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Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

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CBSE Physics Chapter 1 Units and Measurements Class 11 Notes: FREE PDF Download

Understanding the fundamentals of units and measurements is essential for understanding Physics in Class 11. Vedantu’s detailed notes for CBSE Physics Chapter 1 offer a clear and concise overview of the key concepts and principles according to the latest Class 11 Physics Syllabus. This chapter introduces you to the basics of measurement, including the importance of units, the various types of measurements, and the methods for accurate data collection. 

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With these notes, you'll gain a solid foundation in how measurements are made and how they are used in scientific calculations. Perfect for quick revisions and exam preparation, our Class 11 Physics Notes help you understand complex topics simply and easily.

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Access Revision Notes For Class 11 Physics Chapter 1 Units and Measurement

Units:

A unit can be defined as an internationally accepted standard for measuring quantities.

  • Measurement has been included in a numeric quantity along with a specific unit.

  • The units in the case of base quantities (such as length, mass etc.) are defined as Fundamental units.

  • Derived units are the units that are the combination of fundamental units. 

  • Fundamental and Derived units constitute together as a System of Units.

  • An internationally accepted system of units can be defined as Système Internationale d’ Unites (This is how the International System of Units is represented in French) or SI. In 1971, it was produced and recommended by the General Conference on Weights and Measures.

  • The table shown below is the list of 7 base units mentioned by SI.


There are two units along with it. They are, radian or rad (unit for plane angle) and steradian or sr (unit for solid angle). Both of these are dimensionless.

Base Quantity

Name

Symbol

Length

metre

m

Mass

kilogram

kg

Time

second

s

Electric Current

ampere

A

Thermodynamic

Temperature

kelvin

K

Amount of Substance

mole

mol

Luminous intensity

candela

cd


Plane angle



Solid angle


Significant Figures

Every measurement gives us an output in a number that includes of reliable digits and uncertain digits.

Reliable digits added with the first uncertain digit can be defined as significant digits or significant figures. This represents the precision of measurement which is dependent on the least count of instrument used for measurement.

The period of oscillation of a pendulum is 1.62 s can be taken as an example. Here 1 and 6 will be reliable and 2 is uncertain. Hence, the measured value will have three significant figures.


Rules for the determination of the number of significant figures

  • All non-zero digits will be significant.

  • Irrespective of the decimal place, all zeros between two non-zero digits will be significant irrespective of the decimal place.

  • Zeroes before non-zero digits and after decimal are not considered as significant, for a value less than 1. Zero presents before the decimal place in case these numbers will be insignificant always.

  • Trailing zeroes in case of a number without any decimal place will be insignificant.

  • Trailing zeroes in case of a number with a decimal place will be significant.


Cautions for removing ambiguities in calculating the number of significant figures

  • Variation of units will not change number of significant digits. As an example, 

$\text{4}\text{.700 m=470}\text{.0 cm}$ 

$\text{              =4700 mm}$ 

Here first two quantities have 4 but the third quantity is having 2 significant figures.

  • Make use of scientific notation for reporting measurements. Numbers must be shown in powers of 10 such as \[\text{a }\!\!\times\!\!\text{ 10b}\]where b is defined as the order of magnitude. Example,

$\text{4}\text{.700 m = 4}\text{.700  }\!\!\times\!\!\text{  1}{{\text{0}}^{\text{2}}}\text{ cm }$

$\text{               = 4}\text{.700  }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\text{ mm }$

$\text{               = 4}\text{.700  }\!\!\times\!\!\text{  1}{{\text{0}}^{\text{-3}}}\text{ km}$

Here, as the power of 10 is being irrelevant, the number of significant figures will be 4.

  • Multiplying or dividing exact numbers will give an infinite number of significant digits. Example,\[\text{radius=}\frac{\text{diameter}}{\text{2}}\]. In this case, 2 can be represented as 2, 2.0, 2.00, 2.000 and so on.


Rules for Arithmetic operation with Significant Figures

Type

Multiplication or

Division

Addition or Subtraction

Rule

The end result must retain as many significant figures as there in the initial number with the least number of significant digits.

The end result must have as many decimal places similar way as in the original number with the least decimal places.

Example

\[\text{Density=}\frac{\text{Mass}}{\text{Volume}}\]

Assume\[\text{Mass=4}\text{.237 g}\](4 significant figures)

and \[\text{Volume=2}\text{.51 c}{{\text{m}}^{3}}\]

(3 significant figures)

$\text{Density=}\frac{\text{4}\text{.237 g}}{\text{2}\text{.51 c}{{\text{m}}^{3}}}$

$\text{             =1}\text{.68804 gc}{{\text{m}}^{-3}}$ 

$\text{             =1}\text{.69 gc}{{\text{m}}^{-3}}$ 

 (3 significant figures)

Addition of 436.32 (2

digits after decimal),

227.2 (1 digit after decimal)

and .301 (3 digits after

decimal) is= 663.821

As 227.2 is precise up to only 1 decimal

place, Therefore, the end result should be 663.8.


Rules for Rounding off the uncertain digits

Rounding off will be essential for reducing the number of insignificant figures to hold to the rules of arithmetic operation with significant figures.

Rule Number

Insignificant digit

Preceding digit

Example (rounding off to two decimal places)

1

Insignificant digit to be dropped

being more than 5

Preceding digit is

raised by 1.

Number– 3.137

Result –3.14

2

Insignificant digit to be dropped

being less than 5

The preceding digit is left unchanged.

Number– 3.132

Result –3.13

3

Insignificant digit to be dropped being equal to 5

The preceding digit is even, it is left unchanged.

Number– 3.125

Result –3.12

4

Insignificant digit to be dropped

being equal to 5

When the preceding digit is odd, it is raised by 1.

Number– 3.135

Result –3.14


Rules for the determination of uncertainty in the results of arithmetic calculations

For calculating the uncertainty, the below process must be used.

  • Do a summation of the lowest amount of uncertainty in the original numbers. Example uncertainty for 3.2 will be \[\pm 0.1\] and for 3.22 will be \[\pm 0.01\].

  • Find out these in percentage also.

  • The uncertainties get multiplied/divided/added/subtracted after the calculations.

  • In the uncertainty, round off the decimal place to obtain the end uncertainty result.

For example, for a rectangle, 

Suppose length,  \[\text{l=16}\text{.2 cm}\] and breadth, \[\text{b=10}\text{.1 cm}\]

After that, take \[\text{l=16}\text{.2}\pm \text{0}\text{.1 cm}\]or \[\text{l=16}\text{.2 cm}\pm \text{0}\text{.6  }\!\!%\!\!\text{ }\] and

breadth \[\text{=10}\text{.1 }\!\!\pm\!\!\text{ 0}\text{.1 cm}\]or \[\text{10}\text{.1 cm }\!\!\pm\!\!\text{ 1  }\!\!%\!\!\text{ }\]

When we multiply,

\[\text{area=length }\!\!\times\!\!\text{ breadth=163}\text{.62 c}{{\text{m}}^{\text{2}}}\text{ }\!\!\pm\!\!\text{ 1}\text{.6  }\!\!%\!\!\text{ }\]

Or \[\text{163}\text{.62}\pm \text{2}\text{.6 c}{{\text{m}}^{\text{2}}}\]

Hence after rounding off, area\[\text{=164}\pm \text{3 c}{{\text{m}}^{\text{2}}}\].

Therefore \[\text{3 c}{{\text{m}}^{\text{2}}}\]will be the uncertainty or the error in estimation.


Rules

1. In the case of a set of experimental data of ‘n’ significant figures, the result must be accurate to ‘n’ significant figures or less (only in the case of subtraction).

For example \[\text{12}\text{.9-7}\text{.06=5}\text{.84 or 5}\text{.8}\](when we round off to least number of decimal places of original number).

2. The relative error of a value of number mentioned to significant figures will be dependent on n and on the number itself.

As an example, say the accuracy for two numbers 1.02 and 9.89 be \[\pm \text{0}\text{.01}\]. But relative errors are:

For \[\text{1}\text{.02,}\left( \frac{\text{ }\!\!\pm\!\!\text{ 0}\text{.01}}{\text{1}\text{.02}} \right)\text{ }\!\!\times\!\!\text{ 100  }\!\!%\!\!\text{ =}\pm \text{1  }\!\!%\!\!\text{ }\]

For\[\text{9}\text{.89,}\left( \frac{\text{ }\!\!\pm\!\!\text{ 0}\text{.01}}{\text{9}\text{.89}} \right)\text{ }\!\!\times\!\!\text{ 100  }\!\!%\!\!\text{ =}\pm 0.\text{1  }\!\!%\!\!\text{ }\]

Therefore, the relative error will be dependent upon the number itself.

3. The results in the intermediate step of a multi-step computation should be found to have one significant figure more in all the measurements than the number of digits in the least precise measurement.

For example:\[\frac{1}{9.58}=0.1044\]

Now, \[\frac{1}{0.104}=9.56\] and \[\frac{1}{0.1044}=9.58\]

Therefore, taking one extra digit will provide more precise outputs and reduce rounding-off errors.


Dimensions of a Physical Quantity

The powers (exponents) to which base quantities are raised to represent that quantity can be defined as dimensions of a physical quantity. They are figured as the square brackets around the quantity.

  • Dimensions of the 7 base quantities have been considered as – Length [L], time [T], Mass [M], thermodynamic temperature [K], luminous intensity [cd], electric current [A] and amount of substance [mol].

For example,

$\text{Volume=Length }\!\!\times\!\!\text{ Breadth }\!\!\times\!\!\text{ Height}$

$text{=}\left[ \text{L} \right]\text{ }\!\!\times\!\!\text{ }\left[ \text{L} \right]\text{ }\!\!\times\!\!\text{ }\left[ \text{L} \right]\text{=}{{\left[ \text{L} \right]}^{\text{3}}}$ 

$\text{Force=Mass }\!\!\times\!\!\text{ Acceleration}$

$\text{=}\frac{\left[ \text{M} \right]\left[ \text{L} \right]}{{{\left[ \text{T} \right]}^{\text{2}}}}\text{=}\left[ \text{M} \right]\left[ \text{L} \right]{{\left[ \text{T} \right]}^{\text{-2}}}$

  • The other dimensions for a quantity will be always 0. As an example, in the case of volume only length has 3 dimensions but the mass, time

etc will have 0 dimensions. Zero dimension is shown by superscript 0 like \[\left[ {{\text{M}}^{0}} \right]\].

Dimensions will not affect the magnitude of a quantity Dimensional formula and Dimensional Equation

The expression that represents how and which of the base quantities represent the dimensions of a physical quantity is defined as a Dimensional Formula.

An equation we got after equating a physical quantity with its dimensional formula is a Dimensional Equation.

Physical Quantity

Dimensional Formula

Dimensional Equation

Volume

\[\left[ {{\text{M}}^{\text{0}}}{{\text{L}}^{3}}{{\text{T}}^{\text{0}}} \right]\]

\[\left[ \text{V} \right]\text{=}\left[ {{\text{M}}^{\text{0}}}{{\text{L}}^{\text{3}}}{{\text{T}}^{\text{0}}} \right]\]

Speed

\[\left[ {{\text{M}}^{\text{0}}}\text{L}{{\text{T}}^{\text{-1}}} \right]\]

\[\left[ \nu  \right]\text{=}\left[ {{\text{M}}^{\text{0}}}\text{L}{{\text{T}}^{\text{-1}}} \right]\]

Force

\[\left[ \text{ML}{{\text{T}}^{-2}} \right]\]

\[\left[ \text{F} \right]\text{=}\left[ \text{ML}{{\text{T}}^{-2}} \right]\]

Mass Density

\[\left[ \text{M}{{\text{L}}^{-3}}{{\text{T}}^{0}} \right]\]

\[\left[ \rho  \right]\text{=}\left[ \text{M}{{\text{L}}^{-3}}{{\text{T}}^{0}} \right]\]


Dimensional Analysis

  • The physical quantities that have similar dimensions only can be added and subtracted. This can be named as the principle of homogeneity of dimensions.

  • Dimensions are multipliable and can be cancelled as normal algebraic methods.

  • Quantities on both sides should always have identical dimensions, in mathematical equations.

  • Arguments of special functions such as trigonometric, logarithmic and ratio of similar physical quantities will be dimensionless.

  • Equations will be uncertain to the extent of dimensionless quantities.

As an example, say Distance = Speed x Time. In Dimension terms, 

\[\left[ \text{L} \right]\text{=}\left[ \text{L}{{\text{T}}^{\text{-1}}} \right]\text{ }\!\!\times\!\!\text{ }\left[ \text{T} \right]\]

As the dimensions can be cancelled as we do in algebra, dimension \[\left[ \text{T} \right]\] will get cancelled and the equation will be \[\left[ \text{L} \right]\text{=}\left[ \text{L} \right]\].


Applications of Dimensional Analysis

When we check the Dimensional Consistency of equations

  • A dimensionally correct equation should have identical dimensions on both sides of the equation.

  • There is no need for a dimensionally correct equation to be a correct equation but a dimensionally incorrect equation will be always incorrect. Dimensional validity can be tested but not calculate the correct relationship between the physical quantities.

Example, \[\text{x=}{{\text{x}}_{\text{0}}}\text{+}{{\text{ }\!\!\nu\!\!\text{ }}_{\text{0}}}\text{t+}\left( \frac{\text{1}}{\text{2}} \right)\text{a}{{\text{t}}^{\text{2}}}\]

Or, Dimensionally, \[\left[ \text{L} \right]\text{=}\left[ \text{L} \right]\text{+}\left[ \text{L}{{\text{T}}^{\text{-1}}} \right]\left[ \text{T} \right]\text{+}\left[ \text{L}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{T}}^{\text{2}}} \right]\]

Where, \[\text{x}\] be the distance travelled in time t,

\[{{\text{x}}_{0}}\]– starting position,

\[{{\nu }_{0}}\]- initial velocity,

\[\text{a}\]– uniform acceleration.

Dimensions on both sides will be [L] because [T] get cancelled out. Therefore this will be a dimensionally correct equation.


Deducing relation among physical quantities

  • For deducing a relation among physical quantities, we must know the dependence of one quantity over others (or independent variables) and assume it as a product type of dependence.

  • Dimensionless constants will not be obtainable by the use of this method.

We can take an example, 

\[\text{T=k}{{\text{l}}^{\text{x}}}{{\text{g}}^{\text{y}}}{{\text{m}}^{\text{z}}}\]

Or,

$\left[ {{\text{L}}^{\text{0}}}{{\text{M}}^{\text{0}}}{{\text{T}}^{\text{1}}} \right]\text{=}{{\left[ {{\text{L}}^{\text{1}}} \right]}^{\text{x}}}{{\left[ {{\text{L}}^{\text{1}}}{{\text{T}}^{\text{-2}}} \right]}^{\text{y}}}{{\left[ {{\text{M}}^{\text{1}}} \right]}^{\text{z}}}$ 

$\text{                =}\left[ {{\text{L}}^{\text{x+y}}}{{\text{T}}^{\text{-2y}}}{{\text{M}}^{\text{z}}} \right]$

This means that, \[\text{x+y=0,-2y=1 and z=0}\]. So \[\text{x=}\frac{1}{2}\text{,y=-}\frac{1}{2}\text{ and z=0}\].

Hence the original equation will be reduced to \[\text{T=k}\sqrt{\frac{\text{l}}{\text{g}}}\].


Section–A (1 Mark Questions)

1. What is an error? 

Ans. An error is a mistake of some kind causing an error in your results, so the result is not accurate.


2. Find the number of the significant figures in $11\cdot 118\times 10^{-6}V$.

Ans. The number of significant figures is 5 as 10−6 does not affect this number.


3. A physical quantity P is given by $P=\dfrac{A^{5}B^{\dfrac{1}{2}}}{C^{-4}D^{\dfrac{3}{2}}}$ . Find the quantity which brings in the maximum percentage error in P.

Ans. Quantity C has maximum power. So it brings maximum error in P.


4. What is the difference between accuracy and precision?

Ans. Accuracy is an indication of how close a measurement is to the accepted value.

  • An accurate experiment has a low systematic error.

Precision is an indication of the agreement among several measurements.  

  • A precise experiment has a low random error.


difference between accuracy and precision


5. Find the value of a for which $m=\dfrac{1}{\sqrt{3}}$ is a root of the equation $am^{2}+(\sqrt{3}-\sqrt{2})m-1=0$ .

Ans. Put $m=\dfrac{1}{\sqrt{3}}\Rightarrow \dfrac{a}{3}+(\sqrt{3}-\sqrt{2})\dfrac{1}{\sqrt{3}}-1=0$

$\Rightarrow a_+(3-\sqrt{6})-3=0$

So, a = $\sqrt{6}$


Section – B (2 Marks Questions)

6. A force F is given by $F=at+bt^{2}$ , where t is time. What are the dimensions of a and b?

Ans. From the principle of dimensional homogeneity $\left [ F \right ]=\left [ at \right ]\therefore \left [ a \right ]=\left [ \dfrac{F}{t} \right ]=\left [ \dfrac{MLT^{-2}}{T} \right ]=\left [ MLT^{-3} \right ]$

Similarly, $\left [ F \right ]=\left [ bt^{2} \right ]\therefore \left [ b \right ]=\left [ \dfrac{F}{t^{2}} \right ]=\left [ \dfrac{MLT^{-2}}{T^{2}} \right ]=\left [ MLT^{-4} \right ]$ .


7. Let l, r, c, and v represent inductance, resistance, capacitance, and voltage, respectively. Find the dimension of 1/rcv in SI units.  

Ans. Dimension of inductance = [M1L2T−2A−2] = [l]

Dimension of capacitance = [M−1L−2T4A2] = [c]

Dimension of resistance = [M1L2T−3A−2] = [r]

Dimension of voltage = [M1L2T−3A−1] = [v]

Dimension of l/rcv = 

M1L2T−2A−2] / [M−1L2T4A2][M1L2T−3A−2]

[M1L2T−3A−1]
= [ML2T−2A−2]/[ML2T−2A−1]

= [A−1]


8. P represents radiation pressure, c represents speed of light and S represents radiation energy striking unit area per sec. Find the nonzero integers x, y, z such that $P^{x}S^{y}c^{z}$ is dimensionless.

Ans. Try out the given alternatives.

When x = 1, y = −1, z = 1

$P^{x}S^{y}c^{z}=P^{-1}S^{-1}c^{1}=\dfrac{Pc}{S}$

$=\dfrac{\left [ ML^{-1}T^{-2} \right ]\left [ LT^{-1} \right ]}{\left [ \dfrac{ML^{2}T^{-2}}{L^{2}T} \right ]}=\left [ M^{0}L^{0}T^{0} \right ]$


9. The length and breadth of a metal sheet are 3.124 m and 3.002 m respectively. Find the area of this sheet up to the correct significant figure is

Ans. $A=3\cdot 124m\times 3\cdot 002m$

$A=\dfrac{9\cdot 738248}{248m^{2}}$

$=9\cdot 378m^{2}$


10. A certain body weighs 22.42 gm and has a measured volume of 4.7 cc. The possible errors in the measurement of mass and volume are 0.01 gm and 0.1 cc. Then find the maximum error in the density.

Ans. $D=\dfrac{M}{V}\therefore %\dfrac{\Delta D}{D}=%\dfrac{\Delta M}{M}+%\dfrac{\Delta V}{V}=\left ( \dfrac{0\cdot 01}{22\cdot 42}-\dfrac{0\cdot 1}{4\cdot 7} \right )\times 100=2%$


5 Important Topics of Class 11 Physics Chapter 1 Units and Measurements:

S. No

Topics

1

systems of Units

2

Significant figures

3

Dimensions of physical quantities

4

Dimensional formulae and dimensional equations

5

Dimensional analysis and its applications


Importance of Class 11 Physics Chapter 1 Units and Measurement Revision Notes 

Vedantu's Units and Measurements Class 11 Notes offer students a valuable resource to grasp the fundamental concepts of physics. By using Vedantu's notes, students can enhance their problem-solving skills and develop a strong foundation in physics, empowering them to excel in their academic pursuits. Here are some points that explain the Importance of Units and Measurements Class 11 Notes PDF Download:


  • Vedantu's Class 11 Physics Chapter 1 Notes provide a comprehensive understanding of fundamental concepts in physics.

  • These notes cover topics such as SI units, dimensional analysis, and measurements with precision.

  • They offer clear explanations and examples to aid in conceptual clarity and application of theories.

  • Vedantu's notes facilitate effective revision and preparation for exams by condensing complex concepts into concise summaries.

  • With Class 11 Units and Measurements Notes, students can enhance their problem-solving skills and achieve mastery in the subject, laying a strong foundation for future studies in physics.


Tips for Learning the Class 11 Chapter 1  Physics Units and Measurement

  • Start by understanding the basic concepts of units and measurement. Learn about different types of units, such as SI units and derived units, and their importance.

  • Apply what you learn to real-life examples. Measure objects around you using different units to see how measurements work in practice.

  • Practise converting between different units, like metres to centimetres or kilograms to grams. This helps reinforce your understanding of unit relationships.

  • Focus on key formulas related to measurement, such as those for calculating density, speed, and other derived quantities. Know how and when to use these formulas.

  • Review measurement techniques and tools. Learn how to use tools like callipers and micrometres correctly.

  • Solve practice problems to test your understanding. This helps you apply concepts and formulas in different scenarios.

  • Create summary notes and revise regularly. Highlight important points, definitions, and units to make revision easier.


Conclusion

Class 11 Physics Chapter 1 Units and Measurements Notes offered by Vedantu is an excellent resource for students who want to excel in their physics studies. The Class 11 Units and Measurements Notes provide a comprehensive and detailed explanation of the concepts of units and measurement, including the SI units, dimensions, and errors, making it easier for students to understand and improve their physics skills. The notes also include practice exercises and questions that help students test their understanding of the chapter and prepare for their exams. Vedantu also provides interactive live classes and doubt-solving sessions to help students clarify their doubts and improve their understanding of the chapter. Overall, the Units And Measurements Class 11 Notes PDF offered by Vedantu is an essential resource for students who want to improve their physics skills and score well in their exams.


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FAQs on Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

1. What is a quick summary of the key concepts in the Class 11 chapter on Units and Measurements?

This chapter establishes the foundation of physics by introducing the need for standard units. Key concepts to revise include the International System of Units (SI), distinguishing between fundamental and derived units, understanding the concepts of accuracy and precision, applying dimensional analysis to check equations and derive relationships, and correctly using significant figures and error analysis in calculations.

