Answer
Verified
114.6k+ views
Hint We know that if we have to find the correct thickness of an object then we will have to add or subtract the zero error in the measured value.
We can formulate it as follows:
Actual reading \[{\text{ = }}\]Observed reading \[{\text{ - }}\]Excess reading (zero error)
Complete step by step answer
Given:
Observed reading: 1.4 mm
Excess reading (zero error): +0.02 cm (here the positive sign indicates positive zero error) i.e., 0.2 mm
To find:
Actual reading: _______
Here, we will use the formula,
Actual reading \[{\text{ = }}\]Observed reading \[{\text{ - }}\]Excess reading (zero error)
\[ \Rightarrow \]actual reading 1.4 – 0.2
\[ \Rightarrow \]actual reading = 1.2 mm
Hence, the correct answer is option (b.).
Note It is important to convert the values into the same units. As you can see in the above solution, the units of zero error and measured value were different. In this case we cannot apply any operation on them. Also, the zero error can be both positive and negative, so one needs to be careful while substituting the values in the formula. As the formula also contains a minus sign.
We can formulate it as follows:
Actual reading \[{\text{ = }}\]Observed reading \[{\text{ - }}\]Excess reading (zero error)
Complete step by step answer
Given:
Observed reading: 1.4 mm
Excess reading (zero error): +0.02 cm (here the positive sign indicates positive zero error) i.e., 0.2 mm
To find:
Actual reading: _______
Here, we will use the formula,
Actual reading \[{\text{ = }}\]Observed reading \[{\text{ - }}\]Excess reading (zero error)
\[ \Rightarrow \]actual reading 1.4 – 0.2
\[ \Rightarrow \]actual reading = 1.2 mm
Hence, the correct answer is option (b.).
Note It is important to convert the values into the same units. As you can see in the above solution, the units of zero error and measured value were different. In this case we cannot apply any operation on them. Also, the zero error can be both positive and negative, so one needs to be careful while substituting the values in the formula. As the formula also contains a minus sign.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key
JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key
JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key
Hybridization of Atomic Orbitals Important Concepts and Tips for JEE
Atomic Structure: Complete Explanation for JEE Main 2025
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
Class 11 JEE Main Physics Mock Test 2025
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
JEE Main Login 2045: Step-by-Step Instructions and Details
Degree of Dissociation and Its Formula With Solved Example for JEE
Other Pages
NCERT Solutions for Class 11 Physics Chapter 7 Gravitation
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes - CBSE Physics Chapter 1
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs