

Conditions for Equilibrium of Concurrent Forces with Solved Examples
Equilibrium of Concurrent Forces is a key JEE Main concept describing the state when several forces meet at a point and keep a body at rest or constant velocity. Mastering these principles, including vector sum, equations, and conditions for concurrent force systems, is essential for solving physics problems efficiently. Questions on equilibrium, systematic force resolution, and typical misconceptions about Lami’s theorem are frequent in competitive exams. Vedantu’s well-structured resources give aspirants a strong grasp on these ideas, helping boost both conceptual clarity and accurate application.
The core idea of equilibrium of concurrent forces: if all forces acting at one point add vectorially to zero, the net force is zero and there’s neither acceleration nor change in velocity. For example, when three strings pull at a knot with equal but opposing forces, the knot stays stationary. This balance is known as force equilibrium—a critical part of laws of motion and a foundation in mechanics.
Equilibrium of Concurrent Forces: Definition, Formula, and Vector Conditions
In mechanics, equilibrium of concurrent forces means that multiple forces—regardless of their number—act through the same point and together create no resultant force. The following conditions must be strictly satisfied for equilibrium:
- The vector sum of all forces at the point is exactly zero.
- Net acceleration is zero, so the body is at rest or moves at constant speed.
- Each force can be broken into x, y (and sometimes z) components; the sum of each component direction is zero.
For a typical JEE Main system in 2D, if forces F1, F2, and F3 act at a point:
- ΣF = 0 (vector sum is zero)
- ΣFx = 0 (sum of all x-components is zero)
- ΣFy = 0 (sum of all y-components is zero)
If forces are coplanar and in 3D, also add ΣFz = 0. The most succinct mathematical expression is:
- ΣFx = 0
- ΣFy = 0
- ΣFz = 0 (if acts in 3D)
When dealing with JEE numerical problems, resolving each force into components and systematically applying these conditions removes ambiguity and prevents common sign mistakes. For deeper treatment, review the sections on vector addition and resolution of forces.
Lami’s Theorem and Equilibrium of Three Concurrent Forces
Lami’s theorem is widely used in JEE to analyze the equilibrium of three concurrent, non-parallel forces acting on a particle. It states:
- If a particle is in equilibrium under three coplanar forces, each force is proportional to the sine of the angle between the other two forces.
Expressed mathematically (for forces F1, F2, F3, angles α, β, γ) :
- F1 / sin α = F2 / sin β = F3 / sin γ
Here, angle α is between F2 and F3, and so on. This theorem helps quickly solve for any unknown force when the other two and all angles are given.
- Always ensure the angles used are correctly identified as the angles between the forces, not with respect to axes.
- Lami’s theorem only applies when exactly three forces are acting and all are coplanar and concurrent.
For further mastery, use laws of motion, try the laws of motion practice paper, and see detailed types of equilibrium in JEE.
Worked Example: Checking Equilibrium in a Concurrent Force System
Suppose three forces act on a point: F1 = 40 N along x-axis, F2 = 30 N along the y-axis, and F3 at 225° to the positive x-axis. Find F3 that balances this system.
- Break all forces into x and y components.
- Set up ΣFx = 0 : 40 + F3 cos 225° = 0
- Set up ΣFy = 0 : 30 + F3 sin 225° = 0
- Solve for F3 using cos(225°) = -0.707, sin(225°) = -0.707
- So 40 - 0.707 F3 = 0 ⇒ F3 = 56.6 N
- Check y: 30 - 0.707 F3 = 0 ⇒ also yields F3 = 42.4 N (contradiction means error; actual force required should balance both components, typically with correct axes choice or additional data)
Concurrent vs. Non-Concurrent Forces in Equilibrium: Key Differences
Feature | Concurrent Forces | Non-Concurrent Forces |
---|---|---|
Point of Intersection | All act through a common point | Act at different points |
Equilibrium Condition | ΣF = 0 suffices | Both ΣF = 0 and ΣM = 0 needed |
Moment Balance | Not required | Mandatory |
JEE Focus | Common in single-particle equilibrium | Relevant in rigid body problems |
For more on non-concurrent systems, visit torque and equilibrium and types of equilibrium.
Practical Applications and Mistakes in Equilibrium of Concurrent Forces
- Hanging signs or weights suspended by cables (forces add to zero at knot)
- Physics lab setups with pulleys and force tables
- Engineering: bridge cable tensions at a joint in static equilibrium
- Crane hooks and wire tensions in machines
- Common mistakes: mislabeling force directions, using wrong sign conventions, confusing component angles, and applying Lami’s theorem when more than three forces act.
- Always sketch a diagram and resolve forces systematically for each axis.
For strong practice, try the laws of motion mock test and review kinematics revision notes.
