
In a series LCR circuit connected to an ac source of variable frequency and voltage $v = {v_m}\sin \omega t$ , draw a plot showing the variation of current $(I)$ with angular frequency $(\omega )$ for two different values of resistance ${R_1}$ and ${R_2}$ $({R_1} > {R_2})$ , Write the condition under which the phenomenon of resonance occurs. For which value of the resistance out of the two curves a sharper resonance is produced? Define Q-factor of the circuit and give its significance.
Answer
232.8k+ views
Hint: In order to solve this question one should be aware of the concept of resonance and the conditions of resonance in an LCR circuit. The condition of the resonance depends on a particular frequency, also known as resonance frequency. When the frequency of the LCR is equal to the resonance frequency only then the condition of resonance is attained.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Recently Updated Pages
JEE Main 2026 Session 2 Registration Open, Exam Dates, Syllabus & Eligibility

JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Why does capacitor block DC and allow AC class 12 physics JEE_Main

Understanding Average and RMS Value in Electrical Circuits

Understanding Collisions: Types and Examples for Students

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

CBSE Class 12 Physics Set 2 (55/2/2) 2025 Question Paper & Solutions

Inductive Effect and Its Role in Acidic Strength

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Units and Measurements Mock Test for JEE Main 2025-26 Preparation

Chemistry Question Papers for JEE Main, NEET & Boards (PDFs)

