![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
The position of the axis of rotation of a body is changed so that its moment of inertia decreases by \[36\% \]. Find the percentage change in its radius of gyration.
A) It decreases by $18\% $
B) It increases by $18\% $
C) It decreases by $20\% $
D) It increases by $20\% $
Answer
477.3k+ views
Hint:The radius of gyration, $k = \sqrt {\dfrac{I}{M}} $ . Let, the initial moment of inertia is ${I_1} = M{k_1}^2$ and the final moment of inertia is ${I_2} = M{k_2}^2$. Also, ${k_2} = 0.8{k_1}$ and ${k_1} > {k_2}$.
Complete step by step answer:
Moment of inertia of a body about an axis of rotation is defined as the torque acting on the body divided by the corresponding angular acceleration thus generated about the same axis of rotation. So, moment of inertia not only depends on the mass of a body, but also depends on the distance of the particles constituting the body from the axis of rotation, i.e., on the distribution of mass of the body. Now, if the whole mass of a body is assumed to be concentrated at a point such that the moment of inertia of the whole body equals the moment of inertia of that point, then the distance of the point from the axis of rotation is called the radius of gyration.
So, if the mass of an extended body is $M$ and its moment of inertia about an axis of rotation is $I$, then the radius of gyration, $k = \sqrt {\dfrac{I}{M}} $ or, $I = M{k^2}$
Let, the initial moment of inertia is ${I_1} = M{k_1}^2$ and the final moment of inertia is ${I_2} = M{k_2}^2$
According to the question, the initial moment of inertia decreases by $36\% $
$\therefore {I_2} = {I_1} - \dfrac{{36{I_1}}}{{100}} = {I_1} - 0.36{I_1} = 0.64{I_1}$
So, ${I_2} = 0.64{I_1}$ or, $M{k_2}^2 = 0.64M{k_1}^2$
or, ${k_2}^2 = 0.64{k_1}^2$
or, ${k_2} = 0.8{k_1}$ [So, ${k_1} > {k_2}$ ]
So, the change in radius of gyration is $\dfrac{{{k_1} - {k_2}}}{{{k_1}}} \times 100 = \dfrac{{{k_1} - 0.8{k_1}}}{{{k_1}}} \times 100 = \dfrac{{0.2{k_1}}}{{{k_1}}} \times 100 = 20$
So, the radius of gyration decreases by $20\% $.
Note:
In case of rotational motion, a body is compelled to change its state of motion, when an external torque acts on it. In absence of external torque, the body either remains at rest or executes uniform circular motion. It means that the moment of inertia of a body can be called its rotational inertia. It resists any change in the rotational motion of the body and it is clear that more the moment of inertia of a body about an axis, more the torque necessary to rotate the body about that axis.
Complete step by step answer:
Moment of inertia of a body about an axis of rotation is defined as the torque acting on the body divided by the corresponding angular acceleration thus generated about the same axis of rotation. So, moment of inertia not only depends on the mass of a body, but also depends on the distance of the particles constituting the body from the axis of rotation, i.e., on the distribution of mass of the body. Now, if the whole mass of a body is assumed to be concentrated at a point such that the moment of inertia of the whole body equals the moment of inertia of that point, then the distance of the point from the axis of rotation is called the radius of gyration.
So, if the mass of an extended body is $M$ and its moment of inertia about an axis of rotation is $I$, then the radius of gyration, $k = \sqrt {\dfrac{I}{M}} $ or, $I = M{k^2}$
Let, the initial moment of inertia is ${I_1} = M{k_1}^2$ and the final moment of inertia is ${I_2} = M{k_2}^2$
According to the question, the initial moment of inertia decreases by $36\% $
$\therefore {I_2} = {I_1} - \dfrac{{36{I_1}}}{{100}} = {I_1} - 0.36{I_1} = 0.64{I_1}$
So, ${I_2} = 0.64{I_1}$ or, $M{k_2}^2 = 0.64M{k_1}^2$
or, ${k_2}^2 = 0.64{k_1}^2$
or, ${k_2} = 0.8{k_1}$ [So, ${k_1} > {k_2}$ ]
So, the change in radius of gyration is $\dfrac{{{k_1} - {k_2}}}{{{k_1}}} \times 100 = \dfrac{{{k_1} - 0.8{k_1}}}{{{k_1}}} \times 100 = \dfrac{{0.2{k_1}}}{{{k_1}}} \times 100 = 20$
So, the radius of gyration decreases by $20\% $.
Note:
In case of rotational motion, a body is compelled to change its state of motion, when an external torque acts on it. In absence of external torque, the body either remains at rest or executes uniform circular motion. It means that the moment of inertia of a body can be called its rotational inertia. It resists any change in the rotational motion of the body and it is clear that more the moment of inertia of a body about an axis, more the torque necessary to rotate the body about that axis.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How many valence electrons does nitrogen have class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)