State Newton's second law of motion, in terms of momentum.
Answer
654.9k+ views
HINT-The second law states that the rate of change of momentum of a body is directly proportional to
the force applied OR Force equals mass times acceleration.
COMPLETE STEP BY STEP SOLUTION
According to the second law of motion the force applied on a body is proportional to the rate of change of momentum of the body.
ie; force \[ \propto \] change in momentum with respect to time
Or \[F \propto \dfrac{{dp}}{{dt}}\] ……………………...(1)
Where p= momentum and we know that momentum is equal to the product of mass and velocity ie,P=mv
Putting the value of momentum in equation (1)
\[F \propto \dfrac{{d(mv)}}{{dt}}\]
Or \[F = \kappa \dfrac{{d(mv)}}{{dt}}\] ………………….(2)
Where k is constant of proportionality
Since k=1 and mass is considered to be constant here so then in equation (2)
\[\
F = 1m \dfrac{{dv}}{{dt}} \\
\Rightarrow F = m \dfrac{{dv}}{{dt}} \\
\ \]
Since acceleration a measurement of how quickly an object is changing speed or change in velocity with respect to time ie; \[a = \dfrac{{dv}}{{dt}}\]
Therefore F=ma and Here,
Force is directly proportional to mass and acceleration. Imagine a ball of a certain mass moving at a certain acceleration. This ball has a certain force
If you double the mass, you double the force. If you double the acceleration, you double the force.
And if you double the mass and the acceleration then,
(2m)(2a) = 4F Doubling the mass and the acceleration quadruples the force.
Note :- F = ma basically means that the force of an object comes from its mass and its acceleration
Something very massive (high mass) that’s changing speed very slowly (low acceleration), like a glacier, can still have great force
Something very small (low mass) that’s changing speed very quickly (high acceleration), like a bullet, can still have a great force. Something very small changing speed very slowly will have a very weak force
the force applied OR Force equals mass times acceleration.
COMPLETE STEP BY STEP SOLUTION
According to the second law of motion the force applied on a body is proportional to the rate of change of momentum of the body.
ie; force \[ \propto \] change in momentum with respect to time
Or \[F \propto \dfrac{{dp}}{{dt}}\] ……………………...(1)
Where p= momentum and we know that momentum is equal to the product of mass and velocity ie,P=mv
Putting the value of momentum in equation (1)
\[F \propto \dfrac{{d(mv)}}{{dt}}\]
Or \[F = \kappa \dfrac{{d(mv)}}{{dt}}\] ………………….(2)
Where k is constant of proportionality
Since k=1 and mass is considered to be constant here so then in equation (2)
\[\
F = 1m \dfrac{{dv}}{{dt}} \\
\Rightarrow F = m \dfrac{{dv}}{{dt}} \\
\ \]
Since acceleration a measurement of how quickly an object is changing speed or change in velocity with respect to time ie; \[a = \dfrac{{dv}}{{dt}}\]
Therefore F=ma and Here,
Force is directly proportional to mass and acceleration. Imagine a ball of a certain mass moving at a certain acceleration. This ball has a certain force
If you double the mass, you double the force. If you double the acceleration, you double the force.
And if you double the mass and the acceleration then,
(2m)(2a) = 4F Doubling the mass and the acceleration quadruples the force.
Note :- F = ma basically means that the force of an object comes from its mass and its acceleration
Something very massive (high mass) that’s changing speed very slowly (low acceleration), like a glacier, can still have great force
Something very small (low mass) that’s changing speed very quickly (high acceleration), like a bullet, can still have a great force. Something very small changing speed very slowly will have a very weak force
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

Draw a labelled diagram of the neuron and describe class 11 biology CBSE

