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Value of Log 2 in Maths: Exact Values, Formulas & Uses

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How to Find the Value of Log 2 Without a Calculator?


The concept of value of log 2 plays a key role in mathematics and is widely applicable to both real-life situations and exam scenarios. Knowing the value of log 2 helps students solve logarithmic equations, use log tables, and apply shortcuts in board and entrance exams like JEE or NEET.


What Is Value of Log 2?

The value of log 2 refers to the logarithm of 2 to different bases, most commonly base 10 (log102), base e (natural logarithm, ln(2)), and base 2 (binary logarithm, log22). In mathematics, a logarithm is the exponent to which a base must be raised to get a particular number. You’ll find this concept applied in areas such as exponential equations, data science (binary representation), and scientific measurement scales.


Key Formula for Value of Log 2

Here’s the standard formula for changing the base of a logarithm:
\( \log_b{a} = \frac{\log_k{a}}{\log_k{b}} \)
For log 2:

\(\log_{10}{2} \approx 0.3010\)
\(\ln{2} = \log_{e}{2} \approx 0.6931\)
\(\log_{2}{2} = 1\)


Value of Log 2 Table

Base Expression Value
10 log10 2 0.3010
e ln 2 0.6931
2 log2 2 1

Cross-Disciplinary Usage

The value of log 2 is not only useful in Maths but also plays an important role in Physics (like the Richter scale), Computer Science (binary data), and logical reasoning. For example, log 2 helps in calculating how many times a number must be divided by 2 to reach 1, which is used in algorithms, information theory, and more. Students preparing for exams like JEE Main often find log values and related shortcuts extremely useful.


How to Calculate the Value of Log 2 Without Calculator

  1. Use the Change of Base Formula:
    \(\log_{10}{2} = \frac{\ln{2}}{\ln{10}}\) or find using log tables.
  2. Use Powers Close to 2:
    Since \(2^{10} = 1024 \approx 1000\), we use:
    \(10 \times \log_{10}{2} \approx 3\) ⇒ \(\log_{10}{2} \approx 0.3\)
  3. Taylor Series Expansion (for advanced):
    \(\ln{(1 + x)} = x - \frac{x^{2}}{2} + \frac{x^{3}}{3} - ...\)    For x=1, \(\ln{2} \approx 0.6931\)

Quick Tip: For mental maths, remember log 2 ≈ 0.3 and ln 2 ≈ 0.7 for fast calculations.


Step-by-Step Illustration: Example Problem

Find log10 8 using the value of log 2.

1. Write 8 as a power of 2:

2. 8 = 23

3. Use log property: log10 8 = log10 (23) = 3 × log10 2

4. Substitute log10 2 ≈ 0.3010

5. Final Answer: 3 × 0.3010 = 0.9030

Speed Trick or Vedic Shortcut

To estimate log values during exams, remember the shortcut: log10 2 ≈ 0.3 (that is, 210 ≈ 1000, so log 1000 = 3, hence log 2 ≈ 0.3). This helps quickly calculate related logs like:

  1. For log10 4: 4 = 22 ⇒ log 4 = 2 × log 2 ≈ 2 × 0.3 = 0.6
  2. For log10 8: 8 = 23 ⇒ log 8 = 3 × log 2 ≈ 0.9

Vedantu’s live classes include more such shortcuts for exam success.


Try These Yourself

  • Using log 2 ≈ 0.3010, find log10 16.
  • Estimate log10 32.
  • What is log2 64?
  • Calculate ln 4 using ln 2.

Frequent Errors and Misunderstandings

  • Confusing log 2 with ln 2 (log base confusion).
  • Forgetting that log2 2 is exactly 1, not 0.
  • Taking log of a negative number (undefined in real numbers).
  • Using rounded log 2 values in precise calculations—always check question requirement.

Relation to Other Concepts

The idea of value of log 2 connects closely with topics such as logarithm properties (product, quotient, and power rules) and the use of log tables. Mastering this helps with fast calculations in exponentials, scientific data, and other log-based maths concepts.


Classroom Tip

A quick way to remember the value of log 2 is to think “log 2 is almost 0.3.” During exams, students often recall that 210 = 1024 ≈ 103, backing up that 10 × log 2 ≈ 3 ⇒ log 2 ≈ 0.3. Vedantu teachers use visual tables and mobile log charts for quick revision.


We explored value of log 2—from what it is, formulas, log tables, shortcut tricks, and how to avoid common mistakes. Continue practicing with Vedantu to become confident in solving problems using this concept in competitive and board exams.


Related Vedantu Resources


FAQs on Value of Log 2 in Maths: Exact Values, Formulas & Uses

1. What are the common values of log 2 used in mathematics?

The value of log 2 depends on its base. The three most common bases students encounter are:

  • Base 10 (Common Logarithm): log₁₀ 2 is approximately 0.3010. This is frequently used in scientific and engineering calculations.
  • Base e (Natural Logarithm): ln 2 is approximately 0.6931. This is crucial in calculus and topics involving exponential growth.
  • Base 2 (Binary Logarithm): log₂ 2 is exactly 1, as 2 raised to the power of 1 is 2. This is fundamental in computer science and information theory.

2. What is the main difference between log 2 and ln 2?

The key difference is the base of the logarithm. The term 'log 2' typically implies a common logarithm with base 10 (log₁₀ 2). In contrast, 'ln 2' explicitly refers to the natural logarithm with base e (an irrational number approximately equal to 2.718). While both represent the same concept, their values (0.3010 and 0.6931, respectively) are different and used in different mathematical contexts.

3. Where is the value of log 2 used in real-world applications?

The value of log 2 is a cornerstone in many scientific fields. For example:

  • In Chemistry, it is used in pH calculations and reaction kinetics.
  • In Physics, it appears in formulas for sound intensity (decibels) and earthquake magnitude (Richter scale).
  • In Computer Science, the binary logarithm (log₂ n) is essential for analysing algorithms, data structures, and information theory, as it often relates to the number of bits needed to represent a number.

4. How does knowing the value of log 2 help find other log values like log 4, log 8, or log 5?

By using the properties of logarithms, the value of log 2 acts as a building block. For example, using base 10:

  • Value of log 4: Since 4 = 2², log 4 = log(2²) = 2 * log 2 ≈ 2 * 0.3010 = 0.6020.
  • Value of log 8: Since 8 = 2³, log 8 = log(2³) = 3 * log 2 ≈ 3 * 0.3010 = 0.9030.
  • Value of log 5: Since 5 = 10/2, log 5 = log(10/2) = log 10 - log 2 = 1 - 0.3010 = 0.6990.

This shows how mastering log 2 allows for quick calculation of many other logarithms.

5. Why can't we calculate the logarithm of a negative number or zero?

This is a fundamental concept. A logarithm, such as logₐ(x) = y, is the inverse of an exponential function, x = aʸ. For the exponential function, the base 'a' is always a positive number (and not 1). A positive base raised to any real power 'y' can only produce a positive result 'x'. Because 'x' is always positive, the input to its inverse function, the logarithm, must also be positive. Therefore, the domain of a logarithm is restricted to positive real numbers, making log(0) and log(negative number) undefined.

6. How can we estimate the value of log₁₀ 2 without a calculator using mathematical reasoning?

A very useful estimation comes from the fact that 2¹⁰ = 1024, which is very close to 1000 or 10³. By setting these approximately equal (2¹⁰ ≈ 10³), we can apply a logarithm to both sides:

  • log₁₀(2¹⁰) ≈ log₁₀(10³)
  • Using the power rule of logs, this becomes: 10 * log₁₀(2) ≈ 3 * log₁₀(10)
  • Since log₁₀(10) = 1, we get: 10 * log₁₀(2) ≈ 3
  • Therefore, log₁₀ 2 ≈ 3/10 or 0.3. This provides a quick and logically sound approximation for exams.

7. Beyond its value, what does the expression 'log₂ x' represent conceptually?

Conceptually, the expression 'log₂ x' asks a very specific question: "To what exponent must the base 2 be raised to obtain the number x?" It is not just a function to be calculated, but the answer to that question. For example, evaluating log₂ 8 is equivalent to solving the equation 2ʸ = 8. The answer is y = 3. This conceptual understanding is key to solving logarithmic equations and understanding its role in fields like computer science where powers of 2 are fundamental.

8. What is the antilog of log 2?

The antilogarithm, or antilog, is the inverse operation of a logarithm. It essentially 'undoes' the logarithm. The antilog of a number is the base raised to that number. Therefore:

  • The antilog to the base 10 of log₁₀ 2 is 10^(log₁₀ 2), which equals 2.
  • Similarly, the antilog to the base e of ln 2 is e^(ln 2), which also equals 2.

In simple terms, if log(x) = y, then antilog(y) = x.