
The value of universal gravitational constant on earth for a particle of mass 5 kgs is:
A. \[6.67\times {{10}^{-11}}\]
B. \[6.67\times {{10}^{-7}}\]
C. \[5\times 6.67\times {{10}^{-11}}\]
D. \[6.67\times {{10}^{-23}}\]
Answer
498.3k+ views
Hint: The universal gravitational constant is the proportionality constant used in Newton’s Law of Universal Gravitation. It is commonly denoted by G. It is different from g, which denotes the acceleration due to gravity.
Complete step by step answer:
According to Newton's law of universal gravitation, the force of gravitational attraction is given by,
\[F=\dfrac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
Where,
F = gravitational force of attraction
G = universal gravitational constant
$m_1$ = mass of an object
$m_2$ = mass of another object
r = distance between two objects
Which can be written as,
\[G=\dfrac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\]
The universal gravitational constant (G) relates the magnitude of the gravitational attraction force between two bodies to their masses and the distance between them. Its value is extremely difficult to measure experimentally.
Since the universal gravitational constant (G) is a universal constant and its value is independent of the masses or place wherever the masses are situated.
So, its value remains constant i.e., \[6.67\times {{10}^{-11}}N{{m}^{2}}/k{{g}^{2}}\]
Hence, the correct option is A, i.e., \[6.67\times {{10}^{-11}}\]
Additional Information:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a relatively greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is also doubled.
Note: Students should understand Newton's Law of Universal Gravitation and thereafter they need to know how to define the universal gravitational constant (G). Students should also keep in mind that its value remains unchanged with various ranges of masses, distances and places. Students do not need to confuse between G (universal gravitational constant) and g (acceleration due to gravity).
Complete step by step answer:
According to Newton's law of universal gravitation, the force of gravitational attraction is given by,
\[F=\dfrac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
Where,
F = gravitational force of attraction
G = universal gravitational constant
$m_1$ = mass of an object
$m_2$ = mass of another object
r = distance between two objects
Which can be written as,
\[G=\dfrac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\]
The universal gravitational constant (G) relates the magnitude of the gravitational attraction force between two bodies to their masses and the distance between them. Its value is extremely difficult to measure experimentally.
Since the universal gravitational constant (G) is a universal constant and its value is independent of the masses or place wherever the masses are situated.
So, its value remains constant i.e., \[6.67\times {{10}^{-11}}N{{m}^{2}}/k{{g}^{2}}\]
Hence, the correct option is A, i.e., \[6.67\times {{10}^{-11}}\]
Additional Information:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a relatively greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is also doubled.
Note: Students should understand Newton's Law of Universal Gravitation and thereafter they need to know how to define the universal gravitational constant (G). Students should also keep in mind that its value remains unchanged with various ranges of masses, distances and places. Students do not need to confuse between G (universal gravitational constant) and g (acceleration due to gravity).
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

Trending doubts
What are the elders in Goa nostalgic about class 11 social science CBSE

Formaldehyde at room temperature is ALiquid BGas CSolid class 11 chemistry CBSE

Define least count of vernier callipers How do you class 11 physics CBSE

Distinguish between Mitosis and Meiosis class 11 biology CBSE

Why are forests affected by wars class 11 social science CBSE

Explain zero factorial class 11 maths CBSE
