
In the figure shown the wave speed is ‘\[v\]’. The velocity of the car is ‘\[{v_0}\]’. The beat frequency for the observer will be:
A. \[\dfrac{{2{f_0}v{v_0}}}{{{v^2} + v_0^2}} \\ \]
B. \[\dfrac{{2{f_0}{v^2}}}{{{v^2} - v_0^2}} \\ \]
C. \[\dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}} \\ \]
D. \[\dfrac{{{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Answer
128.1k+ views
Hint: If the frequency when the car is approaching is \[{f_1}\] and when the car is leaving is \[{f_2}\]. Get the value of \[{f_1}\] and \[{f_2}\] in terms of \[{f_0}\] . The Doppler effect or Doppler shift can be describing the changes in frequency of sound or light wave produced by a moving source with respect to an observer. Also, we know that the beat frequency is defined as the difference in frequency of two waves. By using this we can get the result.
Formula used:
Frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right)\]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right)\]
Where \[{f_1}\] and \[{f_2}\] is the frequency required, \[{f_0}\] is the given frequency, \[v\] is the velocity of the observer and \[{v_0}\] is the velocity of sound.
Beat frequency is given as,
\[{f_1} - {f_2}\]
Where \[{f_1} - {f_2}\] represents the change in frequency.
Complete step by step solution:
As we know that the frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right) \\ \]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right) \\ \]
Now the beat frequency = \[{f_1} - {f_2} \\ \]
\[\text{beat frequency} = {f_0}v\left( {\dfrac{1}{{v - {v_0}}} - \dfrac{1}{{v + {v_0}}}} \right) \\ \]
\[\Rightarrow \text{beat frequency} = {f_0}v\left( {\dfrac{{v + {v_0} - v + {v_0}}}{{{v^2} - v_0^2}}} \right) \\ \]
\[\therefore \text{beat frequency} = \dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Hence option C is the correct answer.
Note:The formula for Doppler Effect is related to the frequency of the sound of an object with its velocity. Doppler Effect is defined as the change in wave frequency during the relative motion between the wave source and its observer. It was given by Christian Johann Doppler. Beats can be determined by subtracting the initial frequency with the frequency observed by the observer.
Formula used:
Frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right)\]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right)\]
Where \[{f_1}\] and \[{f_2}\] is the frequency required, \[{f_0}\] is the given frequency, \[v\] is the velocity of the observer and \[{v_0}\] is the velocity of sound.
Beat frequency is given as,
\[{f_1} - {f_2}\]
Where \[{f_1} - {f_2}\] represents the change in frequency.
Complete step by step solution:
As we know that the frequency when source is approaching is given as,
\[{f_1} = {f_0}\left( {\dfrac{v}{{v - {v_0}}}} \right) \\ \]
Frequency when source is leaving is given as,
\[{f_2} = {f_0}\left( {\dfrac{v}{{v + {v_0}}}} \right) \\ \]
Now the beat frequency = \[{f_1} - {f_2} \\ \]
\[\text{beat frequency} = {f_0}v\left( {\dfrac{1}{{v - {v_0}}} - \dfrac{1}{{v + {v_0}}}} \right) \\ \]
\[\Rightarrow \text{beat frequency} = {f_0}v\left( {\dfrac{{v + {v_0} - v + {v_0}}}{{{v^2} - v_0^2}}} \right) \\ \]
\[\therefore \text{beat frequency} = \dfrac{{2{f_0}v{v_0}}}{{{v^2} - v_0^2}}\]
Hence option C is the correct answer.
Note:The formula for Doppler Effect is related to the frequency of the sound of an object with its velocity. Doppler Effect is defined as the change in wave frequency during the relative motion between the wave source and its observer. It was given by Christian Johann Doppler. Beats can be determined by subtracting the initial frequency with the frequency observed by the observer.
Recently Updated Pages
Difference Between Vapor and Gas: JEE Main 2024

Area of an Octagon Formula - Explanation, and FAQs

Difference Between Solute and Solvent: JEE Main 2024

Absolute Pressure Formula - Explanation, and FAQs

Carbon Dioxide Formula - Definition, Uses and FAQs

Charle's Law Formula - Definition, Derivation and Solved Examples

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Login 2045: Step-by-Step Instructions and Details

Class 11 JEE Main Physics Mock Test 2025

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement
