
A transformer is used to light a 100W and 110V lamp from 220V mains. If the main current 0.5A, efficiency of transformer is:
A) 10%
B) 50%
C) 60%
D) 90%
Answer
139.2k+ views
Hint: Efficiency of transformer is given by:
$\eta = \dfrac{{output}}{{input}}$
It is the ratio of output power to input power. Generally the efficiency is maximum (with fewer losses) because the transformer is a static device.
Complete step by step solution:
Let’s discuss transformers first:
Transformer is a static device which works on the principle of electromagnetic induction. A single phase transformer has two windings primary and secondary winding .Winding having large number of turns have high voltage and the winding having less number of turns have low voltage, because voltage in a winding is directly proportional to the number of turns it has. An ideal transformer has negligible or no losses.
Now comes to the numerical part:
Transformer is used to light 100W lamps having 110V from 220 V mains.
Therefore, the output power which a transformer can give is 100W
Input power is given as:
Mains voltage given = 220V
Mains current = 0.5A
Input Power =220$ \times $ 0.5=110 VA
Efficiency is calculated as:
$
\Rightarrow \eta = \dfrac{{100}}{{110}} \\
\Rightarrow \eta = .909 \\
\Rightarrow \eta = .909 \times 100 = 90.9\% \\
$ (we have substituted the value of input and output power)
Efficiency of the transformer is 90%.
Option (D) is correct.
Note: Transformer has two types of core named core type and shell type. Transformer core is generally made up of high permeability and low loss material like CRGO silicon steel (cold rolled grain oriented). Shell type transformers are used for low voltage applications while core type transformers are used for high voltage applications.
$\eta = \dfrac{{output}}{{input}}$
It is the ratio of output power to input power. Generally the efficiency is maximum (with fewer losses) because the transformer is a static device.
Complete step by step solution:
Let’s discuss transformers first:
Transformer is a static device which works on the principle of electromagnetic induction. A single phase transformer has two windings primary and secondary winding .Winding having large number of turns have high voltage and the winding having less number of turns have low voltage, because voltage in a winding is directly proportional to the number of turns it has. An ideal transformer has negligible or no losses.
Now comes to the numerical part:
Transformer is used to light 100W lamps having 110V from 220 V mains.
Therefore, the output power which a transformer can give is 100W
Input power is given as:
Mains voltage given = 220V
Mains current = 0.5A
Input Power =220$ \times $ 0.5=110 VA
Efficiency is calculated as:
$
\Rightarrow \eta = \dfrac{{100}}{{110}} \\
\Rightarrow \eta = .909 \\
\Rightarrow \eta = .909 \times 100 = 90.9\% \\
$ (we have substituted the value of input and output power)
Efficiency of the transformer is 90%.
Option (D) is correct.
Note: Transformer has two types of core named core type and shell type. Transformer core is generally made up of high permeability and low loss material like CRGO silicon steel (cold rolled grain oriented). Shell type transformers are used for low voltage applications while core type transformers are used for high voltage applications.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

How to find Oxidation Number - Important Concepts for JEE

How Electromagnetic Waves are Formed - Important Concepts for JEE

Electrical Resistance - Important Concepts and Tips for JEE

Average Atomic Mass - Important Concepts and Tips for JEE

Chemical Equation - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

A point charge + 20mu C is at a distance 6cm directly class 12 physics JEE_Main

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

A conducting loop carrying a current is placed in a class 12 physics JEE_Main
