
The weight of a 13 m long iron rod is $23.4{\text{ kg}}$. The weight of 6 m long of such rod will be ______.
A. $7.2{\text{ kg}}$
B. $12.4{\text{ kg}}$
C. $10.8{\text{ kg}}$
D. $18{\text{ kg}}$
Answer
232.8k+ views
Hint: We will first consider the given values and consider the first set of values as the weight of iron rod is \[23.4\]kg and length as 13m and the second set of values as the weight be \[x\] kg and length as 6m. After this we will use the ratio and proportion method to find the value of \[x\] by writing them in the form of \[\dfrac{{{\text{weight}}}}{{{\text{length}}}}\] and put the values of both sets equal and simplifying the expression gives the desired result.
Complete step by step solution:
Consider the given values in the question,
The weight of the 13 m long rod is 23.4 Kg.
We need to find the value of the weight of 6 m long rod.
Let the weight of 6 m long iron rod will be $x$
Next, we will write the proportion by equating two ratios $23.4{\text{ kg}}$ to 13 m and $x$ to 6 m.
Thus, we get,
$ \Rightarrow \dfrac{{23.4{\text{ }}}}{{13{\text{ }}}} = \dfrac{x}{{6{\text{ }}}}$
Here, we will apply cross multiplication on the expression above to obtain the value of $x$.
We get,
$ \Rightarrow 23.4{\text{ }} \times 6{\text{ }} = x\left( {13{\text{ }}} \right)$
Next, we will divide both sides of the above equation by 13.
Thus, we get,
$
\Rightarrow \dfrac{{23.4{\text{ }} \times 6{\text{ }}}}{{13{\text{ }}}} = \dfrac{{x\left( {13{\text{ }}} \right)}}{{13{\text{ }}}} \\
\Rightarrow \dfrac{{23.4{\text{ }} \times 6}}{{13}} = x \\
$
Further, we will perform multiplication and division to solve for $x$.
$
\Rightarrow \dfrac{{{\text{140.4 kg}}}}{{13}} = x \\
\Rightarrow 10.8{\text{ kg}} = x \\
$
Hence, the weight of the rod having length 6 m is $10.8{\text{ kg}}$.
Therefore, option (C) is correct.
Note: Ratios of the proportion should be from weight to length, because we have to find the weight of the other rod. As we are given two values of one set and one value is given for the second set and need to find the other value, we must use the ratio and proportion method to determine the other value. Also the units of the data should be checked while solving the equation.
Complete step by step solution:
Consider the given values in the question,
The weight of the 13 m long rod is 23.4 Kg.
We need to find the value of the weight of 6 m long rod.
Let the weight of 6 m long iron rod will be $x$
Next, we will write the proportion by equating two ratios $23.4{\text{ kg}}$ to 13 m and $x$ to 6 m.
Thus, we get,
$ \Rightarrow \dfrac{{23.4{\text{ }}}}{{13{\text{ }}}} = \dfrac{x}{{6{\text{ }}}}$
Here, we will apply cross multiplication on the expression above to obtain the value of $x$.
We get,
$ \Rightarrow 23.4{\text{ }} \times 6{\text{ }} = x\left( {13{\text{ }}} \right)$
Next, we will divide both sides of the above equation by 13.
Thus, we get,
$
\Rightarrow \dfrac{{23.4{\text{ }} \times 6{\text{ }}}}{{13{\text{ }}}} = \dfrac{{x\left( {13{\text{ }}} \right)}}{{13{\text{ }}}} \\
\Rightarrow \dfrac{{23.4{\text{ }} \times 6}}{{13}} = x \\
$
Further, we will perform multiplication and division to solve for $x$.
$
\Rightarrow \dfrac{{{\text{140.4 kg}}}}{{13}} = x \\
\Rightarrow 10.8{\text{ kg}} = x \\
$
Hence, the weight of the rod having length 6 m is $10.8{\text{ kg}}$.
Therefore, option (C) is correct.
Note: Ratios of the proportion should be from weight to length, because we have to find the weight of the other rod. As we are given two values of one set and one value is given for the second set and need to find the other value, we must use the ratio and proportion method to determine the other value. Also the units of the data should be checked while solving the equation.
Recently Updated Pages
Area vs Volume: Key Differences Explained for Students

Mutually Exclusive vs Independent Events: Key Differences Explained

Square vs Rhombus: Key Differences Explained for Students

Power vs Exponent: Key Differences Explained for Students

Arithmetic Mean Formula Explained Simply

Algebraic Formula: Key Concepts & Easy Examples

Trending doubts
JEE Main Syllabus 2026: Download Detailed Subject-wise PDF

JEE Main 2026 Exam Centres (OUT) – Latest Examination Centre and Cities List

JEE Main 2026 January 21 Shift 2 Question Papers and Analysis OUT Check Student Reactions

JEE Main 2026 Dress Code for Male & Female Candidates

JEE Main 2025 24 Jan Shift 2 Question Paper with Solutions

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Other Pages
Surface Areas and Volumes Class 10 Maths Chapter 12 CBSE Notes - 2025-26

CBSE Class 10 Maths Set 2 2025 Question Paper (Standard) – PDF & Solutions

CBSE Class 10 Maths Question Paper Set 2 430/1/2 2025 (Basic): PDF, Answers & Analysis

CBSE Class 10 Maths Question Paper Set 1 (Basic) 430/5/1 – 2025 with Answers

CBSE Class 10 Maths Set 1 2025 Question Paper (Standard)

CBSE Class 10 Maths Question Paper Set 2 2025 with Solutions

