Question

How to find how many moles are in an ion? I am given the solution of $NaCl$ and it has a mass of $53.2g$ and a molar mass of $58.44g$. I already know how to find the number of moles for the entire solution, but I also need to find the number of moles for $N{a^ + }$ ions. How exactly do I go about doing that?

Answer 1

Hint: When ions are dissolved in water, their crystal lattice breaks apart. Dissociation is the process in which the separation of ions takes place when a solid ionic compound dissolves. In the other words when ionic compounds dissolve in water it undergoes a process which is known as dissociation in which it splits into the ions it is made of.

Complete answer:
In this question, $NaCl$ which contains one sodium cation $N{a^ + }$ and one chlorine ion $C{l^ - }$.
This indicates that on dissolving one mole of sodium chloride in the water molecules, we will obtain one mole of aqueous sodium cations and one mole of aqueous chloride anions.
$NaCl\left( {aq} \right) \to \,N{a^ + }\left( {aq} \right) + \,C{l^ - }\left( {aq} \right)$
Thus in each mole of sodium chloride gives one mole of sodium cations which indicates that the number of moles of sodium cation which is in the solution would be equal to the number of moles of sodium chloride which we dissolved for the creation of this solution.
Moreover, we know that we are having
$ \Rightarrow 53.2g \times \dfrac{{1\;mole\;NaCl}}{{58.44g}}$
$ \Rightarrow 0.910\;moles\;NaCl$
Which means we have
$ \Rightarrow 0.910\;moles\,NaCl \times \dfrac{{1\;mole\,N{a^ + }}}{{1\;mole\;NaCl}}$
$ \Rightarrow 0.910\,\;moles\;of\,N{a^ + }$
Thus, this is the required answer.

Note:
In the electrolytic or ionic the dissociation is the summation of a solvent or of energy in which crystals substance break down. Most of the dissociating substance produces ions by chemical combination with solvent.