Question

How can I calculate the orbital angular momentum of an electron?

Answer 1

Hint: The conduct of molecule waves can be seen similarly to the waves going on a string. Molecule waves can prompt standing waves held under full conditions. At the point when a fixed string is culled, various frequencies are energized. Then again, we realize that only those frequencies endure which structure a standing wave in the string, that is, which have hubs at the closures.

Complete step by step answer:
The angular momentum of any s orbital is zero, since the wave work for an s orbital has no angular dependence. All in all, review that angular momentum gives ascend to unpredictable states of a given atomic orbital.
Clarification: Azimuthal Quantum Number: It depicts the state of the orbital. It is spoken to as \['l'\]. In a shut system, angular momentum is conserved in all bearings after an impact. Since momentum is conserved, part of the momentum in an impact may become angular momentum as an item begins to turn after a crash.
In easiest terms, orbital rakish force is quantized and can be figured utilizing the orbital precise energy quantum number \[l\]
$L = \sqrt {l(l + 1)} h$
Computation quantum numbers giving the absolute orbital precise energy and complete turn rakish force of a given state. The absolute orbital rakish energy is the amount of the orbital precise moments from every one of the electrons; it has greatness $L = \sqrt {l(l + 1)} h$ Square root in which \[L\] is a whole number.

Note:
Orbital precise momentum is a property of the electron's rotational movement that is identified with the state of its orbital. The orbital is the locale around the core where the electron will be found if identification is attempted. You may have seen the orbital described as the "electron cloud" around the nucleus. All things considered, all s orbitals are roundly symmetric, so angular momentum does not affect the shape. The orbital rakish force depends on the estimation of the azimuthal quantum number.