Answer
Verified
114.6k+ views
Hint: In order to solve this question you have to know the concept of pulley and tension in thread. A pulley is a simple machine that redirects force. Tension is the force that is transmitted through a string, rope, cable, or wire when it is pulled tight by forces acting from opposite ends.
Complete step by step solution:
In this question it is given that ${M_1} > {M_2}$, so the tension in the string connecting the block and surface is given by
${T_{BC}} = ({M_1} - {M_2})g$
It is also given in the question that the string BC is burnt, then this tension disappears and the tension in the spring becomes
${T_s} = {M_1}g$
The spring also gets elongated.
Now, the tension in the string connected to A and B is given by
${T_{AB}} = {M_1}g$
Hence, the resultant force on A becomes zero because the tension in string is balanced by spring tension.
Hence, the net force exerted on the block B which is upward in direction is given by
${F_B} = ({M_1} - {M_2})g$
So, the initial acceleration of the block B is given by
${u_B} = \dfrac{{({M_1} - {M_2})}}{{{M_2}}}g$
Thus, the initial acceleration of mass ${M_1}$ is zero
And the initial acceleration of mass ${M_2}$ is $\dfrac{{({M_1} - {M_2})}}{{{M_2}}}g$ and the direction is upward.
Thus, the correct option is (D).
Note: While solving questions like this we should always draw a free body diagram (FBD) to show the forces exerted on the body. Also, you have to make some assumptions while writing equations that the string is taut and inextensible at each and every point of time, the pulley is massless, and also the string is massless.
Complete step by step solution:
In this question it is given that ${M_1} > {M_2}$, so the tension in the string connecting the block and surface is given by
${T_{BC}} = ({M_1} - {M_2})g$
It is also given in the question that the string BC is burnt, then this tension disappears and the tension in the spring becomes
${T_s} = {M_1}g$
The spring also gets elongated.
Now, the tension in the string connected to A and B is given by
${T_{AB}} = {M_1}g$
Hence, the resultant force on A becomes zero because the tension in string is balanced by spring tension.
Hence, the net force exerted on the block B which is upward in direction is given by
${F_B} = ({M_1} - {M_2})g$
So, the initial acceleration of the block B is given by
${u_B} = \dfrac{{({M_1} - {M_2})}}{{{M_2}}}g$
Thus, the initial acceleration of mass ${M_1}$ is zero
And the initial acceleration of mass ${M_2}$ is $\dfrac{{({M_1} - {M_2})}}{{{M_2}}}g$ and the direction is upward.
Thus, the correct option is (D).
Note: While solving questions like this we should always draw a free body diagram (FBD) to show the forces exerted on the body. Also, you have to make some assumptions while writing equations that the string is taut and inextensible at each and every point of time, the pulley is massless, and also the string is massless.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key
JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key
Hybridization of Atomic Orbitals Important Concepts and Tips for JEE
Atomic Structure: Complete Explanation for JEE Main 2025
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
Class 11 JEE Main Physics Mock Test 2025
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
JEE Main Login 2045: Step-by-Step Instructions and Details
Degree of Dissociation and Its Formula With Solved Example for JEE
Other Pages
NCERT Solutions for Class 11 Physics Chapter 7 Gravitation
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes - CBSE Physics Chapter 1
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs