RD Sharma Class 8 Solutions PDF Available on Vedantu
FAQs on RD Sharma Class 8 Solutions Chapter 10 - Direct and Inverse Variations (Ex 10.1) Exercise 10.1 - Free PDF
1. How can I find reliable, step-by-step solutions for RD Sharma Class 8 Maths, Chapter 10 (Direct and Inverse Variations)?
You can find detailed, step-by-step solutions for all questions in RD Sharma Class 8 Maths Chapter 10, covering both direct and inverse variations, on Vedantu. These solutions are prepared by subject matter experts and follow the latest CBSE guidelines for the 2025-26 session, ensuring accuracy and clarity in every step.
2. What is the fundamental difference between direct variation and inverse variation as explained in Chapter 10?
The fundamental difference lies in how two quantities relate to each other.
- In a direct variation, if one quantity increases, the other quantity also increases at the same rate (e.g., more workers finish more work). The ratio of the quantities (x/y) remains constant.
- In an inverse variation, if one quantity increases, the other quantity decreases proportionally (e.g., more workers take less time to finish the same job). The product of the quantities (x × y) remains constant.
3. How do you determine the constant of proportionality (k) in problems from Exercise 10.1?
To find the constant of proportionality (k), you first identify if the relationship is direct or inverse.
- For direct variation, use the formula x/y = k. You can find 'k' by taking any corresponding pair of values (x₁, y₁) from the problem and calculating their ratio.
- For inverse variation, use the formula x × y = k. You find 'k' by taking any corresponding pair of values (x₁, y₁) and calculating their product.
4. Why is it helpful to create a table when solving word problems on direct and inverse variations?
Creating a table is a highly effective strategy because it helps you organise the given information clearly. By listing the corresponding values of the two quantities (e.g., number of items and their cost), you can easily visualise the relationship between them. This makes it simpler to identify whether it is a case of direct or inverse variation and helps in setting up the correct equation to find the unknown value, reducing the chances of error.
5. Can you provide an example of a direct variation problem from this chapter and outline the steps to solve it?
A common example is: "If the cost of 8 books is ₹400, find the cost of 12 books."
Here are the steps to solve it:
- Step 1: Identify that the number of books and their total cost are in direct variation. As the number of books increases, the cost will also increase.
- Step 2: Set up a proportion. Let the cost of 12 books be 'x'. The ratio of books to cost must be constant: 8/400 = 12/x.
- Step 3: Solve for 'x'. Cross-multiply to get 8x = 400 × 12.
- Step 4: Calculate the final answer: x = (400 × 12) / 8 = ₹600.
6. Are the RD Sharma solutions for Chapter 10 sufficient for preparing for my Class 8 Maths exams?
Yes, practising with the RD Sharma solutions for Chapter 10 is highly beneficial for exam preparation. This chapter in RD Sharma offers a wide variety of problems that build a strong conceptual foundation in direct and inverse variations. Solving these questions helps you master different problem types, improve your speed and accuracy, and gain the confidence needed to tackle similar questions in your exams.
7. How do the RD Sharma Chapter 10 problems enhance my understanding beyond the NCERT textbook?
While the NCERT textbook provides a solid foundation, RD Sharma's Chapter 10 offers a more extensive range of questions. It includes a higher number of practice problems, questions with varying difficulty levels, and more complex word problems. This helps you apply the concepts of direct and inverse variation to a wider array of scenarios, strengthening your problem-solving skills and providing a more thorough preparation.
