mistakes.
8. How does the time period of SHM change under different physical conditions?
The time period of SHM can change with variations in:
- Mass (m): Increases T for a spring-mass system
- Spring constant (k): Higher k decreases T
- Length (l): Longer pendulum increases T
- Gravity (g): Higher g reduces T for pendulums
- External fields: Electric or magnetic fields can affect T if involved
Understanding these dependencies is essential for solving numerical and conceptual exam questions.
9. Can the time period of SHM ever be zero?
The time period of SHM can never be zero for a real physical system:
- Zero time period implies infinite frequency, which is not physically possible
- T approaches zero only if certain system parameters become unphysical (e.g., infinite spring constant)
This concept helps address theoretical doubts in competitive exams.
10. What is the difference between time period and frequency in SHM?
Time period (T) and frequency (f) are related but distinct in SHM:
- Time period (T): Time taken for one full oscillation (measured in seconds)
- Frequency (f): Number of oscillations per second (measured in hertz, Hz)
- They are inversely related: T = 1/f
This distinction is crucial for precision in problem-solving and theory questions in the syllabus.
11. How to handle units and conversions when solving time period problems in exams?
To handle units and conversions for time period problems:
- Always write quantities in SI units (mass in kg, length in meters, k in N/m, g in m/s²)
- Use seconds (s) for the time period
- Check that final answers are in standard units as required by the question
Proper unit handling ensures accuracy in exam solutions and prevents calculation errors.





