2. What are the seven fundamental quantities and their SI base units that I must remember?

For a quick recap, you should memorise the seven fundamental quantities as defined by the SI system and their corresponding base units:

  • Length - meter (m)
  • Mass - kilogram (kg)
  • Time - second (s)
  • Electric Current - ampere (A)
  • Thermodynamic Temperature - kelvin (K)
  • Amount of Substance - mole (mol)
  • Luminous Intensity - candela (cd)

3. How are physical units categorized for revision?

For revision, you can categorise all physical units into two main types:

  • Fundamental Units: These are the base units for the seven fundamental quantities (like meter, kilogram, second) that are independent of each other.
  • Derived Units: These are units that are formed by combining one or more fundamental units. For example, the unit for speed (m/s) is derived from the fundamental units of length (meter) and time (second).

4. What is the core difference between accuracy and precision in measurements?

The key difference to remember is that accuracy refers to how close a measured value is to the true or accepted value. In contrast, precision refers to how close multiple measurements of the same quantity are to each other, regardless of their accuracy. An instrument can be precise without being accurate.

5. How does the principle of homogeneity of dimensions help in checking the correctness of a physical equation?

The principle of homogeneity states that a physically valid equation must have the same dimensions on both sides of the equals sign. This is because we can only add, subtract, or equate quantities that have the same physical nature. For revision, remember this simple check: if the dimensions of the Left Hand Side (LHS) do not match the dimensions of the Right Hand Side (RHS), the equation is dimensionally incorrect and therefore physically wrong.

6. What are the basic rules for determining significant figures that I should recap?

To quickly revise significant figures, focus on these key rules:

  • All non-zero digits are significant.
  • Zeros between two non-zero digits are significant (e.g., 101 has 3).
  • Leading zeros (e.g., 0.05) are not significant.
  • Trailing zeros are significant only if there is a decimal point (e.g., 5.00 has 3, but 500 has 1).
When performing calculations, the result should be rounded to the least number of significant figures (for multiplication/division) or decimal places (for addition/subtraction) present in the original data.

7. Why can't dimensional analysis determine the value of dimensionless constants in a formula?

This is a key limitation to remember. Dimensional analysis works by comparing the base dimensions (M, L, T, etc.) on both sides of an equation. Dimensionless constants (like π, 1/2, or k) have no dimensions by definition. Therefore, the method of equating powers of M, L, and T cannot provide any information about their presence or their value. Their values must be determined through experimentation or more advanced theory.

8. How should I summarise the concepts of absolute, relative, and percentage errors for quick revision?

For a quick summary, think of them as a progression:

  • Absolute Error is the basic difference between the true value and a measured value. It tells you the magnitude of the error in the same units as the quantity.
  • Relative Error provides context by comparing the absolute error to the true value (Relative Error = Absolute Error / True Value). It is a dimensionless ratio.
  • Percentage Error is simply the relative error expressed as a percentage (Relative Error × 100). It is the most common way to express experimental uncertainty.

9. Beyond checking equations, what are the other key applications of dimensional analysis?

While checking correctness is a primary use, dimensional analysis has two other powerful applications you should revise:

  • Deriving relationships between physical quantities. If you know how one quantity depends on others, you can deduce the form of the equation connecting them (e.g., deriving the formula for the time period of a simple pendulum).
  • Converting units from one system to another. By understanding the dimensional formula of a quantity, you can easily find the conversion factor between different unit systems (e.g., converting Newtons to dynes).

10. How do these revision notes for Units and Measurements align with the latest CBSE 2025-26 syllabus?

These revision notes are carefully crafted to cover all the core concepts prescribed in the CBSE syllabus for the 2025-26 academic year. They focus on the essential topics for Class 11 Physics, Chapter 1, including the SI system, significant figures, error analysis, and dimensional analysis, ensuring your revision is comprehensive and aligned with board requirements.