Answer
Verified
455.4k+ views
Hint As temperature increases of a wire, it’s resistance also increases. We are having a relation given for change in resistance with respect to temperature. So we can get a solution using this equation.
Complete step by step answer
The temperature dependence of the resistance in the question is given as
$ \Rightarrow R = {R_0}\left( {1 + \alpha \Delta T} \right) $
Now, according to the question, we have $ {R_0} = 100\Omega $, $ R = 150\Omega $, $ {T_0} = {27^ \circ }C $, and $ T = {227^ \circ }C $ .
So, $ \Delta T = T - {T_0} $
$ \Rightarrow \Delta T = {227^ \circ }C - {27^ \circ }C = {200^ \circ }C $
Putting these values in (1) we get
$ \Rightarrow 150 = 100\left( {1 + 200\alpha } \right) $
$ \Rightarrow 200\alpha = 0.5 $
On solving we get
$ \Rightarrow \alpha = 2.5 \times {10^{ - 4}}{/^ \circ }C $
This value matches with the value given in the Statement 1.
But while deriving the expression for the variation of the resistance with the temperature, it is assumed that the change in temperature is very small. But in this case, the change in temperature is
$ \Rightarrow \Delta T = {200^ \circ }C $
This is a quite large value.
Also, while the derivation of the equation (1) is carried out, it is assumed that the change in resistance is very small compared to the original value, that is
$ \Rightarrow \left( {R - {R_0}} \right) < < {R_0} $
But in this case the change in resistance
$ \Rightarrow \left( {R - {R_0}} \right) = 150 - 100 $
$ \Rightarrow \left( {R - {R_0}} \right) = 50\Omega $
Which is comparable to the original value of resistance. So the above equation (1) cannot be applied to this case. Thus the value of $ \alpha $ which is obtained above is incorrect.
Thus the Statement 1 is False.
Also the Statement 2 is True at the same time due to the reasons already stated above.
Hence the correct answer is option D.
Note
Do not blindly jump to the conclusion that Statement 1 is correct after getting the value of $ \alpha $ same as that given in the Statement. That value is intentionally given to be the same. The question basically wants to judge the knowledge of the concept mentioned in the Statement 2.
Complete step by step answer
The temperature dependence of the resistance in the question is given as
$ \Rightarrow R = {R_0}\left( {1 + \alpha \Delta T} \right) $
Now, according to the question, we have $ {R_0} = 100\Omega $, $ R = 150\Omega $, $ {T_0} = {27^ \circ }C $, and $ T = {227^ \circ }C $ .
So, $ \Delta T = T - {T_0} $
$ \Rightarrow \Delta T = {227^ \circ }C - {27^ \circ }C = {200^ \circ }C $
Putting these values in (1) we get
$ \Rightarrow 150 = 100\left( {1 + 200\alpha } \right) $
$ \Rightarrow 200\alpha = 0.5 $
On solving we get
$ \Rightarrow \alpha = 2.5 \times {10^{ - 4}}{/^ \circ }C $
This value matches with the value given in the Statement 1.
But while deriving the expression for the variation of the resistance with the temperature, it is assumed that the change in temperature is very small. But in this case, the change in temperature is
$ \Rightarrow \Delta T = {200^ \circ }C $
This is a quite large value.
Also, while the derivation of the equation (1) is carried out, it is assumed that the change in resistance is very small compared to the original value, that is
$ \Rightarrow \left( {R - {R_0}} \right) < < {R_0} $
But in this case the change in resistance
$ \Rightarrow \left( {R - {R_0}} \right) = 150 - 100 $
$ \Rightarrow \left( {R - {R_0}} \right) = 50\Omega $
Which is comparable to the original value of resistance. So the above equation (1) cannot be applied to this case. Thus the value of $ \alpha $ which is obtained above is incorrect.
Thus the Statement 1 is False.
Also the Statement 2 is True at the same time due to the reasons already stated above.
Hence the correct answer is option D.
Note
Do not blindly jump to the conclusion that Statement 1 is correct after getting the value of $ \alpha $ same as that given in the Statement. That value is intentionally given to be the same. The question basically wants to judge the knowledge of the concept mentioned in the Statement 2.
Recently Updated Pages
How is abiogenesis theory disproved experimentally class 12 biology CBSE
What is Biological Magnification
Master Class 9 Science: Engaging Questions & Answers for Success
Master Class 9 English: Engaging Questions & Answers for Success
Class 9 Question and Answer - Your Ultimate Solutions Guide
Master Class 9 Maths: Engaging Questions & Answers for Success
Trending doubts
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
What are the major means of transport Explain each class 12 social science CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Explain sex determination in humans with the help of class 12 biology CBSE
How much time does it take to bleed after eating p class 12 biology CBSE