
In a series LCR circuit connected to an ac source of variable frequency and voltage $v = {v_m}\sin \omega t$ , draw a plot showing the variation of current $(I)$ with angular frequency $(\omega )$ for two different values of resistance ${R_1}$ and ${R_2}$ $({R_1} > {R_2})$ , Write the condition under which the phenomenon of resonance occurs. For which value of the resistance out of the two curves a sharper resonance is produced? Define Q-factor of the circuit and give its significance.
Answer
174k+ views
Hint: In order to solve this question one should be aware of the concept of resonance and the conditions of resonance in an LCR circuit. The condition of the resonance depends on a particular frequency, also known as resonance frequency. When the frequency of the LCR is equal to the resonance frequency only then the condition of resonance is attained.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Recently Updated Pages
JEE Main 2025-26 Atoms and Nuclei Mock Test: Free Practice Online

JEE Main 2025-26: Dual Nature of Matter and Radiation Mock Test

JEE Main 2025-26 Electronic Devices Mock Test – Free Practice

JEE Main Mock Test 2025-26: Experimental Skills Chapter Online Practice

JEE Main 2025-26 Current Electricity Mock Test: Free Practice Online

JEE Main 2025-26 Rotational Motion Mock Test – Free Practice Online

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Displacement-Time Graph and Velocity-Time Graph for JEE

Uniform Acceleration

Electric field due to uniformly charged sphere class 12 physics JEE_Main

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Instantaneous Velocity - Formula based Examples for JEE

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Essential Derivations for CBSE Class 12 Physics: Stepwise & PDF Solutions

Electron Gain Enthalpy and Electron Affinity for JEE

Wheatstone Bridge for JEE Main Physics 2025
