Summary of HC Verma Solutions Part 2 Chapter 37: Magnetic Properties of Magnet
FAQs on HC Verma Solutions Class 12 Chapter 37 - Magnetic Properties of Matter
1. Where can I find clear, step-by-step solutions for all questions in HC Verma's Class 12 Physics Chapter 37, 'Magnetic Properties of Matter'?
Vedantu provides comprehensive, step-by-step solutions for all exercises in HC Verma's 'Magnetic Properties of Matter', Chapter 37. Each solution is prepared by subject matter experts to ensure accuracy and alignment with the problem-solving methods required for the CBSE 2025-26 board exams and competitive exams like JEE.
2. What is the correct method to solve problems related to magnetic susceptibility and permeability from HC Verma Chapter 37?
To correctly solve problems on magnetic susceptibility (χ) and permeability (μ) from this chapter, you should follow these steps:
- First, carefully identify all the given parameters, such as magnetic intensity (H), magnetisation (M), or the magnetic field (B).
- Recall the key relationships: B = μ₀(H + M) and M = χH.
- Use these to find the connection between relative permeability (μᵣ) and susceptibility, which is μᵣ = 1 + χ.
- Ensure you substitute all values using consistent SI units to arrive at the correct answer.
3. Why do diamagnetic materials have negative magnetic susceptibility, and how is this concept tested in HC Verma problems?
Diamagnetic materials have a negative magnetic susceptibility (χ) because when placed in an external magnetic field, the induced magnetic moment in them opposes the external field. This results in weak repulsion. In HC Verma problems, this concept is often tested by requiring you to:
- Identify a material as diamagnetic based on a given negative value of χ.
- Calculate the net magnetic field inside the material, which will be slightly weaker than the external field.
- Differentiate the behaviour of diamagnetic, paramagnetic, and ferromagnetic materials in a uniform magnetic field.
4. How do the concepts of retentivity and coercivity, as explained in Chapter 37, help determine if a material is suitable for a permanent magnet or an electromagnet?
The suitability of a material is determined by its properties on the hysteresis loop:
- Permanent Magnets: These require materials with high retentivity to remain strongly magnetised and high coercivity to resist demagnetisation from external fields. Steel is a classic example.
- Electromagnets: These need materials with low retentivity and low coercivity. This allows them to be easily and quickly magnetised and demagnetised by controlling the electric current. Soft iron is the ideal choice for this application.
HC Verma solutions often feature problems where you must interpret a hysteresis curve to make these distinctions.
5. How do you calculate the intensity of magnetisation (M) for a solenoid with a magnetic core in HC Verma Chapter 37 exercises?
To calculate the intensity of magnetisation (M) for a magnetic core inside a solenoid, follow this procedure:
- First, determine the magnetic intensity (H) generated by the solenoid current using the formula H = nI, where 'n' is the number of turns per unit length and 'I' is the current.
- Next, use the magnetic susceptibility (χ) of the core material in the relationship M = χH.
- If the total magnetic field (B) inside the core is provided instead, you can find M by first calculating H and then rearranging the formula B = μ₀(H + M).
6. What is a key difference in the approach to problems on magnetic properties in HC Verma compared to the NCERT textbook?
While both textbooks cover the same core topics for the Class 12 syllabus, HC Verma problems generally demand a deeper conceptual application and stronger analytical skills. NCERT focuses on establishing a solid foundation, whereas HC Verma exercises are structured to enhance problem-solving prowess for competitive exams like JEE and NEET. Consequently, HC Verma problems often feature more complex scenarios that require multi-step derivations and a nuanced understanding of how different magnetic properties interact.
7. Why is understanding the classification of magnetic materials (dia-, para-, ferro-) essential for solving problems in this chapter correctly?
Understanding the classification is critical because the material type dictates which physical laws and mathematical formulas to apply. Each class has distinct properties:
- Diamagnetic: Susceptibility (χ) is small and negative.
- Paramagnetic: Susceptibility (χ) is small and positive.
- Ferromagnetic: Susceptibility (χ) is large and positive, and concepts like hysteresis and saturation are relevant.
Using the wrong assumptions for a material type, for example, ignoring hysteresis for a ferromagnetic material, will lead to an incorrect solution.
8. What is the best strategy to use Vedantu's HC Verma solutions for Chapter 37 to maximise learning?
For the most effective preparation, you should first attempt to solve the Chapter 37 exercises independently. Then, refer to Vedantu's solutions to:
- Verify if your answer and method are correct.
- Understand the most efficient, step-by-step approach for complex problems.
- Clarify how to apply key formulas for magnetisation, susceptibility, and permeability in different contexts.
- Resolve any conceptual doubts that arise during problem-solving, which is vital for both board exams and competitive tests.











