

Step-by-Step Guide: Investigating Reaction Rates in Class 12 Chemistry (2025-26)
Redox Reaction refers to the kind of chemical change where both oxidation and reduction happens simultaneously. Oxidation is the chemical process in a substance when oxygen is added to it. The reaction where electrons are gained by one of the atoms among the two or more chemicals in the reaction is known as a reduction reaction.
Potassium iodate is reduced to iodide by sulphite in an acidic medium. Sulphite ions react with potassium iodate, manufacturing iodide ions. Iodide ions, therefore formed, are oxidized to iodine by reaction with more iodate ions. Iodine reacts immediately with sulphite ions forming iodide ions. When sulphite ions are fully consumed, the liberated iodine will not be consumed and will show blue color if starch is present.
This is an example of a clock reaction, as the rate of the reaction is calculable by the time taken for the appearance of the blue color. The oxidation of sodium sulphite by air is retarded by alcohol.
Table of Content
Aim
Articles Required
Theory
Procedure
Result
Precautions
Viva Questions
Lab Manual Questions
Summary
Aim
To study the reaction rate of the reaction between KIO3 (Potassium Iodate) and Na2SO3 (sodium sulphite).
Articles Required
4 Conical flasks (250 ml)
measuring cylinder
Burette
pipette (25 ml)
stop-watch
0.01 M sodium sulphite solution
0.1 M potassium iodate solution
starch solution
2 M H2SO4.
Theory
The reaction between potassium iodate and sodium sulphite indirectly includes the formation of iodide ions oxidized in an acidic medium. The overall reaction takes place in 2 steps.
$\begin{align} & IO_{3}^{-}+3SO_{3}^{2-}\to {{I}^{-}}+3SO_{4}^{2-}\cdots (1) \\ & 5{{I}^{-}}+6{{H}^{+}}+IO_{3}^{-}\to 3{{H}_{2}}O+3{{I}_{2}}\cdots (2) \\ & {{I}_{2}}+SO_{3}^{2-}+{{H}_{2}}O\to SO_{4}^{2-}+2{{I}^{-}}+2{{H}^{+}}\cdots (3,\text{ very fast)} \\ \end{align}$
The evolved iodine generates blue color with a starch solution. This reaction is additionally known as a clock reaction.
Procedure
Take four 250 milliliter conical flasks and label them as A, B, C and D.
Add 10 ml, 20 ml, 30 milliliters and 40 milliliters of 0.1 M KIO3 solution to the flasks A, B, C and D, respectively, with the help of burette.
Add 10 ml of 2 M H2SO4 to each flask.
Add water to form the volume of solution of 100 milliliters in each flask.
Add 5 milliliters of freshly prepared starch solution to every flask.
Add 25 milliliters of 0.01 M sodium sulphite solution to flask A with the assistance of a pipette and start the stopwatch immediately. Note the time once the blue color just appears.
Repeat step 6 with the solutions of flasks B, C and D.
Observation
Result
The rate of reaction will increase with the increase in the concentration of potassium iodate.
Precautions
Following precautions must be taken while carrying out the experiment:
Only use freshly prepared starch solution.
We have only to use a freshly prepared solution of sodium sulfide because it can simply get oxidised by air.
The concentration of KIO3 should be more than the concentration of sodium sulphite solution.
Viva Questions
Q1.What is the concentration of Sulphuric acid used for this experiment?
Ans: 2M.
2.What's the proportion of sodium sulphite solution used for this experiment?
Ans: 6%.
3. What’s the percentage of starch solution used for this experiment?
Ans: 5%.
4. What is the proportion of sodium thiosulphate solution used for this experiment?
Ans: 0.04M.
5. What is the percentage of K iodate solution used for this experiment?
Ans: 6%.
Lab Manual Questions
1. Why is the concentration of K iodate solution kept more than the concentration of sodium sulphite solution?
Ans. As Na2SO3 is likely to be easily oxidised in air, always use a fresh solution of Na2SO3.
Keep the concentration of KIO3 solution more than the concentration of Na2SO3 solution. Use a starch solution that is freshly prepared.
2. What happens when you combine K iodate and sodium metabisulfite?
Ans. In such a reaction, potassium iodate and sodium metabisulfite react to make iodine. The starch solution is an indicator of the end of the reaction by forming a deep-blue coloured starch–iodine complex.
3. Why is the excess of potassium iodide utilised in iodometric titration?
Ans. Potassium iodide should be added in excess to keep iodine dissolved. Once all the ascorbic acid has been consumed, any excess iodine can remain in the solution. Since aqueous iodine solutions are brown in colour, iodine can act as its own indicator.
4. What does K iodate do in salt?
Ans. The Potassium iodide and the role of iodate ions in salt are used to prevent iodine deficiency and associated thyroid disease.
Summary
Kinetics is the study of the rates of chemical reactions. As reactants are transformed into products during a chemical change, the number of reactants can decrease and also the amount of product can increase. The speed of the reaction describes how fast the reaction happens.
The larger the speed of the reaction, the less time is required for a selected amount of reactants to be converted to a product. Some factors that will affect the rate of a chemical reaction include temperature, the nature of the reactants, their concentrations, and the presence of a catalyst. Starch as an indicator is used in the experiment performed.
FAQs on How to Measure Reaction Rate of Potassium Iodate & Sodium Sulphite Using Starch
1. What is the main objective of the Class 12 experiment studying the reaction between potassium iodate and sodium sulphite?
The primary objective of this experiment, as per the CBSE 2025-26 syllabus, is to study the effect of concentration on the rate of reaction between potassium iodate (KIO₃) and sodium sulphite (Na₂SO₃). By varying the concentration of one reactant while keeping others constant, students can determine the order of the reaction and understand the rate law.
2. For the board practical exam, why is it crucial to use freshly prepared solutions of sodium sulphite and starch?
Using freshly prepared solutions is critical for obtaining accurate results and is a common viva question.
- Sodium Sulphite (Na₂SO₃): It is a strong reducing agent and gets readily oxidised by atmospheric oxygen. Using an old solution would mean its actual concentration is lower than stated, leading to incorrect reaction rate calculations.
- Starch Solution: Over time, starch solutions can undergo bacterial decomposition or hydrolysis, which significantly reduces their ability to act as an effective indicator for iodine, resulting in a poorly defined or faint blue colour endpoint.
3. Why is the reaction between potassium iodate and sodium sulphite known as an “iodine clock” reaction?
This experiment is called an “iodine clock” reaction because of the characteristic delayed but sudden appearance of the blue colour. The reaction proceeds in two stages: iodine is produced in the first step, but it is immediately consumed by the sodium sulphite. The blue colour, from the iodine-starch complex, only appears abruptly after all the sodium sulphite has been used up, acting like a chemical timer or clock.
4. What is the specific role of the starch solution in this experiment?
The starch solution functions as an indicator. Its purpose is to signal the exact moment when free molecular iodine (I₂) begins to accumulate in the solution. Starch forms a distinct deep blue-black complex with iodine. This colour change marks the endpoint of the reaction, which is the point in time (t) used to calculate the reaction rate.
5. How does increasing the concentration of potassium iodate affect the time taken for the blue colour to appear?
Increasing the concentration of a reactant typically increases the reaction rate. Therefore, if you increase the concentration of potassium iodate (KIO₃), the reaction will proceed faster. This means the time required for the blue colour to appear will decrease, as the fixed amount of sodium sulphite gets consumed more quickly.
6. What is the formula used to calculate the rate of reaction in this practical?
For the iodine clock experiment, the rate of reaction is not calculated in traditional units of mol L⁻¹s⁻¹ but is expressed as a proportional value. The rate is taken to be inversely proportional to the time taken for the endpoint to be reached. Therefore, the rate of reaction is conveniently calculated as Rate ∝ 1/t, where 't' is the time in seconds for the blue colour to appear.
7. What are the key chemical equations a student must know for their viva on this experiment?
For the CBSE Class 12 practical exam, students must know these two essential reactions:
- Step 1 (Main Reaction): 2IO₃⁻(aq) + 5HSO₃⁻(aq) → I₂(aq) + 5SO₄²⁻(aq) + 3H⁺(aq) + H₂O(l)
- Step 2 (Clock Reaction): I₂(aq) + HSO₃⁻(aq) + H₂O(l) → 2I⁻(aq) + SO₄²⁻(aq) + 3H⁺(aq)
8. What are some major sources of error in this experiment that can affect a student's marks?
Common sources of error that can lead to inaccurate results and marks deduction in the board practical include:
- Not using freshly prepared solutions, especially for sodium sulphite and starch.
- Inaccuracy in measuring the volumes of the reactant solutions with pipettes or burettes.
- A significant delay in starting or stopping the stopwatch at the exact moment of mixing and colour appearance.
- Failure to maintain a constant temperature across different experimental sets, as reaction rate is highly sensitive to temperature changes.

















