
The relation between amplitude of Electric and magnetic field at any place is given by:
Answer
401.7k+ views
Hint: In order to get the relation, we first need to understand the basic property that an electromagnetic wave follows during its propagation in a given space. Understanding this will give us the idea of exactly what is the relation between amplitude of Electric and magnetic field at any place.
Complete answer:
Whenever an electromagnetic wave propagates in a medium it has both magnetic and electric field associated with it. These fields are always in phase with one another.
Both these fields are perpendicular to each other and the direction of propagation of the wave is given by the cross product of these two vectors.
Now the maximum amplitude of electric and magnetic fields is related as.
\[{E_0} = c{B_0}\]
Where the speed of light is $c$.
Now we can determine the speed of light in the given medium by the formula:
\[c = \dfrac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\]
Where ${\mu _0}$ is the dielectric constant and ${\varepsilon _0}$ is the diamagnetic constant.
Note:
Sometimes in different mediums the dielectric and di magnetic constant doesn’t remain the same so we have to multiply a constant value associated with them in order to make the speed of light for that given medium equal to the actual calculated value. It is due to this constant for a given medium that the speed of light is different and we get to see the refraction of light for medium change.
Complete answer:
Whenever an electromagnetic wave propagates in a medium it has both magnetic and electric field associated with it. These fields are always in phase with one another.
Both these fields are perpendicular to each other and the direction of propagation of the wave is given by the cross product of these two vectors.
Now the maximum amplitude of electric and magnetic fields is related as.
\[{E_0} = c{B_0}\]
Where the speed of light is $c$.
Now we can determine the speed of light in the given medium by the formula:
\[c = \dfrac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }}\]
Where ${\mu _0}$ is the dielectric constant and ${\varepsilon _0}$ is the diamagnetic constant.
Note:
Sometimes in different mediums the dielectric and di magnetic constant doesn’t remain the same so we have to multiply a constant value associated with them in order to make the speed of light for that given medium equal to the actual calculated value. It is due to this constant for a given medium that the speed of light is different and we get to see the refraction of light for medium change.
Recently Updated Pages
NCERT Solutions For Class 4 English Marigold (Poem) - Don’t Be Afraid Of The Dark

NCERT Solutions For Class 5 English Marigold (Poem) - Class Discussion

NCERT Solutions For Class 5 English Marigold - Gullivers Travels

NCERT Solutions For Class 5 Hindi Rimjhim - Bagh Aaya Uss Raat

NCERT Solutions For Class 8 Hindi Bharat Ki Khoj - Tanaav

NCERT Solutions For Class 12 Maths - Differential Equations

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE
