Answer
Verified
114.6k+ views
Hint: Use the first law of thermodynamics which states that, if the quantity of heat supplied to the system is capable of doing work, then the quantity of heat absorbed by the system is equal to the sum of the external work done by the system, and the increase in the internal energy of the system. Mathematically,
$dQ = dW + dU$
Complete step by step solution
According to the first law of thermodynamics,
$dQ = dW + dU$ ……(i)
Where, dQ = Amount of heat added to the system.
dW = External work done by the system.
dU = Change in internal energy of the system.
Now, we know that specific heat of a gas at constant volume \[\left( {{C_v}} \right)\] is defined as the amount of heat required to raise the temperature of 1g gas through \[1^\circ C\] keeping the volume of the gas constant.
${C_v} = {\left( {\dfrac{{dQ}}{{dt}}} \right)_v} = {\left( {\dfrac{{dU}}{{dt}}} \right)_v}$ ……(ii)
Again, \[dW = PdV\] ……(iii)
Where, P = Pressure
dV = Change in volume
As volume is constant,
$dV = 0$
$\therefore dW = 0$, (From equation (iii))
So, equation (i) becomes
$dQ = dU$
Again, using equation (ii), we get
$dU = {C_v}dT$
For n mole of gas,
$dU = n{C_v}dT$
This can only happen if the temperature change occurred at constant volume. Therefore correct option is A
Note: In thermodynamics, state function is the property whose value does not depend on the path taken by the system to reach a specific value. For example, if a system changes from state 1 to state 2 then the value of dU will depend on the value of dT at state 1 and 2 but not on the path taken to reach the desired result.
$dQ = dW + dU$
Complete step by step solution
According to the first law of thermodynamics,
$dQ = dW + dU$ ……(i)
Where, dQ = Amount of heat added to the system.
dW = External work done by the system.
dU = Change in internal energy of the system.
Now, we know that specific heat of a gas at constant volume \[\left( {{C_v}} \right)\] is defined as the amount of heat required to raise the temperature of 1g gas through \[1^\circ C\] keeping the volume of the gas constant.
${C_v} = {\left( {\dfrac{{dQ}}{{dt}}} \right)_v} = {\left( {\dfrac{{dU}}{{dt}}} \right)_v}$ ……(ii)
Again, \[dW = PdV\] ……(iii)
Where, P = Pressure
dV = Change in volume
As volume is constant,
$dV = 0$
$\therefore dW = 0$, (From equation (iii))
So, equation (i) becomes
$dQ = dU$
Again, using equation (ii), we get
$dU = {C_v}dT$
For n mole of gas,
$dU = n{C_v}dT$
This can only happen if the temperature change occurred at constant volume. Therefore correct option is A
Note: In thermodynamics, state function is the property whose value does not depend on the path taken by the system to reach a specific value. For example, if a system changes from state 1 to state 2 then the value of dU will depend on the value of dT at state 1 and 2 but not on the path taken to reach the desired result.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key
JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key
Hybridization of Atomic Orbitals Important Concepts and Tips for JEE
Atomic Structure: Complete Explanation for JEE Main 2025
Trending doubts
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
Collision - Important Concepts and Tips for JEE
Ideal and Non-Ideal Solutions Raoult's Law - JEE
Current Loop as Magnetic Dipole and Its Derivation for JEE
A particle performs SHM of amplitude A along a straight class 11 physics JEE_Main
Other Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Keys & Solutions
JEE Main 2023 January 30 Shift 2 Question Paper with Answer Keys & Solutions
NCERT Solutions for Class 11 Physics Chapter 3 Motion In A Plane
A solid sphere of radius r made of a soft material class 11 physics JEE_MAIN