NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line - FREE PDF Download
FAQs on NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
1. Where can I find the complete, step-by-step NCERT Solutions for Class 11 Physics Chapter 2 for the 2025-26 session?
You can find the complete and detailed NCERT Solutions for Class 11 Physics Chapter 2, Motion in a Straight Line, on this page. The solutions are prepared by subject matter experts and are fully updated for the CBSE 2025-26 academic session, covering every exercise question from the textbook.
2. What key topics are covered in the NCERT Solutions for Class 11 Physics Chapter 2?
The NCERT Solutions for Class 11 Physics Chapter 2 cover all essential concepts of motion in one dimension. Key topics include:
- The concepts of path length (distance) and displacement.
- Definitions and differences between average speed and average velocity.
- Instantaneous velocity and acceleration.
- Uniformly accelerated motion and the three kinematic equations.
- Solving problems using position-time (x-t) and velocity-time (v-t) graphs.
3. Are these NCERT Solutions for Chapter 2 updated for the latest CBSE 2025-26 syllabus?
Yes, all solutions provided for Class 11 Physics Chapter 2 are meticulously aligned with the latest CBSE syllabus for the 2025-26 academic year. Any topics that have been rationalised or removed from the NCERT textbook are not included, ensuring you study only what is relevant for your exams.
4. How do these NCERT solutions explain the difference between distance and displacement with examples?
The solutions clearly explain that distance is the total path length covered and is a scalar quantity, while displacement is the shortest straight-line path between the initial and final points and is a vector. This is illustrated with solved numericals, such as a person walking to a market and returning, where the displacement is zero but the distance covered is significant.
5. What are the three main kinematic equations for uniformly accelerated motion applied in these solutions?
The solutions for Chapter 2 extensively use the three fundamental kinematic equations for objects moving with constant acceleration:
- v = u + at (Velocity-Time Relation)
- s = ut + ½ at² (Position-Time Relation)
- v² = u² + 2as (Position-Velocity Relation)
Each equation's application is demonstrated through step-by-step solutions to textbook problems.
6. Why is it important to follow the step-by-step method shown in the NCERT Solutions for solving numerical problems in exams?
Following the step-by-step method is crucial because it aligns with the CBSE marking scheme. Writing down the given data, the formula used, substituting values correctly, and stating the final answer with units ensures you get full marks. This structured approach also minimises calculation errors and clearly demonstrates your understanding of the concept.
7. How do the NCERT Solutions for Chapter 2 clarify common misconceptions, like the sign of acceleration and velocity?
The solutions clarify that the sign of velocity and acceleration depends on the chosen coordinate system. A key misconception addressed is that positive acceleration always means 'speeding up'. The solutions explain with examples that if an object has negative velocity, a positive acceleration will cause it to slow down first, demonstrating that the signs must be considered together.
8. In the NCERT Solutions, how is the case of an object with zero velocity but non-zero acceleration explained?
The solutions explain this classic physics concept using the example of a ball thrown vertically upwards. At its highest point, the instantaneous velocity of the ball is zero for a moment. However, the acceleration due to gravity (g ≈ 9.8 m/s²) is still acting on it, pulling it downwards. This proves that zero velocity does not imply zero acceleration.
9. How do the solved examples for graph-based questions in these NCERT Solutions help in building conceptual clarity?
The graph-based solutions are critical as they help visualise motion. They teach you how to interpret the slope of a position-time graph as velocity and the slope of a velocity-time graph as acceleration. By solving problems that involve plotting and reading graphs, you build a deeper, more intuitive understanding of motion that goes beyond just using formulas.
10. Why do the solutions often distinguish between average speed and the magnitude of average velocity?
The solutions emphasize this distinction to prevent common errors. Average speed is the total path length divided by time, which is always positive. The magnitude of average velocity is the magnitude of displacement divided by time. For a round trip where you return to the start, displacement is zero, making average velocity zero, but average speed is positive. This distinction is vital for accurately describing motion.

