With focused study and repeated problem-solving, the equilibrium of concurrent forces becomes a manageable and high-scoring topic. Use Vedantu for precise doubt resolution and smart practice aligned to the latest JEE standards.
FAQs on Equilibrium of Concurrent Forces Explained
1. What is equilibrium of concurrent forces?
Equilibrium of concurrent forces means all forces acting at a single point produce zero net force, so the body remains at rest or moves with constant velocity.
Key points:
- Forces meet at a common point (are concurrent)
- Vector sum of all forces is zero: ΣF = 0
- No net effect, so object is in mechanical equilibrium
2. When are three concurrent forces in equilibrium?
Three concurrent forces are in equilibrium if their vector sum is zero and they can be represented as the sides of a closed triangle taken in order.
Conditions for equilibrium:
- The magnitude and direction must satisfy F1 + F2 + F3 = 0
- They can be drawn tip to tail to form a triangle (triangle law)
- Lami’s theorem applies if all three are non-parallel and act at the same point
3. What is the equilibrium equation for a concurrent force system?
The equilibrium equation for a concurrent force system states that the vector sum of all concurrent forces is zero.
Mathematically:
- ΣFx = 0: Sum of all force components along x-axis is zero
- ΣFy = 0: Sum of all force components along y-axis is zero
4. What is Lami’s theorem and how is it applied to equilibrium of concurrent forces?
Lami’s theorem relates the magnitudes of three concurrent, coplanar forces in equilibrium with the angles between them.
Statement:
- "If three concurrent, coplanar forces keep a body in equilibrium, then each force is proportional to the sine of the angle between the other two."
It is used to solve force magnitude problems in JEE/NEET exam questions.
5. How do you check the equilibrium of a concurrent force system?
To check equilibrium of a concurrent force system, resolve all forces into x and y components and verify that their algebraic sums are zero.
Steps:
- Draw a vector diagram of forces at the point
- Resolve each force into its horizontal and vertical components
- Add up all x-components (ΣFx) and y-components (ΣFy)
- If both sums are zero: the system is in equilibrium
6. What is the difference between concurrent and non-concurrent forces?
Concurrent forces act at the same point, while non-concurrent forces act through different points.
Comparison:
- Concurrent forces: All lines of action meet at a single point (often exam problems on force equilibrium)
- Non-concurrent forces: Lines of action do not intersect at a single point; moments about a point must be considered
7. What is the formula for equilibrium of concurrent forces?
The formula for equilibrium of concurrent forces requires the sum of all force vectors at a point to be zero.
Equilibrium conditions:
- ΣF = 0 (resultant force must be zero)
- ΣFx = 0 (sum of x-components)
- ΣFy = 0 (sum of y-components)
8. Is equilibrium possible for more than three concurrent forces?
Yes, equilibrium is possible for any number of concurrent forces, provided their vector sum is zero.
Steps:
- Resolve all forces into components
- Sum all x and y (and z, if in 3D) components
- If all sums are zero, the system is in equilibrium
9. What are the steps to solve equilibrium of concurrent forces numericals?
To solve equilibrium numericals for concurrent forces:
- Draw a clear force diagram, labelling all forces with magnitudes and directions
- Resolve each force into horizontal and vertical components using trigonometry
- Write equilibrium equations: ΣFx = 0 and ΣFy = 0
- Solve the equations to find unknowns (force, angle, etc.)
- Double check unit consistency and vector directions
10. What are some real-life examples of equilibrium of concurrent forces?
Examples of equilibrium of concurrent forces can be found in daily life and engineering.
Common examples:
- A traffic signal hanging by cables (three forces at the joint)
- Weight suspended by two ropes at angles
- Forces acting at a nail holding a picture on a wall
- Ring support in labs for force verification experiments
11. Can concurrent forces be in equilibrium if their lines of action do not pass through the same point?
No, concurrent force equilibrium requires that all lines of action pass through a single common point.
If lines of action do not intersect at the same point, the forces are non-concurrent and require additional moment (torque) analysis for equilibrium. Always ensure concurrency for applying these specific force balance equations.
12. Are the equations of equilibrium the same in two and three dimensions?
While the principle remains the same, in three dimensions you must balance components in all three axes.
In 2D:
- ΣFx = 0
- ΣFy = 0
- ΣFx = 0
- ΣFy = 0
- ΣFz = 0
13. What mistakes occur when resolving forces into components for equilibrium problems?
Common mistakes include incorrect angles or wrong assignment of signs to force components.
Watch out for:
- Mixing up sine and cosine depending on the reference angle
- Missing negative signs for direction
- Not breaking all forces into orthogonal axes

















