1 g of copper powder was taken in a china dish and heated, what changes take place on heating? When hydrogen gas is passed over this heated substance, a visible change is seen in it. Give the chemical equation of reaction, the name, and the color of the products formed in each case.
Answer
650.1k+ views
Hint: When the copper is heated, the heating occurs in the presence of oxygen, so the copper gets oxidized. When hydrogen is passed over oxidized copper, the reduction of copper takes place, because the hydrogen is used as a reducing agent.
Complete step by step answer:
When copper is heated, it is heated in the presence of oxygen. So the copper gets oxidized. Therefore, when the copper powder is heated in a china dish, copper oxide is formed. So, the red-brown color of copper is changed into black colored copper oxide. The reaction is given below:
\[\underset{\text{Red brown}}{\mathop 2Cu}\,+\underset{Air}{\mathop {{O}_{2}}}\,\xrightarrow{Heat}\underset{Black}{\mathop 2CuO}\,\]
Now hydrogen gas is passed from this product. We know that hydrogen is a reducing agent and it is used to reduce the copper oxide. So, when the hydrogen gas is passed over the copper oxide, copper metal is formed. The black-colored copper oxide is changed into brown colored copper metal. The reaction is given below:
$\underset{Black}{\mathop CuO}\,+{{H}_{2}}\to \underset{Brown}{\mathop Cu(s)}\,+{{H}_{2}}O$
So, the powdered copper changes to copper oxide, and then it changes to copper metal.
Note: In this reaction, chemical change and physical change occurs. Chemical change because the reactant is converted into products in both reaction and physical change because of the color changes in both reactions.
Complete step by step answer:
When copper is heated, it is heated in the presence of oxygen. So the copper gets oxidized. Therefore, when the copper powder is heated in a china dish, copper oxide is formed. So, the red-brown color of copper is changed into black colored copper oxide. The reaction is given below:
\[\underset{\text{Red brown}}{\mathop 2Cu}\,+\underset{Air}{\mathop {{O}_{2}}}\,\xrightarrow{Heat}\underset{Black}{\mathop 2CuO}\,\]
Now hydrogen gas is passed from this product. We know that hydrogen is a reducing agent and it is used to reduce the copper oxide. So, when the hydrogen gas is passed over the copper oxide, copper metal is formed. The black-colored copper oxide is changed into brown colored copper metal. The reaction is given below:
$\underset{Black}{\mathop CuO}\,+{{H}_{2}}\to \underset{Brown}{\mathop Cu(s)}\,+{{H}_{2}}O$
So, the powdered copper changes to copper oxide, and then it changes to copper metal.
Note: In this reaction, chemical change and physical change occurs. Chemical change because the reactant is converted into products in both reaction and physical change because of the color changes in both reactions.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

