Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

Probability Density Function in Continuous Random Variables

Reviewed by:
ffImage
hightlight icon
highlight icon
highlight icon
share icon
copy icon

Probability Density Function formula properties and solved examples

The concept of Probability Density Function (PDF) plays a key role in mathematics and is widely applicable to both real-life situations and exam scenarios. From understanding population statistics to solving tough JEE or CBSE probability questions, mastering the PDF helps you grasp how probabilities work for continuous outcomes like heights, weights, or timings. Let's explore the basics, formulas, solved examples, and best tips for learning PDFs in a clear, stepwise format perfect for your Maths journey.


What Is Probability Density Function (PDF)?

A probability density function (PDF) is a type of function that describes the likelihood (or density) that a continuous random variable will take on a value within a particular range. Unlike the probability mass function (PMF) used for discrete variables, the PDF works for variables that can take any value over a continuous interval, such as the exact height of a student or the precise time light takes to travel a certain distance.

You’ll find this concept applied in areas such as statistical inference, data science, and physics experiments. For example, PDFs define the famous normal distribution "bell curve" and the uniform distribution for evenly spread results.


Key Formula for Probability Density Function (PDF)

Here’s the standard formula:
If X is a continuous random variable and f(x) is its PDF, then the probability of X falling between a and b is given by:

\( P(a < X < b) = \int_{a}^{b} f(x) \, dx \)

The function f(x) must always satisfy:

  • f(x) ≥ 0 for all x
  • \( \int_{-\infty}^{+\infty} f(x) dx = 1 \) (Total area under the curve = 1)

Cross-Disciplinary Usage

A probability density function is not only useful in Maths but also plays an important role in Physics, Computer Science, Economics, and daily logical reasoning. Students preparing for exams like JEE or NEET will see its relevance in topics such as quantum probability, statistical mechanics, and data prediction problems.


Step-by-Step Illustration

  1. Given: A variable X has PDF \(f(x) = 2x\) for \(x\) in [0,1]. What is the probability that X lies between 0.2 and 0.5?
  2. Set up the integral: \(P(0.2 < X < 0.5) = \int_{0.2}^{0.5} 2x\, dx\)
  3. Integrate: \(= [x^2]_{0.2}^{0.5}\)
  4. Calculate limits: \(= (0.5)^2 - (0.2)^2 = 0.25 - 0.04 = 0.21\)
  5. Final answer: The probability is 0.21

Speed Trick or Vedic Shortcut

Here’s a quick shortcut: When the PDF is constant (like in a uniform distribution), probabilities can be found directly by the formula:

Probability = (Interval Length) × PDF height

Example: If f(x) = 0.2 for 0 ≤ x ≤ 5, then P(1 < X < 3) = (3 – 1) × 0.2 = 0.4

Tricks like this save time in competitive exams. Vedantu’s live sessions provide many more tips for mastering PDFs and related probability topics.


Try These Yourself

  • Given f(x) = 3x² for 0 ≤ x ≤ 1, find P(0.5 < X < 1).
  • Explain why P(X = 0.3) = 0 for any continuous PDF.
  • If f(x) = 4 for 0 ≤ x ≤ 0.25, what’s P(0.1 < X < 0.2)?
  • Name two differences between PDF and PMF.

Frequent Errors and Misunderstandings

  • Confusing the value of the PDF (f(x)) with actual probability. Remember, the probability is found by integrating over an interval, not by looking at f(x) at a single point.
  • Forgetting that the total area under the PDF must be 1, even if the graph rises above 1 for some x.
  • Mixing up PDF with PMF or CDF. PDF is for continuous data, PMF is for discrete, CDF adds up probabilities up to a point.

Relation to Other Concepts

The idea of a probability density function connects closely with topics such as the Probability Distribution and Cumulative Distribution Function (CDF). Mastering PDFs makes it much easier to move on to calculating expected values, mean and variance of random variables, and working with standard distributions like the normal distribution or uniform distribution.


Classroom Tip

A quick way to remember PDFs: "Points are impossible, ranges are possible." For any exact value x, the probability is always 0 for continuous variables; only a range gives a nonzero chance. Vedantu’s teachers often highlight this with real-life analogies and visualization tricks in their classes.


