
The atmospheric pressure and height of the barometer column is \[{10^5}\,Pa\] and $760\,mm$ respectively on the earth surface. If the barometer is taken to the moon, then what will be the column height?
A. zero
B. $76\,mm$
C. $126.6\,mm$
D. $760\,mm$
Answer
148.8k+ views
Hint: We know pressure in a barometer on earth is given by the formula
$p = \rho gh$
Where $\rho $ is the density.
$g$ is the acceleration due to gravity.
$h$ is the height of the column.
On earth the pressure is due to the presence of atmosphere. The reading that we get in the barometer corresponds to the atmospheric pressure
But on the moon there is no air or atmosphere.
Complete step by step answer:
A barometer is an instrument used to measure atmospheric pressure. Atmosphere is a layer of air surrounding the earth. This pressure tendency measured using a barometer can be used to forecast short term changes in the weather.
Given,
Atmospheric pressure on earth surface =${10^5}\,Pa$
The height of barometer on earth surface =$760\,mm$
We need to find column height on the moon.
We know pressure in a barometer on earth is given by the formula
$p = \rho gh$
Where $\rho $ is the density.
$g$ is the acceleration due to gravity.
$h$ is the height of the column.
On earth the pressure is due to the presence of the atmosphere. The reading that we get in the barometer corresponds to the atmospheric pressure.
But on the moon there is no atmosphere. So, there will be no atmospheric pressure
Thus pressure, $p = 0$.
That is, $\rho gh = 0$
$ \Rightarrow \,h = 0$
So, the height of the column will be zero on the moon.
Note: If there was atmosphere on moon(just in case) then we would have to calculate the gravity on moon, on moon gravity is less than that on earth, hence it would take more height than 760mm of Hg to record the same pressure.
$p = \rho gh$
Where $\rho $ is the density.
$g$ is the acceleration due to gravity.
$h$ is the height of the column.
On earth the pressure is due to the presence of atmosphere. The reading that we get in the barometer corresponds to the atmospheric pressure
But on the moon there is no air or atmosphere.
Complete step by step answer:
A barometer is an instrument used to measure atmospheric pressure. Atmosphere is a layer of air surrounding the earth. This pressure tendency measured using a barometer can be used to forecast short term changes in the weather.
Given,
Atmospheric pressure on earth surface =${10^5}\,Pa$
The height of barometer on earth surface =$760\,mm$
We need to find column height on the moon.
We know pressure in a barometer on earth is given by the formula
$p = \rho gh$
Where $\rho $ is the density.
$g$ is the acceleration due to gravity.
$h$ is the height of the column.
On earth the pressure is due to the presence of the atmosphere. The reading that we get in the barometer corresponds to the atmospheric pressure.
But on the moon there is no atmosphere. So, there will be no atmospheric pressure
Thus pressure, $p = 0$.
That is, $\rho gh = 0$
$ \Rightarrow \,h = 0$
So, the height of the column will be zero on the moon.
Note: If there was atmosphere on moon(just in case) then we would have to calculate the gravity on moon, on moon gravity is less than that on earth, hence it would take more height than 760mm of Hg to record the same pressure.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Uniform Acceleration

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry
