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Unit Cell Packing Efficiency

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What Is Unit Cell Packing Efficiency?

A Unit Cell may be viewed as a 3-D Structure made up of one or more atoms. Some void space is always present irrespective of the type of packing the cell has. The fraction of total space that is filled with the inherent constituent particles of a particular cell or structure is called the packing fraction. It can be obtained by dividing the total volume occupied by constituent particles by the cell's total volume.

 

When this is shown as a percentage i.e., out of the total space, the percentage that is held up by constituent particles is called the Packing Efficiency of a Unit Cell.

 

Packing Efficiency Formula = \[\frac{\text{No of Atoms x Volume Occupied by 1 atom}}{\text{Total Volume of Unit Cell}}\] X 100

 

We can say that Packing Fraction, when multiplied by 100, is seen as a percentage, it becomes the Packing Efficiency of that particular cell.

 

So, how to find the packing fraction:

Packing Fraction Formula =\[\frac{\text{Volume Occupied by all constituent particles}}{\text{Total Volume of Unit Cell}}\] 

 

There is always some space inside a cell, and this is known as Void Space. It can be derived as follows:

 

Void Space Fraction: 1- Packing Fraction

 

Percentage of Void Space: 100 - Packing Efficiency

 

Packing Efficiency of a Simple Cubic Crystal Lattice (SCC)


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In a simple cubic crystal structure, particles are located only on the corners of the cube. The following relation gives the edge or side length of the cube(a) and radius(r) of constituent particles:

 

a = 2r

 

A Simple Cubic Crystal contains only single atom and hence the Volume Occupied by atoms is given as: 

 

The Volume of Cube = a3 i.e. (2r)3 = 8r3    

 

Therefore, Packing Efficiency = \[\frac{4\pi r^{3}}{3\times 8r^{3}}\] X 100

 

It totals to 52.4% while Void Space Percentage is 47.6%

 

It highlights that a Simple Cubic Crystal Lattice is Loosely Bound.

 

Packing Efficiency of Body Centred Cubic Lattice


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In this kind of structure, the particles are present at the edges, and a single particle is present in the centre as well. We can calculate the packing efficiency as follows:

 

When Side is ‘a’ and Radius is ‘r’:     r =  \[\frac{\sqrt{3}}{4}\] a

 

It contains two atoms and area occupied by one atom is  \[\frac{4\pi r^{3}}{3}\] 

 

The volume of the cell in terms of 'r' is:    =  \[\frac{64r^{3}}{3\sqrt{3}}\]

 

BCC Packing Efficiency = 68.04%

 

The packing fraction of BCC is \[\frac{68}{100}\].

 

32% of the total Volume remains void.

 

Packing Efficiency of Hexagonal Close Packing (HCP) and Cubic Close Packing (CCP)


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Both the Hexagonal Close Packing (HCP) and Cubic Close Packing (CCP) structure have the same packing efficiency. The relationship between side represented as 'a' and radius is represented as 'r' is given as:

 

a = 2\[\sqrt{2}\]r

 

These structures are also face-centered cubic lattice and have atoms situated on the eight corners of the cube and the center.

 

The Volume in terms of 'r' can be, given as: 

 

(\[2\sqrt{2}r)^{3}\] = 16\[\sqrt{2}\]\[r^{3}\]

 

Packing Efficiency of CCP = \[\frac{4\times (\frac{4\pi r^{3}}{3})}{16\sqrt{2}r^{3}}\] X 100 = 74%

 

Packing fraction of HCP and FCC -  \[\frac{74}{100}\]

 

Leaving only 26% Void Space

 

Therefore, we can Summarize:


Type of Structure

Number of Atoms

‘a’ and ‘r’ Relationship

Packing Efficiency

Void Space 

Scc

1

a = 2r

52.4%

47.6%

Bcc

2

r = \[\frac{(\sqrt{3})}{4}\]a

68.04%

31.96%

Hcp and Ccp – Fcc

4

a = \[2\sqrt{2}r\]

74%

26%

 

How To Mathematically Find The Relationship Between 'a' And 'r.'?

 

In a Simple Cubic Structure:

Since the atoms are only on the corners, radius becomes half the side ,i.e., r = \[\frac{a}{2}\]

 

In a Body Centred Cubic Structure:

In this case, since atoms are on the corners and an atom is present in the center, we draw a diagonal, and its length (c) can be calculated using Pythagoras theorem.

 

We get c = \[\sqrt{3}a\]

 

And since radius = 4 X Diagonal (as shown in the figure under Body Centred Cubic Lattice)

 

r = \[4\sqrt{3}a\]

 

In hcp and ccp i.e., Face Centred Cubic Structure

Again, we draw the face diagonal and as shown in the figure,

 

b = \[\sqrt{2}a\]

 

r = \[\frac{d\times b}{4}\] 

 

It finally gives us: a = 2\[\sqrt{2r}\] 

 

Unit Cell Packing Efficiency

Unit cell can be defined as a three-dimensional structure that is made of one or more than one atom. Even when there is packing in the cell, a certain void is present in it. The space is filled by other constituents or particles. The fraction of total space that is filled with the particular cell or structure is called the packing fraction. This can be obtained by dividing the volume of the constituent particles filled in the space by the total volume of the cell. When it is represented as a percentage then the percentage of the space applied by the constituent particles out of the total space present in the structure is called the packing efficiency of the unit cell.