We explored Probability Density Function (PDF)—from definition, formula, examples, mistakes, and how it links to other topics like probability distributions. Keep practicing and reviewing these steps, and don’t forget to check out other topics on Vedantu for a full understanding of Mathematics!


Related Topics: Probability | Probability Distribution | Cumulative Distribution Function (CDF) | Normal Distribution | Mean and Variance of Random Variable


FAQs on Probability Density Function in Continuous Random Variables

1. What is a probability density function (PDF)?

A probability density function (PDF) is a function that describes the relative likelihood of a continuous random variable taking on a given value. For a continuous random variable X, the PDF f(x) satisfies:

  • f(x) ≥ 0 for all x
  • -∞ f(x) dx = 1
The probability that X lies in an interval [a, b] is given by P(a ≤ X ≤ b) = ∫ab f(x) dx. Unlike discrete distributions, the probability at a single point is zero.

2. What is the formula for a probability density function?

The formula for a probability density function depends on the distribution, but it must satisfy f(x) ≥ 0 and -∞ f(x) dx = 1. For example, a simple PDF is:

  • f(x) = 2x, for 0 ≤ x ≤ 1
  • f(x) = 0, otherwise
Check validity: ∫01 2x dx = [x²]01 = 1, so it is a valid probability density function.

3. How do you find the probability from a probability density function?

To find probability from a PDF, integrate the function over the required interval using P(a ≤ X ≤ b) = ∫ab f(x) dx. Steps:

  • Identify the interval [a, b]
  • Integrate the PDF over that interval
  • Evaluate the definite integral
Example: If f(x) = 2x for 0 ≤ x ≤ 1, then P(0 ≤ X ≤ 0.5) = ∫00.5 2x dx = [x²]00.5 = 0.25.

4. What is the difference between PDF and CDF?

The probability density function (PDF) gives density at a point, while the cumulative distribution function (CDF) gives accumulated probability up to a point. The relationship is:

  • F(x) = ∫-∞x f(t) dt
  • f(x) = dF(x)/dx
The CDF is always increasing from 0 to 1, while the PDF represents the rate of change of probability.

5. What are the properties of a probability density function?

A valid probability density function must satisfy two main properties:

  • Non-negativity: f(x) ≥ 0 for all x
  • Total area equals 1:-∞ f(x) dx = 1
Additionally, probabilities are found using integration, and P(X = a) = 0 for any single value in a continuous distribution.

6. Can a probability density function be negative?

No, a probability density function cannot be negative because it must satisfy f(x) ≥ 0 for all x. A negative value would imply negative probability, which is impossible. However, the function can be zero in certain intervals as long as the total integral over all real numbers equals 1.

7. What is the expected value of a probability density function?

The expected value (mean) of a continuous random variable is given by E(X) = ∫-∞ x f(x) dx. Steps:

  • Multiply x by the PDF f(x)
  • Integrate over the entire range
Example: If f(x) = 2x for 0 ≤ x ≤ 1, then E(X) = ∫01 2x² dx = [2x³/3]01 = 2/3.

8. What is the variance of a probability density function?

The variance of a continuous random variable is Var(X) = E(X²) − [E(X)]², where E(X²) = ∫-∞ x² f(x) dx. Steps:

  • Compute E(X)
  • Compute E(X²)
  • Apply Var(X) formula
For f(x) = 2x on [0,1], E(X) = 2/3 and E(X²) = ∫01 2x³ dx = 1/2, so Var(X) = 1/2 − (2/3)² = 1/18.

9. What is an example of a probability density function?

An example of a probability density function is the uniform distribution on [a, b], defined as f(x) = 1/(b − a) for a ≤ x ≤ b. For example, if X is uniform on [0, 4]:

  • f(x) = 1/4 for 0 ≤ x ≤ 4
  • f(x) = 0 otherwise
The total area is (1/4) × 4 = 1, satisfying the PDF condition.

10. Why is the probability at a single point zero in a PDF?

The probability at a single point is zero because probability in a continuous distribution is calculated using integration over an interval. Mathematically, P(X = a) = ∫aa f(x) dx = 0. A single point has no width, so its area under the probability density function curve is zero, even though f(a) itself may be positive.