Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

RS Aggarwal Class 11 Solutions Chapter-11 Arithmetic Progression

ffImage
banner

Class 11 RS Aggarwal Chapter-11 Arithmetic Progression Solutions - Free PDF Download

CBSE students who are preparing for their Class 11th examination can take reference from arithmetic progression Class 11 RS Aggarwal. This book is phenomenal for its study materials that help students to understand every topic with clarity. A chapter-wise solution is outlined in the textbooks which makes the concept easy and intriguing. It is the right tool for students to overcome the difficulty section in the chapter.

Competitive Exams after 12th Science
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow
tp-imag
bottom-arrow

RS Aggarwal Class 11 Maths Chapter 11 Solutions Arithmetic Progression

Progression is a term used to describe a succession whose terms follow particular patterns. Arithmetic Progression in RS Aggarwal Solutions Class 11 Maths Chapter 11 is an important chapter. It is a sequence of numbers in which the preceding term adds a constant quantity to form the consequent term. It states that the difference between the preceding term and the consequent term is a constant quantity. For example, in all the natural numbers: 1,2,3,4,5,6...the difference between two successive numbers is always 1. Also, in odd or even numbers we observe a similar thing is happening, where the difference between the two numbers always remains as 2. 


bn+1- bn = constant (=d) for all n∈ N Arithmeticc progression is about a sequence of numbers in which the difference between two terms remains constant. 


The sequence {5, 10, 15, 20, 25, 30, …………………} is an Arithmetic Progression where the common difference is 5, since


Why is it Beneficial to Learn Arithmetic Progression?

An arithmetic progression is a sequence of terms with a common difference between them that is a constant value. It's a term that's used to generalize a group of patterns that we see in our daily lives.


The capacity to notice and generate patterns aids us in making predictions based on our observations is a crucial mathematical talent. Pattern recognition helps children’s acquisition and understanding of complex numerical concepts and mathematical processes. Patterns let us recognize connections and make generalizations.


What are the Properties of Arithmetic Progression Class 11 RS Aggarwal?

The properties of arithmetic progression discussed in RS Aggarwal class 11 maths chapter 11 solutions are as follows:


Property 1: When you add or subtract any constant term to the given AP in each number, the resulting sequence will be an arithmetic progression. 

Property 2: When you multiply or divide each term of a given AP with a non-zero constant, the result will also create an arithmetic progression. 

Property 3: In a finite term of numbers of an arithmetic progression, the total summation of two numbers equidistant from the end and starting will be the numbers is the same as the total summation of the last term and first term. 

Property 4: If 2b = a+c then the three numbers are said to be in an arithmetic progression.

Property 5: A sequence will be established as an arithmetic progression if the nth term is a linear expression. 

Property 6: A sequence will be an arithmetic progression if the summation of the 1st n terms is of An2 + Bn, where A and B are said to be two constant quantities independent of n. 

Note: The effect of adding or subtracting a constant from each term of an AR is an AP with the same common difference. The resulting sequence is also an AP if each term of an AP is multiplied or divided by a non-zero constant.


What are the Benefits of  Preparing from RS Aggarwal Class 11 Maths Arithmetic Progression Exercise?

There are several benefits of preparing from RS Aggarwal Arithmetic Progression exercises. 


  • Exercise 1- The first exercise contains questions, where one needs to find the number of terms in the sequence. Suppose the exact term like the 23rd term of the sequence, identifying the terms and finding the differences, etc. This exercise is a starter exercise that doesn’t include a lot of difficult questions. This exercise exists to make students used to the process of identifying the terms and finding the differences.

  • Exercise 2- The second exercise has questions related to finding some differences as asked in the questions, r term of AP, the value of x, the sum of n terms of AP, last term of Ap, etc. The second exercise is one step up. The exercises in the RS Aggarwal reference book build up the difficulty level with every question you solve, ensuring that one is prepared for any kind of question that might come in the exam.

  • Exercise 3- In this exercise, some questions need to be solved using the various formulas of an arithmetic progression. This is a comparatively basic exercise. Helps in making the basics strong. 

  • Exercise 4- Here, students will find different questions, where one has to find the arithmetic mean. The questions in this exercise will help you brush up on your concepts.

  • Exercise 5- Here students have to prove different situations that are asked in the questions. This exercise requires a good presence of mind and decent application skills. It will require you to apply the concepts that you’ve already learned and practiced differently.

  • Exercise 6- The final exercise comprises various questions that are present in the overall chapter. Solving this exercise will help you assess where you stand on your overall preparation for this chapter. 


Solved Exercise Question from Arithmetic Progression

Question Given that: the nth term of series = (5a+2) 

Sol: Putting a= 1,3,5,7 in the nth term, we obtain, 

First-term a1 = (5 x 1 + 2) = 7

Second term a2 = (5 x 3 + 2) = 17

Third term a3 = (5 x 5 + 2) = 27

Fourth term a4 = (5 x 7 + 2) = 37

Therefore, the first four terms of the series are (7, 17, 27, 37)


Did You Know? 

The behaviour of an arithmetic progression depends upon the common difference. If the difference is positive, it progresses towards positive infinity, if negative it goes towards negative infinity.  The distinction between arithmetic and a geometric sequence is that the difference between two consecutive terms in an arithmetic sequence remains constant, whereas the ratio between two consecutive terms in a geometric series remains constant.


Conclusion

The chapter covers all the important questions along with the answers that serve as a ready reference to comprehend and solve various questions for examination. Students can now include it in their daily practice schedule and home task to grasp the chapter very well. RS Aggarwal Class 11 Maths Arithmetic Progression PDF by Vedantu is made according to the latest question pattern that follows in the examination. So, it will be a good resource for scoring higher marks.

WhatsApp Banner

FAQs on RS Aggarwal Class 11 Solutions Chapter-11 Arithmetic Progression

1. How do Vedantu's RS Aggarwal Class 11 Maths Solutions for Chapter 11 help in exam preparation?

Vedantu's RS Aggarwal Solutions for Class 11 Maths Chapter 11 provide a significant advantage by offering detailed, step-by-step answers for every problem in the textbook. This helps you master the correct methodology as per the CBSE 2025-26 curriculum. By practising with these solutions, you can strengthen your understanding of core concepts, improve problem-solving speed, and learn to tackle complex questions on Arithmetic Progression, ensuring a solid foundation for your exams.

2. What is the standard method to find the nth term of an Arithmetic Progression in RS Aggarwal problems?

To find the nth term (a_n) of an Arithmetic Progression (AP), you use the fundamental formula: a_n = a + (n-1)d. Here, 'a' is the first term, 'n' is the term number you want to find, and 'd' is the common difference. The solutions for RS Aggarwal Chapter 11 consistently apply this formula, showing how to first identify 'a' and 'd' from the given sequence and then substitute the values to find the required term.

3. How are problems related to the sum of the first 'n' terms of an AP structured in RS Aggarwal Chapter 11?

Problems on the sum of 'n' terms in RS Aggarwal typically use one of two main formulas for an Arithmetic Progression. The primary formula is S_n = n/2 [2a + (n-1)d]. An alternative formula, used when the last term (l) is known, is S_n = n/2 [a + l]. The exercises provide practice in identifying which formula is more efficient based on the given information, such as the first term, common difference, number of terms, or the last term.

4. What types of questions are covered across the exercises in RS Aggarwal's Chapter 11 on Arithmetic Progression?

The exercises in RS Aggarwal Chapter 11 cover a comprehensive range of topics on Arithmetic Progression. You will find problems focusing on:

  • Finding a specific term (the nth term) of an AP.
  • Calculating the sum of a given number of terms in an AP.
  • Solving for the first term (a), common difference (d), or number of terms (n) when other values are provided.
  • Problems involving the insertion of Arithmetic Means (A.M.s) between two numbers.
  • Word problems and real-life applications of Arithmetic Progression.
This structured approach ensures a thorough understanding of the entire chapter.

5. How is the concept of Arithmetic Mean (A.M.) used to solve problems in this chapter?

In RS Aggarwal Class 11 Chapter 11, the concept of Arithmetic Mean (A.M.) is primarily used for problems that require inserting a certain number of terms between two given numbers to form an AP. To insert 'n' A.M.s between two numbers 'a' and 'b', you treat 'a' as the first term and 'b' as the (n+2)th term of the new AP. You then calculate the common difference 'd' and subsequently find the 'n' means, which are a+d, a+2d, ..., a+nd.

6. What is a common mistake to avoid when finding the nth term from the end of an AP?

A common mistake is using the standard formula without adjusting the parameters. The correct approach for finding the nth term from the end is to use the formula: l - (n-1)d, where 'l' is the last term and 'd' is the common difference. An alternative method, often clarified in the solutions, is to reverse the AP. In the reversed sequence, the new first term becomes 'l' and the common difference becomes '-d'. You can then find the nth term from the beginning of this new AP.

7. Why are the properties of an Arithmetic Progression crucial for solving higher-order thinking (HOTS) questions?

Understanding the properties of an AP is vital for HOTS questions because these problems often require more than direct formula application. Key properties include:

  • If a constant is added to or subtracted from each term of an AP, the resulting sequence is also an AP with the same common difference.
  • If each term is multiplied or divided by a non-zero constant, the new sequence is also an AP.
  • In a finite AP, the sum of terms equidistant from the beginning and the end is constant and equal to the sum of the first and last terms.
Applying these properties can simplify complex problems that would otherwise be lengthy and difficult to solve.