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Class 11 Physics Determine Radius Of Curvature Of A Given Spherical Surface By A Spherometer Experiment

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An Overview of Class 11 Physics Determine Radius Of Curvature Of A Given Spherical Surface By A Spherometer Experiment

Ever wondered how the glasses you wear are made to match your eyes perfectly? In Class 11 Physics Determine Radius Of Curvature Of A Given Spherical Surface By A Spherometer Experiment, you’ll find out how a spherometer helps us measure the curve of round objects like lenses. This simple tool becomes your key to understanding real-world measurements that can’t be done with a ruler!


Many students find experiments confusing at first, but with Vedantu’s important questions and step-by-step solutions, you’ll see how to use the spherometer easily and get confident for your practicals. You can also check out the latest syllabus on Class 11 Physics Syllabus if you want a complete idea of what chapters you need to cover this year.


Practice from the curated list on Class 11 Physics Important Questions and get ready to ace both your board exams and lab work!


Introduction

Most of us wearing spectacles require at some point of time or the other to go to the optician, who examines the suitable lens and prescribes another pair effectively. But how does this task get carried out? A spherometer is capable of examining a regular curved surface and determining its radius of curvature using the known formula. These measurements are not possible to be measured with conventional measuring scales and, therefore, the use of a spherometer is vital for such measurements. Let us dive in detail on a hands-on of this simple experiment.


Table of Contents

  • Aim

  • Procedure

  • Observations

  • Results


Aim

To determine the radius of curvature of a given spherical surface by a spherometer.


Apparatus required

  • Curved surface

  • Spherometer

  • White paper sheet

  • Pencil 

  • Ruler

  • Flat glass plate or plane mirror


Theory

As a spherometer is placed upon a curved surface convex to the height, its central screw touches the optical centre of the surface, while its legs touch the outer boundaries which are comparatively flat. This causes a difference in heights experienced by the central screw compared to that of the legs, which is readily measured using the main scale of the spherometer. This value combined with the average leg separation of the spherometer is incorporated into a formula, giving the accurate radius of curvature of the given surface.


Procedure

  1. Keep the spherometer on a white sheet of paper on its three legs. Press the spherometer so that the pointed legs leave a slight mark on the paper.

  2. Release the spherometer and rotate the circular scale to the maximum range till the central screw begins to touch the base, the same plane as the legs.

  3. Ensure that at this position, the zero of the circular scale coincides with the zero of the main scale. If it does not, note the main scale division with which the circular scale coincides.

  4. Rotate the circular scale once and note the distance covered by it on the main scale. This is the pitch.


A Spherometer Consists of Three Coplanar Legs and a Circular Scale


A Spherometer Consists of Three Coplanar Legs and a Circular Scale.


  1. Note the number of divisions on the circular scale and divide the pitch of the spherometer with this. This is the least count.

  2. Lift-off the spherometer from the paper sheet and pinpoint the leg marks as A, B and C using a pencil. Join the points to form an equilateral triangle ABC using a ruler.

  3. Measure AB, BC and AC using a ruler. Note the values.

  4. Now put the given curved surface on a plain glass slab or a plane mirror with the bulging face of the surface outwards. 

  5. Put the spherometer on the surface and adjust the central screw such that it touches at the center of the surface gently while the spherometer legs touch the points on the surface equidistant from the center.

  6. Note the main scale division corresponding to the circular scale. This is main scale reading.

  7. Note the circular scale division which coincides with the main scale. This is circular scale reading.

  8. Note both the readings for the surface in a similar fashion two other times. Tabulate the observations.


Observations

Pitch of the spherometer = 

Number of divisions on circular scale = 

Least count = \[\dfrac{{Pitch}}{{Divisions\;on\;circular\;scale}}\]

Using centimeter scale,

Length AB = 

Length BC = 

Length AC = 

Average leg separation, L = \[\dfrac{{AB + BC + AC}}{3}cm\]


Observation Table

Sr-No

Main Scale Reading

(cm)

Circular Scale Divisions Coinciding

Circular Scale Reading 

= \[Divisions \times Least\;Count\]

(cm)

Total Reading

(cm)

1





2





3






Results

The average height of the curved surface=

Average reading, H = \[\dfrac{{Sum\;of\;readings}}{3}\] =

Using the spherometer formula

\[\dfrac{{{L^2}}}{{6H}} + \dfrac{H}{2}\]

where R = Radius of curvature of the given curved surface

L = Average leg separation

H = Average height of the surface

Putting the values of L and H obtained above, the value of R =


Precautions

  1. Determine the leg separation very carefully by gently pressing the spherometer against the paper sheet.

  2. Ensure to add/subtract the zero error in the final reading.

  3. Determine the pitch very carefully from one rotation.


Lab Manual Questions

1. Does a given object have the same radius of curvature on its both surfaces (i.e. does the thickness of an object plays a role in radius of curvature)?

Ans: No, an object of considerable thickness does not have the same values of radius of curvature on its both surfaces. This is because the finite difference of the distances between the reference of measurement and the object's apparent surface due to thickness causes a finite error in measurement of the height as measured by the spherometer.


2. Name some commercial applications of a spherometer.

Ans: Spherometers are used to measure the radius of curvature of curved surfaces such as balls, optical lenses, mirrors, etc.


3. What is the least count of a spherometer?

Ans: The least count of a spherometer is 0.01 mm. It is the minimum length precisely measured by the spherometer and is obtained by dividing the pitch (1 mm) by the number of circular scale divisions (100).


4. Which instrument would be precise for measuring thickness of a card sheet – a screw gauge or a spherometer?

Ans: For measuring the thickness of a card sheet, a screw gauge would be more precise over a spherometer because a screw gauge is ideal for measuring small linear distances, whereas a spherometer is ideal for measuring the radius of curvature of a curved surface which is not a linear distance as the thickness of a card sheet.


Viva Questions

1. Name the material used for the construction of a spherometer.

Ans: A spherometer is made using stainless steel, copper and iron to make it durable and the readings engraved do not go off soon after usage.


2. What is the pitch of a spherometer?

Ans: The pitch of a spherometer is defined as the distance covered by the circular scale over the main scale on one complete rotation of the circular scale. It is roughly 1 mm.


3. Give the final calculation formula for the spherometer.

Ans: It is given by:

\[\dfrac{{{L^2}}}{{6H}} + \dfrac{H}{2}\]

where R = Radius of curvature of the given curved surface

L = Average leg separation

H = Average height of the surface


4. How does a spherometer differ from a vernier calliper/screw gauge?

Ans: A spherometer is used for the precise determination of radius of curvature of a given curved surface, whereas a vernier calliper/screw gauge is used for measuring very fine linear distances of the order of the diameter of a fine wire or the thickness of a sheet.


5. Explain the zero error of a spherometer. How to check it?

Ans: The zero error of a spherometer arises when the zero of the circular scale does not coincide with the zero of the main scale, causing an additional distance error. To check it, note the main scale division at which the circular scale coincides at the full range of the circular scale when all the four legs of the spherometer lie in the same plane on a base.


6. Give the formula for calculating the least count of the spherometer.

Ans: The least count of a spherometer can be calculated by dividing the distance traveled by the circular scale in one complete rotation along the main scale by the number of divisions on the circular scale.


7. Give three commercial uses of the spherometer.

Ans: The three commercial uses of a spherometer are as follows:

  1. To measure the thickness of a micrometer chip.

  2. To measure the elevation or depression in a slide.

  3. To measure the curvature of a curved surface in aerodynamics.


8. Name the ideal quantity a spherometer is suitable for measuring.

Ans: A spherometer is ideally suitable for measuring the radius of curvature of a given curved surface using the surface elevation. This finds many applications such as in getting the right curvature for a given surface for critical engineering and medical purposes.


9. Explain the working principle of a spherometer.

Ans: A spherometer is based on the principle of a rotating screw. As the screw rotates, it covers a linear distance on the main scale. The difference between the levels of planes in which the legs and the central screw lie gives the estimate of the required curvature of the surface.


10. How many markings are there on the circular scale on a spherometer?

Ans: There are 100 markings on the circular scale on a spherometer.


Practical Based Questions

1. The least count of a spherometer is given by:

  1. 1 mm

  2. 0.1 mm

  3. 0.01 mm

  4. 0.001 mm

Ans: (C)


2. How many legs are there in a spherometer?

  1. 3

  2. 2

  3. 1

  4. 4

Ans: (A)


3. How many scales does a spherometer have?

  1. 2

  2. 3

  3. 5

  4. 6

Ans: (A)


4. The ratio of the least counts of the centimeter scale to that of a spherometer is:

  1. 1

  2. 10

  3. 100

  4. 1000

Ans: (C)


5. A spherometer can be used to accurately measure:

  1. Edge of a dice

  2. Thickness of a wire

  3. Length of a notebook

  4. Radius of curvature

Ans: (D)


6. State the value of radius of curvature of plane mirror:

  1. Zero

  2. 10 m

  3. 1 km

  4. Infinite

Ans: (D)


7. The error that arises when the zeroes of the main scale and the circular scale do not coincide is called:

  1. Systematic error

  2. Random error

  3. Backlash error

  4. Zero error

Ans: (D)


8. Accuracy of measurement can be increased by:

  1. Increasing the number of divisions on circular scale

  2. Using a magnifying glass

  3. Using a thick wire for measuring diameter

  4. Using more circular scales

Ans: (A)


9. How many types of zero errors are there?

  1. One

  2. Two

  3. Three

  4. Four

Ans: (B)


10. A spherometer is not suitable for measuring:

  1. Radius of curvature

  2. Elevation in a curved sheet

  3. Diameter of a vessel

  4. Depression in a curved sheet

Ans: (C)


Conclusion

From this experiment, we can conclude that the spherometer finds immense applications in the field of experimental physics in order to accurately measure the radius of curvature of curved surfaces, find the elevation/ depression of a given surface, etc. using its simplified formula. It finds various commercial applications in numerous engineering and medical fields in the society for the same. We have covered all the basic and fundamental concepts related to the spherometer along with its important commercial applications. 


