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Tension, Normal, and Spring Forces Explained for JEE/NEET/Boards

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How to Draw Free Body Diagrams with Tension, Normal, and Spring Forces

Understanding Tension, Normal and Spring Forces is critical for mastering JEE Main Physics. These forces form the backbone of many problems in mechanics, especially when drawing free body diagrams or solving questions on equilibrium and motion. Applications include block-pulley systems, springs, inclined planes, and oscillatory motion.


In Physics, forces are interactions that change an object’s motion. The four main contact and non-contact forces are gravitational, electromagnetic, nuclear, and mechanical forces, with tension force, normal force, and spring force classified among mechanical forces. Questions on these are common in Newton's laws of motion contexts.


Key Concepts: Tension, Normal and Spring Forces

Tension, normal and spring forces act in different scenarios but often appear together. Tension force is present when a rope, string, or cable pulls an object. Normal force is always perpendicular to the contact surface, resisting penetration. Spring force is the restoring force observed in deformed springs, all governed by their specific physical laws.


A frequent exam trap is confusing normal with tension forces, especially on inclined planes or in pulley questions. Remember, normal force always acts perpendicular, while tension acts along the rope or cord. Practicing with free body diagrams helps avoid mistakes.


Formulas for Tension, Normal and Spring Forces

  • Tension force: T = m·a, where T is tension, m is mass, and a is acceleration. For equilibrium, set net force to zero.
  • Normal force: N = m·g·cosθ for an inclined plane; N = m·g when surface is horizontal and no other vertical forces act.
  • Spring force (Hooke’s Law): F = –k·x, with F as spring force, k the spring constant, and x the extension or compression from equilibrium.

Sign convention is crucial: the negative sign in Hooke’s law indicates the force is always opposite to displacement. Forgetting this often leads to sign errors in oscillation numericals.


Comparison Table: Tension, Normal and Spring Forces

Type of Force Direction Formula/Principle Example
Tension Along string or rope T = m·a or by force balance Weight hanging from a rope
Normal Perpendicular to surface N = m·g·cosθ Book on a table
Spring Along axis of spring F = –k·x Compressed spring in toys

Hooke’s law and spring constant are central for finding spring force in both static and oscillating systems.


Applying Tension, Normal and Spring Forces in JEE Problems

To solve mechanics questions, first identify all contact and restoring forces. On inclines, normal force reduces as angle increases, and tension distributes across connected masses. Springs resist both stretching and compression, governed strictly by Hooke’s law.


  • For tension: Set up equilibrium or motion equations for objects connected by strings and pulleys.
  • For normal force: Account for inclined planes, stacked blocks, or vertical loads.
  • For spring force: Use F = –k·x and be careful with the direction of x.
  • In compound systems: Combine all forces with Newton’s second law.
  • Double-check units; SI units are always used in JEE Main questions.

Example: A block of mass 2 kg hangs motionless from a stationary rope. The tension force must balance the weight. So, T = m·g = 2 × 9.8 = 19.6 N upward.


If the block is on a frictionless incline at 30°, the normal force is N = m·g·cos30° = 2 × 9.8 × 0.866 ≈ 16.97 N upward and perpendicular to the slope.


For a spring stretched 0.2 m with k = 100 N/m, the spring force is F = –100 × 0.2 = –20 N. The negative sign means the force acts opposite to the displacement.


Students often overlook that tension can vary along a rope with changing mass or friction, especially when a pulley has mass or friction. Double-check assumptions. Friction and normal reaction interplay whenever a surface resists motion.


  • Always define force directions clearly in the diagram.
  • Beware of hidden forces: walls, surfaces, or tied points can produce extra reactions.
  • Practice applying sign conventions for springs, especially in energy calculations.
  • Use free body diagram methods for error-free solutions.
  • Refer to laws of motion summaries for overlooked points.

The spring force concept directly connects to simple harmonic motion and oscillations. Many JEE objective and assertion-reason questions use these as a base scenario.


A solid understanding of Tension, Normal and Spring Forces ensures you tackle everything from pulley systems to oscillating masses efficiently. For more practice and theory, Vedantu offers expert-reviewed materials covering these key JEE topics.

Competitive Exams after 12th Science
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FAQs on Tension, Normal, and Spring Forces Explained for JEE/NEET/Boards

1. What is tension force and how is it calculated?

Tension force is a pulling force transmitted through a string, rope, cable or spring. It is calculated using Newton’s second law and depends on the weight and acceleration of the objects involved. For an object of mass m hanging at rest, Tension (T) = m × g, where g = 9.8 m/s². For accelerating objects, use T = m × (g ± a), adjusting the sign for acceleration direction.

2. What is the difference between spring force and tension force?

Spring force is a restoring force exerted by a spring, while tension force is a pulling force in a string or rope. The differences include:

  • Spring force obeys Hooke's law: F = -k × x, where k is the spring constant, x is the extension/compression.
  • Tension force applies to ropes/cables under forces, acting equally on either side.
  • Spring force acts in both directions to restore equilibrium; tension only pulls away.

3. What is the difference between normal force and tension force?

Normal force is a support force exerted perpendicular to contact surfaces, while tension force is a pulling force along ropes or strings. Key differences:

  • Normal force prevents objects from passing through each other.
  • Tension force transmits pulling effect through cables or ropes.
  • Normal force acts perpendicularly; tension acts along the string’s length.

4. What is the formula for the force in a spring?

Spring force follows Hooke's law: F = -k × x, where

  • F = spring force
  • k = spring constant
  • x = displacement from equilibrium
The negative sign indicates force direction is opposite to displacement.

5. What is the relationship between spring constant and tension?

Spring constant determines how much tension a spring produces for a given stretch or compression. The relationship is:

  • Tension force (F) in the spring = k × x
  • Higher k means greater tension for the same extension.
  • The spring constant (k) measures the spring’s stiffness.

6. What is the formula for normal force?

Normal force (N) on a flat surface is given by N = m × g if the surface is horizontal and there are no other vertical forces. If the surface is inclined, N = m × g × cos(θ), where θ is the angle of the incline.

7. What are the four main types of forces?

The four main types of forces in physics are:

  • Gravitational force - attraction between masses
  • Electromagnetic force - acts between charged particles
  • Normal force - support from surfaces
  • Tension force - pull through ropes or springs
These are fundamental to understanding mechanics and interactions.

8. How do you solve problems involving spring force, normal force, and tension force?

To solve problems on spring force, normal force, and tension force, follow these steps:

  • Draw a free-body diagram indicating all forces
  • Apply relevant formulas: Tension = m × g, Normal force = m × g (or m × g × cos(θ)), Spring force = -k × x
  • Use Newton’s Laws to relate forces and motion
  • Consider direction and equilibrium conditions

9. What does the negative sign in Hooke’s law mean?

The negative sign in Hooke’s law (F = -k × x) shows that spring force acts in the opposite direction to displacement. This means:

  • If spring is stretched right, force pulls left
  • If compressed left, force pushes right
This restoring force tries to return the spring to its equilibrium position.

10. What types of forces act on an object resting on a spring on an inclined plane?

For an object on a spring on an incline, these forces act:

  • Normal force perpendicular to the incline
  • Spring force along the spring’s length (restoring direction)
  • Gravitational force (weight) vertically downward
  • Frictional force (if surface isn’t smooth)
Free-body diagrams help visualize and solve such problems in exams.