A lattice is largely made of a number of unit cells in which the lattice point is filled or occupied by a constituent particle. This unit cell of the lattice is a three-dimensional structure that has one or more atoms and also void spaces irrespective of the packing present. The cubic closed packed or ccp and the hexagonal closed packed or hcp are two efficient lattices when we consider packing. The packing efficiency of both of these is 74% which means 74% of the space is filled. For a simple cubic lattice, the packing efficiency is 52.4% and the packing efficiency is 68% for a body-centered cubic lattice or bcc.

FAQs on Unit Cell Packing Efficiency

1. What is unit cell packing efficiency and why is it important for students to understand?

Packing efficiency is the percentage of the total volume of a unit cell that is actually occupied by the constituent particles (atoms, ions, or molecules). It's a fundamental concept in solid-state chemistry because it helps determine the structure and properties of a solid. Understanding it allows you to predict a solid's density, stability, and how tightly its atoms are bonded together.

2. What is the general formula used to calculate the packing efficiency of a crystal lattice?

The formula to calculate packing efficiency for any unit cell is:

Packing Efficiency = (Volume occupied by all atoms in the unit cell / Total volume of the unit cell) × 100

This can also be expressed as:

Packing Efficiency = [ (Z × (4/3)πr³) / a³ ] × 100

Where:

  • Z is the number of atoms per unit cell.
  • r is the radius of the atom.
  • a is the edge length of the unit cell.

3. What is the packing efficiency of a Simple Cubic (SC) unit cell?

The packing efficiency of a Simple Cubic (SC) unit cell is 52.4%. This is the least efficient of the cubic packing structures, meaning it has the largest amount of empty space (voids), which accounts for 47.6% of the total volume. This loose packing is due to atoms being present only at the corners of the cube.

4. What is the packing efficiency of a Body-Centred Cubic (BCC) unit cell?

The packing efficiency of a Body-Centred Cubic (BCC) unit cell is 68%. This structure is more efficiently packed than a simple cubic lattice because, in addition to atoms at the eight corners, there is one atom at the very centre of the cube. This leaves a void space of 32%.

5. What is the packing efficiency for Face-Centred Cubic (FCC) and Cubic Close-Packed (CCP) structures?

The packing efficiency for both Face-Centred Cubic (FCC) and Cubic Close-Packed (CCP) structures is 74%. This is the highest possible packing efficiency for spheres of equal size. In this arrangement, atoms are located at the corners and at the centre of each of the six faces of the cube, leaving only 26% as void space.

6. How does the relationship between the edge length (a) and atomic radius (r) influence the packing efficiency in different cubic cells?

The relationship between the edge length 'a' and atomic radius 'r' is crucial because it directly connects the atomic dimensions to the unit cell's volume in the packing efficiency formula. The relationship varies for each structure:

  • For a Simple Cubic (SC) lattice, atoms touch along the edge, so a = 2r.
  • For a Body-Centred Cubic (BCC) lattice, atoms touch along the body diagonal, leading to the relationship a = 4r / √3.
  • For a Face-Centred Cubic (FCC) lattice, atoms touch along the face diagonal, giving the relationship a = 4r / √2 or a = 2√2r.

These distinct relationships are the mathematical reason why each structure has a different packing efficiency.

7. Why do FCC and Hexagonal Close-Packed (HCP) structures have the same packing efficiency of 74%?

Although FCC (with an ABCABC... stacking pattern) and HCP (with an ABABAB... stacking pattern) have different three-dimensional arrangements, they share the same maximum packing efficiency of 74%. This is because, in both structures, each sphere is in contact with 12 other spheres (a coordination number of 12). The local environment and the way layers are packed are optimised for minimum empty space, resulting in the same density of packing, regardless of the long-range stacking sequence.

8. How is the coordination number of a crystal structure related to its packing efficiency?

The coordination number, which is the number of nearest neighbouring atoms touching a single atom, is directly related to packing efficiency. A higher coordination number means atoms are packed more closely together, which generally leads to a higher packing efficiency and greater stability. This trend is clear in cubic systems:

  • SC: Coordination Number = 6, Packing Efficiency = 52.4%
  • BCC: Coordination Number = 8, Packing Efficiency = 68%
  • FCC/CCP: Coordination Number = 12, Packing Efficiency = 74%

9. Based on packing efficiency, which crystal structure is the most stable and why?

Based solely on packing efficiency, the Face-Centred Cubic (FCC) or Cubic Close-Packed (CCP) structure is the most stable. The stability hierarchy is: FCC (74%) > BCC (68%) > SC (52.4%). A higher packing efficiency indicates that the atoms are more closely packed, maximising the attractive forces between them and minimising the volume of empty space. This dense packing results in a lower potential energy state, which corresponds to greater thermodynamic stability.

10. What is the physical significance of the void space that is not covered in packing efficiency?

The empty or void space not accounted for by packing efficiency is physically significant. These voids, known as interstitial sites (e.g., tetrahedral and octahedral voids), are not just empty space. They can be occupied by smaller atoms to form interstitial alloys (like steel, where carbon atoms occupy voids in the iron lattice). The size, number, and location of these voids also influence a crystal's properties, such as its ability to accommodate defects and its diffusion characteristics.