We hope that the reader is sufficiently enlightened regarding the very concept of the spherometer and is motivated to explore the field in the time to come.

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FAQs on Class 11 Physics Determine Radius Of Curvature Of A Given Spherical Surface By A Spherometer Experiment

1. What are the most important steps to follow while determining the radius of curvature with a spherometer to ensure an accurate reading for the exam?

To ensure an accurate reading in the Class 11 Physics practical exam, you must follow these crucial steps: First, determine the pitch and least count of the spherometer. Next, find the zero reading by placing the spherometer on a plane glass plate. Then, place it on the curved surface and measure the sagitta (h). Finally, measure the average distance between the outer legs (l) by pressing them on paper to get an impression. Following these steps systematically is key to obtaining reliable results and full marks.

2. For your viva, how would you define the pitch and least count of a spherometer, and why are these values important?

For a viva voce, you should define them as follows:

  • Pitch: The pitch is the vertical distance moved by the central screw when the circular disc is rotated by one complete revolution (360°). It is usually 1 mm.
  • Least Count (L.C.): The least count is the smallest distance that can be measured accurately by the instrument. It is calculated by dividing the pitch by the total number of divisions on the circular scale.
These values are critically important because they determine the precision of your measurement. The final reading of the sagitta (h) is calculated using the least count, so any error in determining the L.C. will lead to an incorrect final result for the radius of curvature.

3. State the important formula used to calculate the radius of curvature (R) and explain the terms 'l' and 'h'.

The formula to determine the radius of curvature (R) of a spherical surface as per the CBSE Class 11 syllabus is:
R = (l² / 6h) + (h / 2)
In this formula:

  • l represents the average distance between any two outer legs of the spherometer.
  • h represents the sagitta, which is the perpendicular distance between the plane of the outer legs and the tip of the central screw when it touches the centre of the spherical surface.

4. What is backlash error in a spherometer, and what is the correct procedure to avoid it during the practical exam?

Backlash error is a common instrumental error that occurs due to wear and tear in the screw-nut mechanism. It is observed when the direction of rotation of the screw is reversed, causing the screw to turn without any corresponding vertical movement. To avoid this error during the exam, you should always rotate the screw in the same direction (preferably clockwise) when taking the final measurement. If you overshoot the mark, rotate it back a full turn and approach the point again from the same direction.

5. Why is it necessary to measure the distance 'l' on a flat surface instead of on the curved surface itself?

The distance 'l' in the formula for the radius of curvature represents the side of the equilateral triangle formed by the three legs in a horizontal plane. This is a straight-line distance. If you were to measure it along the curved surface, you would be measuring an arc length, which is longer than the required straight-line chord length. Using an incorrect, longer value for 'l' would lead to a significant error in the final calculated radius of curvature (R), making the result inaccurate.

6. For which types of surfaces is a spherometer a more suitable measuring instrument than a vernier caliper?

A spherometer is specifically designed to measure very small curvatures, making it ideal for surfaces like convex lenses, concave mirrors, or watch glasses. A vernier caliper, on the other hand, is designed to measure linear dimensions like length, diameter, or depth. It cannot measure the slight height difference (sagitta) required to calculate the radius of curvature. Therefore, for determining the curvature of a spherical surface, a spherometer is far more suitable and precise.

7. What are two significant sources of error in the spherometer experiment, other than backlash error, that can affect your marks?

Besides backlash error, two other important sources of error are:

  • Zero Error: This occurs if the tip of the central screw and the plane of the three outer legs are not perfectly aligned when placed on a flat surface. This can be positive or negative and must be accounted for in the final calculation.
  • Non-uniformity of the Screw: If the pitch of the screw is not uniform throughout its length, the readings will be inconsistent. This is a manufacturing defect and can be minimised by taking readings at different parts of the surface and averaging them.

8. How would a blunt or worn-out central screw tip affect the final result of the experiment?

A blunt or worn-out central screw tip would introduce a significant error. The formula for the radius of curvature assumes a perfect point contact between the screw tip and the spherical surface. A blunt tip creates an area of contact, not a point. This prevents the screw from reaching the true deepest or highest point of the curve, leading to an inaccurate measurement of the sagitta (h). This inaccuracy directly affects the calculation, resulting in an incorrect value for the radius of curvature (R).