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NCERT Books for Class 12 Chemistry Chapter 4 - Chemical Kinetics

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Chemical Kinetics Free PDF Download

Free NCERT Books download for Class 12 Chemistry Chapter 4 - Chemical Kinetics on Vedantu.com. Students can also download the NCERT Textbooks Solutions in PDF for Class 6 to 12 all subjects. Register for Chemistry tuition to clear your doubts and score more in your exams.

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NCERT Books for Class 12 Chemistry Chapter 4

A Brief Into The Chapter

The concept of chemical kinetics helps us in understanding how chemical reactions occur. Chemical kinetics is a very important chapter as all the other chapters are connected to this concept therefore it is advisable to study this chapter in-depth so that nothing is missed out. To make things even Vedantu’s team has curated study material for the students to access easily. We have provided revision notes for class 12 electrochemistry students that will help them to study the chapter in-depth. 

This chapter covers various important topics that are important to study in order to score exceedingly well in class 12 board exam examples: difference between elementary and complex reactions, the difference between molecularity and order of reaction; it defines rate constant briefly, and describes collision theory.

Subtopics Of The Chapters

The subtopics included in the NCERT book of class 12 in ch 4 are:

  • 4.1 Rate  of a Chemical  Reaction

  • 4.2 Factors Influencing Rate of a Reaction

  • 4.3 Integrated  Rate Equation

  • 4.4 Pseudo First Order Reaction

  • 4.5 Temperature Dependence of the Rate of a Reaction

  • 4.6 Collision Theory of Chemical Reactions

Chemical Kinetics

Chemical kinetics can be studied as chemical reactions with respect to reaction rates, the effect of various variables, rearrangement of atoms, and formation of intermediates. It is a branch of chemistry that deals with the rates of chemical reactions. As a part of thermodynamics. It is also known as reaction kinetics. There are various factors affecting reaction rate such as Nature of the reactants, physical state, the surface area of solid-state, concentration, temperature, catalyst, pressure, absorption of light. Mathematical representation of the rate of a reaction is given by rate law. The NCERT book of class 12 provides a comprehensive understanding of chemical kinetics. The book has a whole chapter dedicated to the study of chemical kinetics called ch -4 chemical kinetics.

The Collision Theory Of Chemical Reactions

Collision theory is used to predict the rates of chemical reactions, particularly gasses. This theory has proven to be extremely useful and has made great progress over time. It is part of our day-to-day fast-paced life, be it fast-moving vehicles or manufacturing plants. This theory is based on the assumption that in order for a chemical reaction to occur, the reaction particles must collide with one another. The kinetic theory of gasses states that for every 1000 binary collisions, there will be only one event in which three molecules simultaneously come together.  Students can study this theory in depth in the class 12 NCERT book in the ch -4 called Chemical kinetics.

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FAQs on NCERT Books for Class 12 Chemistry Chapter 4 - Chemical Kinetics

1. What are the most important topics in Chemical Kinetics from which questions are frequently asked in the CBSE Class 12 board exams?

For the CBSE Class 12 board exam 2025-26, the most important topics in Chemical Kinetics that carry significant weightage are:

  • Integrated Rate Equations: Derivations and numerical problems for zero and first-order reactions.
  • Half-Life Period: Calculations and its relationship with the order of reaction.
  • Arrhenius Equation: Numerical problems to calculate activation energy (Ea) and rate constants at different temperatures.
  • Order and Molecularity: Questions based on the differences and identification from reaction mechanisms.
  • Rate Law: Determining the rate law and order of reaction from experimental data tables.

2. What types of numerical problems are expected from Chapter 4, Chemical Kinetics, in the board exam?

In the Class 12 board exam, you can expect numerical problems based on:

  • Calculating the half-life (t₁/₂) of zero and first-order reactions.
  • Using the integrated rate equation for a first-order reaction to find the time required for a certain percentage of completion (e.g., 99.9%).
  • Determining the order of a reaction and the rate constant (k) from a given set of experimental concentration and rate data.
  • Applying the Arrhenius equation to calculate activation energy or the rate constant at a different temperature.

These questions are often asked for 3 marks.

3. Are there any important derivations in Chemical Kinetics that I should prepare for the board exam?

Yes, two derivations from this chapter are very important for the CBSE board exam. Students must practice deriving the:

  • Integrated rate equation for a zero-order reaction (k = ([R]₀ - [R])/t).
  • Integrated rate equation for a first-order reaction (k = (2.303/t) log([R]₀/[R])).

These derivations are frequently asked as 2 or 3-mark questions.

4. How can I distinguish between 'order of reaction' and 'molecularity' in an exam question to avoid losing marks?

This is a critical concept for scoring well. Remember these key differences:

  • Basis: Order is an experimental quantity determined from the rate law. Molecularity is a theoretical concept for elementary reactions only.
  • Values: Order can be a whole number, zero, or even a fraction. Molecularity must be a positive integer (1, 2, or 3).
  • Applicability: Order applies to both elementary and complex reactions. Molecularity is only defined for elementary (single-step) reactions.

Answering with these distinctions helps secure full marks in theory-based questions.

5. Why is the half-life of a first-order reaction considered independent of the initial concentration, and what is its significance in exam problems?

The half-life of a first-order reaction is independent of the initial reactant concentration because its formula, t₁/₂ = 0.693/k, does not contain any concentration term ([R]₀). This is a crucial concept for HOTS (Higher Order Thinking Skills) questions. For example, if a problem states that the initial concentration of a first-order reactant is doubled, its half-life remains unchanged. Recognising this can help you solve MCQs and short-answer questions quickly and accurately.

6. How does a catalyst work, and how is this concept tested in important questions for the board exam?

A catalyst increases the rate of a reaction by providing an alternative reaction pathway with a lower activation energy (Ea). It does not get consumed in the reaction and does not alter the equilibrium constant (K) or Gibbs free energy (ΔG). In board exams, this is often tested by asking you to:

  • Interpret an energy profile diagram, showing the lowered energy barrier in the presence of a catalyst.
  • Explain why a catalyst increases the rate of both forward and reverse reactions equally.
  • Answer conceptual questions on the characteristics of a catalyst.

7. What is the best strategy to solve numericals where you need to identify the order of a reaction from experimental data?

The most effective strategy is to look for key information in the problem. First, check the units of the rate constant (k) if provided:

  • For zero-order, the unit is mol L⁻¹ s⁻¹.
  • For first-order, the unit is s⁻¹.
  • For second-order, the unit is L mol⁻¹ s⁻¹.

If k is not given, analyse the experimental data table. See how the rate changes when the concentration of a reactant is doubled or halved while keeping others constant. This will help you determine the power to which each reactant concentration is raised in the rate law, thus finding the overall order.

8. What type of graph-based questions can be expected from Chemical Kinetics in the Class 12 exam?

Graph-based questions are a common feature. Be prepared to identify the order of a reaction or calculate values from plots such as:

  • Zero-Order: A plot of [R] vs. time gives a straight line with a slope of -k.
  • First-Order: A plot of ln[R] vs. time gives a straight line with a slope of -k, or a plot of log[R] vs. time gives a slope of -k/2.303.
  • Arrhenius Equation: A plot of ln(k) vs. 1/T gives a straight line with a slope of -Ea/R, from which activation energy (Ea) can be calculated.