Answer
Verified
454.2k+ views
Hint: Joule: Joule is SI unit of energy. If it is equal to work done by unit force (Newton) through a distance of one meter.
Calorie: Amount of energy required to raise temperature i.e. unit gram of water 60 unit degree at unit atmospheric pressure.
\[\text{1 cal=4}\text{.184 J}\]
Complete step-by-step answer:
By relation between calorie and Joule we can write
\[\Rightarrow \text{4}\text{.184 J=1 cal}\]
\[\Rightarrow \text{1 J = }\dfrac{\text{1}}{\text{4}\text{.184}}\text{cal }\]
$\Rightarrow \text{1J=0}\text{.239005cal}$
$\Rightarrow \text{1J=0}\text{.24cal}$
Hence, the answer is option c.
Note: Calories are of following types:
Small calories:- If the amount of energy required to heel unit grams to unit Celsius at unit atmospheric pressure it is generally represented in small cal.
Large calories: it is the amount of energy required to 1 kg to \[1{}^\circ C\]at 1 atm pressure. These are generally represented in caps (cal). These are also known as food calories relation between small and large.
\[\text{1 large calorie = 1 kilogram small calorie}\]
We generally consider large calories calories.
To convert \[\text{(}\mathop{E}_{j}\text{)}\]Joules to calories
\[\mathop{E}_{cal}=\dfrac{E(cal)}{4.184}calories\]
And to convert \[\text{(}\mathop{E}_{cal}\text{)}\]to \[\text{(}\mathop{E}_{j}\text{)}\]
\[\mathop{E}_{j} = 4.184\times {{E}_{cal}}\]
Calorie: Amount of energy required to raise temperature i.e. unit gram of water 60 unit degree at unit atmospheric pressure.
\[\text{1 cal=4}\text{.184 J}\]
Complete step-by-step answer:
By relation between calorie and Joule we can write
\[\Rightarrow \text{4}\text{.184 J=1 cal}\]
\[\Rightarrow \text{1 J = }\dfrac{\text{1}}{\text{4}\text{.184}}\text{cal }\]
$\Rightarrow \text{1J=0}\text{.239005cal}$
$\Rightarrow \text{1J=0}\text{.24cal}$
Hence, the answer is option c.
Note: Calories are of following types:
Small calories:- If the amount of energy required to heel unit grams to unit Celsius at unit atmospheric pressure it is generally represented in small cal.
Large calories: it is the amount of energy required to 1 kg to \[1{}^\circ C\]at 1 atm pressure. These are generally represented in caps (cal). These are also known as food calories relation between small and large.
\[\text{1 large calorie = 1 kilogram small calorie}\]
We generally consider large calories calories.
To convert \[\text{(}\mathop{E}_{j}\text{)}\]Joules to calories
\[\mathop{E}_{cal}=\dfrac{E(cal)}{4.184}calories\]
And to convert \[\text{(}\mathop{E}_{cal}\text{)}\]to \[\text{(}\mathop{E}_{j}\text{)}\]
\[\mathop{E}_{j} = 4.184\times {{E}_{cal}}\]
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
10 examples of evaporation in daily life with explanations
Write a letter to the principal requesting him to grant class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Name 10 Living and Non living things class 9 biology CBSE