Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

NCERT Solutions for Class 6 Maths Chapter 3 - Playing with Numbers Exercise 3.3

ffImage

NCERT Solutions for Class 6 Maths 3.3 Exercise Chapter 3 Playing with Numbers - FREE PDF Download

The Class 6 Maths Exercise 3.3 Solutions focuses on prime and composite numbers, helping students understand how to identify and differentiate them. Additionally, it introduces concepts like factors and multiples, which are essential for solving various mathematical problems. Through Class 6 Maths 3.3 Exercise, students learn to apply these concepts, enhancing their problem-solving skills and building a strong foundation in number theory. Students can access The Class 6 Maths NCERT Solutions from our page which is prepared in such a way that you can understand it easily.

toc-symbol
Table of Content
1. NCERT Solutions for Class 6 Maths 3.3 Exercise Chapter 3 Playing with Numbers - FREE PDF Download
2. Glance on NCERT Solutions Maths Chapter 3 Exercise 3.3 Class 6 | Vedantu
3. Access NCERT Solutions for Maths Class 6 Chapter 3 - Playing with Numbers
4. Class 6 Maths Chapter 3: Exercises Breakdown
5. CBSE Class 6 Maths Chapter 3 Other Study Materials
6. Chapter-Specific NCERT Solutions for Class 6 Maths
FAQs


These solutions include shortcut techniques for studying every subject, which not only makes learning interesting but also helps to prepare students for their exams. Also, these solutions are easily available online free of cost in PDF format, which is easily accessible by anyone and from anywhere. Access the Class 6 Maths Syllabus here.


Glance on NCERT Solutions Maths Chapter 3 Exercise 3.3 Class 6 | Vedantu

  • The Class 6 Maths Chapter 3 Exercise 3.3 Solution covers the topic - Tests for Divisibility of Numbers.

  • In Class 6 Maths Exercise 3.3 Solutions the topic - Tests for Divisibility of Numbers is a concept that helps you quickly determine if a number is divisible by another number (like 2, 3, 5, 6, 9, or 11) without performing actual division.

  • Divisibility by 2: The last digit of the number must be even (0, 2, 4, 6, or 8).

  • Divisibility by 3: The sum of all the digits of the number must be divisible by 3.

  • Divisibility by 6: The number must be divisible by both 2 and 3 (i.e., even the last digit and sum of digits are divisible by 3).

  • Divisibility by 9: The sum of all the digits of the number must be divisible by 9 (a stricter rule than divisibility by 3).

  • Divisibility by 11: A divisibility rule based on alternating sum of digits. Add the digits at odd places (from the right) and subtract the sum of digits at even places. If the difference is either 0 or divisible by 11, the number is divisible by 11.

  • Class 6 Maths Exercise 3.3 Solutions contains 6 solved Questions.

Access NCERT Solutions for Maths Class 6 Chapter 3 - Playing with Numbers

Exercise 3.3

1. Using the divisibility test, determine which of the following numbers are divisible by \[\mathrm{2}\]; by \[\mathrm{3}\]; by \[\mathrm{4}\]; by \[\mathrm{5}\]; by \[\mathrm{6}\]; by \[\mathrm{8}\]; by \[\mathrm{9}\]; by \[\mathrm{10}\] ; by \[\mathrm{11}\]. (Say yes or no).

Number

Divisible by 


\[\mathrm{2}\]

\[\mathrm{3}\]

\[\mathrm{4}\]

\[\mathrm{5}\]

\[\mathrm{6}\]

\[\mathrm{8}\]

\[\mathrm{9}\]

\[\mathrm{10}\]

\[\mathrm{11}\]

\[\mathrm{128}\]

Yes

No

Yes

No

No

Yes

No

No

No

\[\mathrm{990}\]










\[\mathrm{1586}\]










\[\mathrm{275}\]










\[\mathrm{6686}\]










\[\mathrm{639210}\]










\[\mathrm{429714}\]










\[\mathrm{2856}\]










\[\mathrm{3060}\]










\[\mathrm{406839}\]










Ans:

Number

Divisible by 


\[\mathrm{2}\]

\[\mathrm{3}\]

\[\mathrm{4}\]

\[\mathrm{5}\]

\[\mathrm{6}\]

\[\mathrm{8}\]

\[\mathrm{9}\]

\[\mathrm{10}\]

\[\mathrm{11}\]

\[\mathrm{128}\]

Yes

No

Yes

No

No

Yes

No

No

No

\[\mathrm{990}\]

Yes

Yes

No

Yes

Yes

No

Yes

Yes

Yes

\[\mathrm{1586}\]

Yes

No

No

No

No

No

No

No

No

\[\mathrm{275}\]

No

No

No

Yes

No

No

No

No

Yes

\[\mathrm{6686}\]

Yes

No

No

No

No

No

No

No

No

\[\mathrm{639210}\]

Yes

Yes

No

Yes

Yes

No

No

Yes

Yes

\[\mathrm{429714}\]

Yes

Yes

No

No

Yes

No

Yes

No

No

\[\mathrm{2856}\]

Yes

Yes

Yes

No

Yes

Yes

No

No

No

\[\mathrm{3060}\]

Yes

Yes

Yes

Yes

Yes

No

Yes

Yes

No

\[\mathrm{406839}\]

No

Yes

No

No

No

No

No

No

No

2. Using the divisibility test, determine which of the following numbers are divisible by \[\mathrm{4}\]; by \[\mathrm{8}\].

(a) \[\mathrm{572}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Not divisible by \[\text{8}\] as its last three digits are not divisible by \[\text{8}\].

(b) \[\mathrm{726352}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Divisible by \[\text{8}\] as its last three digits are divisible by \[\text{8}\].

(c) \[\mathrm{5500}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Not divisible by \[\text{8}\] as its last three digits are not divisible by \[\text{8}\].

(d) \[\mathrm{6000}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Divisible by \[\text{8}\] as its last three digits are divisible by \[\text{8}\].

(e) \[\mathrm{12159}\]

Ans: Not divisible by \[\text{4}\] and \[\text{8}\] as it is an odd number.

(f) \[\mathrm{14560}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Divisible by \[\text{8}\] as its last three digits are divisible by \[\text{8}\].

(g) \[\mathrm{21084}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Not divisible by \[\text{8}\] as its last three digits are not divisible by \[\text{8}\].

(h) \[\mathrm{31795072}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Divisible by \[\text{8}\] as its last three digits are divisible by \[\text{8}\].

(i) \[\mathrm{1700}\]

Ans: Divisible by \[\text{4}\] as its last two digits are divisible by \[\text{4}\].

Not divisible by \[\text{8}\] as its last three digits are not divisible by \[\text{8}\].

(j) \[\mathrm{2150}\]

Ans: Not divisible by \[\text{4}\] as its last two digits are not divisible by \[\text{4}\].

Not divisible by \[\text{8}\] as its last three digits are not divisible by \[\text{8}\].

3. Using the divisibility test, determine which of the following numbers are divisible by \[\mathrm{6}\].

(a) \[\mathrm{297144}\]

Ans: Divisible by \[\text{2}\] as its units place is an even number.

Divisible by \[\text{3}\] as the sum of its digits \[\left( =27 \right)\] is divisible by \[3\].

Since the number is divisible by both \[2\] and \[3\], therefore it is also divisible by \[6\].

(b) \[\mathrm{1258}\]

Ans: Divisible by \[\text{2}\] as its units place is an even number.

Not divisible by \[\text{3}\] as the sum of its digits \[\left( =16 \right)\] is not divisible by \[3\].

Since the number is not divisible by both \[2\] and \[3\], therefore it is not divisible by \[6\].

(c) \[\mathrm{4335}\]

Ans: Not divisible by \[\text{2}\] as its units place is not an even number.

Divisible by \[\text{3}\] as the sum of its digits \[\left( =15 \right)\] is divisible by \[3\].

Since the number is not divisible by both \[2\] and \[3\], therefore it is not divisible by \[6\].

(d) \[\mathrm{61233}\]

Ans: Not divisible by \[\text{2}\] as its units place is not an even number.

Divisible by \[\text{3}\] as sum of its digits \[\left( =15 \right)\] is divisible by \[3\].

Since the number is not divisible by both \[2\] and \[3\], therefore it is not divisible by \[6\].

(e) \[\mathrm{901352}\]

Ans: It is divisible by \[\text{2}\] since its unit place is even number.
Sum of the digits of the given number is \[20\], which is not divisible by \[3\].

Here the number is not divisible by both \[2\] and \[3\], so it is not divisible by \[6\].

(f) \[\mathrm{438750}\]

Ans: It is divisible by \[\text{2}\] since its unit place is even number.
Sum of the digits of the given number is \[27\], which is divisible by \[3\].

Here the number is divisible by both \[2\] and \[3\], so it is divisible by \[6\].

(g) \[\mathrm{1790184}\]

Ans: It is divisible by \[\text{2}\] since its unit place is even number.
Sum of the digits of the given number is \[30\], which is divisible by \[3\].

Here the number is divisible by both \[2\] and \[3\], so it is divisible by \[6\].

(h) \[\mathrm{12583}\]

Ans: It is not divisible by \[\text{2}\] since its unit place is not an even number.
Here the number is not divisible by both \[2\] and \[3\], so it is not divisible by \[6\].

(i) \[\mathrm{639210}\]

Ans: It is divisible by \[\text{2}\] since its unit place is even number.
Sum of the digits of the given number is \[21\], which is divisible by \[3\].

Here the number is divisible by both \[2\] and \[3\], so it is divisible by \[6\].

(j) \[\mathrm{17850}\]

Ans: It is divisible by \[\text{2}\] since its unit place is even number.
Sum of the digits of the given number is \[23\], which is not divisible by \[3\].

Here the number is not divisible by both \[2\] and \[3\], so it is not divisible by \[6\].

4. Using the divisibility test, determine which of the following numbers are divisible by \[\mathrm{11}\].

(a) \[\mathrm{5445}\]

Ans:

Odd places sum\[\text{=4+5=9}\]

Even places sum \[\text{=4+5=9}\]

Difference \[\text{=9-9}\]

Though the difference is \[0\], the number is divisible by \[11\].

(b) \[\mathrm{10824}\]

Ans:

Odd places sum\[\text{=1+8+4=13}\]

Even places sum \[\text{=0+2=2}\]

Difference \[\text{=13-2=11}\]

Though the difference is \[11\], the number is divisible by \[11\].

(c) \[\mathrm{7138965}\]

Ans: Odd places sum\[\text{=7+3+9+5=24}\]

Even places sum \[\text{=6+8+1=15}\]

Difference \[\text{=24-15=9}\]

Though the difference is \[9\], the number is not divisible by \[11\].

(d) \[\mathrm{70169308}\]

Ans: Odd places sum\[\text{=8+3+6+0=17}\]

Even places sum \[\text{=6+8+1=15}\]

Difference \[\text{=17-15=2}\]

Though the difference is \[2\], the number is not divisible by \[11\].

(e) \[\mathrm{10000001}\]

Ans: Odd places sum\[\text{=1+0+0+0=1}\]

Even places sum \[\text{=0+0+0+1=1}\]

Difference \[\text{=1-1=0}\]

Though the difference is \[0\], the number is divisible by \[11\].

(f) \[\mathrm{901153}\]

Ans: Odd places sum\[\text{=9+1+5=15}\]

Even places sum \[\text{=3+1+0=4}\]

Difference \[\text{=15-4=11}\]

Though the difference is \[11\], the number is divisible by \[11\].

5. Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisible by \[\mathrm{3}\].

(a) \[........\mathrm{6724}\]

Ans: To get divisible by \[\text{3}\] the sum of the digits should be divisible by \[\text{3}\].

So, the sum of the digits of the given number is \[\text{6+7+2+4=19}\].

So, the least digit will be \[\text{2 }\left( 19+2=21 \right)\] and largest digit will be \[8\text{ }\left( 19+8=27 \right)\].

(b) \[\mathrm{4765 }\!\!\_\!\!\text{ 2}\]

Ans: To get divisible by \[\text{3}\] the sum of the digits should be divisible by \[\text{3}\].

So, the sum of the digits of the given number is \[\text{4+7+6+5+2=24}\].

So, the least digit will be \[\text{0 }\left( 24 \right)\] and the largest digit will be \[\text{9 }\left( 24+9=33 \right)\].

6. Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisible by \[\mathrm{11}\].

(a) \[\mathrm{92 }\!\!\_\!\!\text{ 389}\]

Ans: To get divisible by \[11\] ,the difference between the sum of digits in odd places and even places should be \[0\] or \[11\].

Odd places: \[9+8+8=25\]

Even places: \[2+3+9=14\]

Difference: \[25-14=11\]

Therefore \[8\] is the largest and smallest digit.

(b) \[\mathrm{8 }\!\!\_\!\!\text{ 9484}\]

Ans: To get divisible by \[11\] ,the difference between the sum of digits in odd places and even places should be \[0\] or \[11\].

