If the young’s modulus of the material is 3 times its modulus of rigidity, then its volume elasticity will be:
A) Zero
B) Infinity
C) $2 \times {10^{10}}N{m^{ - 2}}$
D) $3 \times {10^{10}}N{m^{ - 2}}$
Answer
Verified
125.1k+ views
Hint: First find the relation between the young modulus and modulus of rigidity, then find the relation between the Poisson’s ratio and modulus of rigidity, from that relation we can find the value of volume elasticity.
Complete step by step solution:
Here, we are asked to find the value of volume elasticity or the volume elasticity of the material.
Let’s discuss the terms volume modulus.
The modulus of volume is also called bulk modulus. It is a numerical constant that helps to analyze the properties of elasticity of fluid or solid when pressure is acting on all of its surfaces. The volume reduces due to the applied pressure.
It is given that the young’s modulus is equal to three times its modulus of rigidity.
That is, $Y = 3\eta $
It is known that the value of Young’s modulus is given by,
$Y = 2\eta (1 + \sigma )$
Where, $\sigma $ is the Poisson’s ratio.
Applying the value of young’s modulus we get,
$3\eta = 2\eta (1 + \sigma )$
$ \Rightarrow \sigma = \dfrac{1}{2}$
Now we are using another formula for young’s modulus to find the value of bulk modulus.
That is, $Y = 3K(1 - 2\sigma )$
Where, $K$ is the bulk modulus.
We are applying the value of Poisson’s ratio to this equation, we get,
\[Y = 3K(1 - 2\sigma )\]
$ \Rightarrow K = \dfrac{Y}{{3(1 - 2\sigma )}}$
$ \Rightarrow K = \dfrac{Y}{{3\left\{ {1 - \left( {2 \times \dfrac{1}{2}} \right)} \right\}}}$
$ \Rightarrow K = \dfrac{Y}{{3 \times 0}}$
$ \Rightarrow K = \dfrac{Y}{0}$
We know if anything is divided by zero, the answer will be infinity,
That is $K = \infty $
Final answer is option (B): infinity.
Note: Young’s modulus is a numerical constant that describes the capacity of a material to undergo a lengthwise compression or tension. It is also called the modulus of elasticity, and given by the longitudinal stress divided by the stain. Modulus of rigidity is also called the shear modulus. The value modulus of rigidity is equal to the shear stress divided by shear strain.
Complete step by step solution:
Here, we are asked to find the value of volume elasticity or the volume elasticity of the material.
Let’s discuss the terms volume modulus.
The modulus of volume is also called bulk modulus. It is a numerical constant that helps to analyze the properties of elasticity of fluid or solid when pressure is acting on all of its surfaces. The volume reduces due to the applied pressure.
It is given that the young’s modulus is equal to three times its modulus of rigidity.
That is, $Y = 3\eta $
It is known that the value of Young’s modulus is given by,
$Y = 2\eta (1 + \sigma )$
Where, $\sigma $ is the Poisson’s ratio.
Applying the value of young’s modulus we get,
$3\eta = 2\eta (1 + \sigma )$
$ \Rightarrow \sigma = \dfrac{1}{2}$
Now we are using another formula for young’s modulus to find the value of bulk modulus.
That is, $Y = 3K(1 - 2\sigma )$
Where, $K$ is the bulk modulus.
We are applying the value of Poisson’s ratio to this equation, we get,
\[Y = 3K(1 - 2\sigma )\]
$ \Rightarrow K = \dfrac{Y}{{3(1 - 2\sigma )}}$
$ \Rightarrow K = \dfrac{Y}{{3\left\{ {1 - \left( {2 \times \dfrac{1}{2}} \right)} \right\}}}$
$ \Rightarrow K = \dfrac{Y}{{3 \times 0}}$
$ \Rightarrow K = \dfrac{Y}{0}$
We know if anything is divided by zero, the answer will be infinity,
That is $K = \infty $
Final answer is option (B): infinity.
Note: Young’s modulus is a numerical constant that describes the capacity of a material to undergo a lengthwise compression or tension. It is also called the modulus of elasticity, and given by the longitudinal stress divided by the stain. Modulus of rigidity is also called the shear modulus. The value modulus of rigidity is equal to the shear stress divided by shear strain.
Recently Updated Pages
Household Electricity Important Concepts and Tips for JEE
JEE Main 2023 (January 31st Shift 1) Physics Question Paper with Answer Key
Electric Flux and Area Vector - Important Concepts for JEE
JEE Main 2023 (April 12th Shift 1) Physics Question Paper with Answer Key
Clemmensen and Wolff Kishner Reduction Important Concepts and Tips for JEE
Clemmensen and Wolff Kishner Reduction - Important Concepts and Tips for JEE
Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More
Class 11 JEE Main Physics Mock Test 2025
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements
NCERT Solutions for Class 11 Physics Chapter 9 Mechanical Properties of Fluids
Units and Measurements Class 11 Notes: CBSE Physics Chapter 1
NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
NCERT Solutions for Class 11 Physics Chapter 7 Gravitation