

What do you Mean by Escape Velocity?
When we throw an object towards the sky, it doesn’t fly through the air and escape to space. This is due to the gravitational pull. So how does a rocket escape into outer space? The space vehicle requires an immense quantity of fuel to break through the earth’s gravitational pull. This explains what is escape velocity for the earth or the escape speed. This is the minimum speed required to break free the gravitational pull. The object needs to achieve the escape velocity of the celestial bodies like natural satellites and planets. This allows for escaping the influence of the gravitational sphere of the celestial body. The sum total of kinetic energy and gravitational potential energy of the system will be zero in this given velocity
What is the Escape Speed?
Escape speed is defined as the minimum speed with which a mass needs to be propelled from the earth’s surface to escape the earth’s gravity. What is escape velocity for the earth is also the escape speed. This is the minimum speed needed for an object to be free from the gravitation force of a massive object.
What Speed is Escape Velocity?
To understand what speed is escape velocity, let’s view the earth as a massive body. The escape velocity is the minimum speed or velocity that an object should gain to overcome the gravitational field of earth and travel to infinite space without falling back. It totally depends on the mass of the massive body and the distance of the object from the massive body. The more mass and closer the distance of the massive body, greater will be the escape velocity.
Derivation of Escape Speed
The derivation of escape speed is defined in terms of an object and its velocity. When the object moves with a velocity at which the arithmetic total of the object’s kinetic energy, its gravitational potential energy equates to zero. This means the object should possess greater kinetic energy than the gravitational potential energy to escape to infinity.
The easiest way to understand escape velocity formula derivation is by using the concept of conservation of energy. Let’s think that an object is trying to fly from a planet (that is uniform circular in nature) by going away from it.
The main force behind such an object will be the planet’s gravity. We already know that kinetic energy (K) and gravitational potential energy (Ug) are the only two kinds of energies related here.
So by following the principle of conservation of energy, we can write:
(K+Ug)i=(K+Ug)f
Where,
\[K = \frac{1}{2}mv^{2}\], the kinetic energy
\[U = \frac{GMm}{r}\], the gravitational potential energy
Here Ugf is considered zero as the distance is infinity and Kf will also be zero as final velocity will be zero.
The minimum velocity needed to escape from the gravitational force of the massive body is represented by:
\[V_{e} = \sqrt{2gr} = \sqrt{\frac{2GM}{r}}\]
Where
\[g = \frac{GM}{r^{2}}\], G is the universal gravitational constant.
What is the Value of Escape Velocity of the Earth?
The content below will help to derive an expression for escape velocity.
The acceleration due to gravity (earth), g = 9.8 m/s2.
The radius (earth), R = 6.4 × 106 m.
The escape velocity (earth), ve = 11.2 km/s (Approximately).
The escape speed of the earth at the surface is approximately 11.2 km/s. This means to escape from earth’s gravity and travel to infinite space, an object must have a minimum of 11.2 km/s of the initial velocity.
Escape Velocity refers to the minimum speed that is required in order to escape from a planet’s gravitational pull.
Taking an example, if we consider the earth to be a massive body, then the escape velocity is the minimum velocity which an object will have to acquire in order to be able to overcome the gravitational field of the earth and fly to infinity without falling back.
This will depend on the distance of the object from the massive body and the mass of the massive body. If the mass is more, it will be higher. Similarly, the closer the distance, the escape velocity will be higher.
What is the Unit of Escape Speed?
The unit of escape speed or escape velocity is expressed in meters per second (m.s-1). This is also the SI unit of escape speed.
Dimensional Formula
The dimensional formula of the escape velocity can be obtained by resolving the formula dimensionally. Now, we know that the escape velocity formula includes a constant, G, which is known as the universal gravitational constant. The value of the universal gravitational constant is 6.673 × 10-11 N . m2 / kg2. The unit for escape velocity is meters per second (m/s).
Since the escape velocity is again a form of velocity and it is measured in terms of m/s. Thus the dimensional formula of escape velocity is [M0L1T-1].
We can also determine the dimensions of escape velocity by dimensional analysis. We know that the dimensional formula of the escape velocity is:
\[V_{e} = \sqrt{2gr} = \sqrt{\frac{2GM}{r}}\]
Now, we know that,
Dimensional formula of the earth’s mass =M= M1L0T0.
Dimensional formula of universal gravitational constant =G= M-1L3T-2.
Dimensional formula of the center of the earth to the distance covered =r= M0L1T0.
The dimensional formula of escape speed is Ve= M0L1T-1
Therefore,
\[\sqrt{\frac{2GM}{r}} = \left ( \frac{[M^{-1}L^{3}T^{-2}][M]}{[L]} \right )^{\frac{1}{2}} = [M^{0}L^{2}T^{-2}]^{\frac{1}{2}} = [M^{0}L^{1}T^{-1}] \]
Therefore, the dimensional formula of escape velocity is \[[M^{0}L^{1}T^{-1}] \]
The table below shows the escape velocity of various objects:
The Escape Velocity of Various Objects
Did You Know?
There exists a relationship between escape velocity and orbital velocity. The relationship between the escape velocity and orbital velocity is proportional in nature. Escape velocity refers to the minimum velocity needed to overcome the gravitational pull of the massive to fly to the infinite space. Orbital velocity is a velocity that is required to rotate around a massive body. This means if the orbital velocity increases, the escape velocity also increases, and if orbital velocity decreases, the escape velocity also decreases.
FAQs on Escape Speed
1. What is escape speed as per the CBSE Class 11 Physics syllabus?
Escape speed is the minimum initial speed an object must have to be projected from the surface of a celestial body (like a planet or moon) to completely overcome its gravitational pull and travel to an infinite distance away without ever falling back. For an object to escape, its kinetic energy must be equal to or greater than its gravitational potential energy.
2. What is the formula to calculate escape speed?
The formula for escape speed (Vₑ) from the surface of a spherically symmetric body is given by:
Vₑ = √(2GM/R)
Alternatively, since the acceleration due to gravity (g) is GM/R², the formula can also be expressed as:
Vₑ = √(2gR)
- G is the universal gravitational constant.
- M is the mass of the celestial body (e.g., Earth).
- R is the radius of the celestial body.
3. How is the formula for escape speed derived?
The derivation of escape speed is based on the principle of conservation of energy. To escape the gravitational field, the total mechanical energy (Kinetic Energy + Gravitational Potential Energy) of the object must be zero at an infinite distance. By setting the final energy to zero, we can find the minimum initial kinetic energy required at the surface.
- Initial Kinetic Energy = ½ mVₑ²
- Initial Gravitational Potential Energy = -GMm/R
- For the object to just escape, the total initial energy must be zero: ½ mVₑ² - GMm/R = 0
- Solving for Vₑ gives the formula: Vₑ = √(2GM/R).
4. What is the escape speed of Earth, and what is the significance of this value?
The escape speed from the Earth's surface is approximately 11.2 kilometres per second (km/s) or about 40,320 km/h. This value is significant because any object, such as a rocket or a space probe, must reach this minimum speed to break free from Earth's gravity and travel into deep space, for example, to other planets or beyond our solar system.
5. Why is Earth's escape speed a specific value of 11.2 km/s?
The value of 11.2 km/s is a direct result of Earth's specific physical properties plugged into the escape speed formula, Vₑ = √(2GM/R). The calculation uses:
- The Earth's mass (M), which is approximately 5.97 x 10²⁴ kg.
- The Earth's radius (R), which is approximately 6,371 km.
- The Universal Gravitational Constant (G).
A planet with a different mass or radius would have a different escape speed. For instance, the Moon's lower mass and smaller radius result in a much lower escape speed of about 2.4 km/s.
6. Does the escape speed depend on the mass of the object that is escaping?
No, the escape speed is independent of the mass of the escaping object. As seen in the formula Vₑ = √(2GM/R), the variables are the mass (M) and radius (R) of the large celestial body (like Earth), not the mass of the smaller object (like a satellite). This means a small satellite and a massive spaceship both need to achieve the same speed of 11.2 km/s to escape Earth's gravity.
7. What is the key difference between escape speed and orbital speed?
The key difference lies in their purpose and magnitude. Orbital speed is the speed required for an object to maintain a stable orbit around a celestial body, balancing the gravitational pull with its forward motion. Escape speed is the higher speed required to completely overcome that gravitational pull and leave orbit permanently. For an object in a low Earth orbit, the escape speed is √2 (approximately 1.414) times its orbital speed.

