Odd places: \[8+9+8=25\]

Even places: \[6+4+4=14\]

Difference: \[25-14=11\]

Therefore \[6\] is the largest and smallest digit.


Conclusion

In conclusion, the class 6 maths exercise 3.3 provides valuable insights into the tests for the divisibility of numbers. By understanding these rules, students can efficiently determine whether a number is divisible by another without performing lengthy division. This knowledge not only simplifies calculations but also strengthens their understanding of number properties. The skills gained from exercise 3.3 class 6 maths are essential for tackling more complex mathematical problems in higher grades, making it a crucial part of their math education.


Class 6 Maths Chapter 3: Exercises Breakdown

Exercise

Number of Questions

Exercise 3.1

4 Questions & Solutions

Exercise 3.2

12 Questions & Solutions

Exercise 3.4

7 Questions & Solutions

Exercise 3.5

10 Questions & Solutions

Exercise 3.6

3 Questions & Solutions

Exercise 3.7

11 Questions & Solutions


CBSE Class 6 Maths Chapter 3 Other Study Materials


Chapter-Specific NCERT Solutions for Class 6 Maths

Given below are the chapter-wise NCERT Solutions for Class 6 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.


FAQs on NCERT Solutions for Class 6 Maths Chapter 3 - Playing with Numbers Exercise 3.3

1. What is playing with numbers in the class 6 maths 3.3 exercise?

Chapter 3 of NCERT Solutions for Class 6 Maths "Playing With...

Students are taught about multiples and divisors in particular in the third chapter of the maths syllabus, Playing with Numbers. Students learn about common factors and multiples, divisibility laws, highest and lowest common factors, and other related topics as the chapter goes on.

2. What is the name of Chapter 3 of Maths Class 6?

Chapter 3 of the class 6 maths syllabus is on 'Knowing Our Numbers'. This is a very important chapter in class 6 that develops a student's number sense.

3. What is the definition of playing with numbers?

During our time in exercise 3.3 class 6 maths we learned the definition of Playing with numbers and it entails tasks like sorting them into groups, comprehending the BODMAS rule, determining if a particular number is a multiple of another number or a factor of another number, and being aware of the characteristics of multiples and factors.

4. What are the properties of playing with numbers in class 6 maths exercise 3.3 solutions?

Property 1: A two-digit number's total multiplied by its reverse is always greater than 11. Property 2: A two-digit number's difference from its reverse is always greater than or equal to nine. Property 3: A three-digit number's difference from its reverse is always a multiple of 99.

5. What is the rule for divisibility by 2 in Class 6 Exercise 3.3?

A number is divisible by 2 if its last digit is even (0, 2, 4, 6, or 8).

6. How can you tell if a number is divisible by 3 in Class 6 Exercise 3.3? 

A number is divisible by 3 if the sum of its digits is divisible by 3.

7. What is the rule for divisibility by 4 in Class 6 Exercise 3.3? 

A number is divisible by 4 if the last two digits form a number that is divisible by 4.

8. How can you check if a number is divisible by 5 in Class 6 Maths Ex 3.3? 

A number is divisible by 5 if its last digit is either 0 or 5.

9. What is the divisibility rule for 6 in Class 6 Ex 3.3?

A number is divisible by 6 if it is divisible by both 2 and 3.

10. How do you determine if a number is divisible by 8 Class 6 Maths Chapter 3.3 Exercise? 

A number is divisible by 8 if the last three digits form a number that is divisible by 8.

11. What is the rule for divisibility by 9 in Class 6 Maths Ex 3.3? 

A number is divisible by 9 if the sum of its digits is divisible by 9.

12. How can you check if a number is divisible by 10 in Class 6 Ex 3.3? 

A number is divisible by 10 if its last digit is 0.

13. What is the divisibility rule for 11 in Class 6 Maths Chapter 3 Exercise 3.3 Solution? 

A number is divisible by 11 if the difference between the sum of the digits in the odd positions and the sum of the digits in the even positions is either 0 or a multiple of 11.

14. Why are divisibility rules important in Class 6 Maths Chapter 3.3 Exercise? 

As we studied in exercise 3.3 class 6th, Divisibility rules are important because they allow us to quickly and easily determine if a number is divisible by another without performing long division. This helps in simplifying calculations and solving various mathematical problems efficiently.