
How long would gamma radiation take to travel from sun to earth, a distance of \[1.5 \times {10^{11}}{\rm{ m}}\]?
Answer
476.4k+ views
Hint: We will use the concept of generation of the electromagnetic spectrum to determine the velocity of gamma radiation. Later, we will also use the expression of speed of gamma radiation, which is given in terms of distance traveled, and time period of gamma radiation.
Complete step by step answer:
Given:
The distance between the sun and earth is equal to \[1.5 \times {10^{11}}{\rm{ m}}\].
We know that gamma radiation is a part of the electromagnetic radiation spectrum obtained when white light is allowed to pass through a diffraction medium.
The speed of light is represented by c and is equal to \[3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}\].
We also know that gamma radiation is obtained from white light; therefore, we can say that gamma radiation's speed is equal to the speed of light.
\[
v = c\\
\Rightarrow v= 3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}
\]
The relationship of velocity, distance traveled, and time period of gamma radiation at any time instant t is expressed as:
\[
v = \dfrac{d}{t}\\
\Rightarrow t = \dfrac{d}{v}
\]
Here v is the velocity of gamma radiation, and d is the distance traveled by gamma radiation.
Substitute \[1.5 \times {10^{11}}{\rm{ m}}\] for d and \[3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}\] for v in equation (1) to get the value of time taken by gamma radiation to reach earth starting from the sun.
\[
t = \dfrac{{1.5 \times {{10}^{11}}{\rm{ m}}}}{{3 \times {{10}^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}}}\\
\therefore t = 500{\rm{ s}}
\]
Therefore, the time taken by gamma radiation to travel from the sun to earth is equal to \[500{\rm{ s}}\].
Note: In the solution, we need the velocity of gamma radiation, which is unknown, so do not confuse how to find it as it is equal to the speed of light because gamma radiation is a part of the electromagnetic spectrum of light.
Complete step by step answer:
Given:
The distance between the sun and earth is equal to \[1.5 \times {10^{11}}{\rm{ m}}\].
We know that gamma radiation is a part of the electromagnetic radiation spectrum obtained when white light is allowed to pass through a diffraction medium.
The speed of light is represented by c and is equal to \[3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}\].
We also know that gamma radiation is obtained from white light; therefore, we can say that gamma radiation's speed is equal to the speed of light.
\[
v = c\\
\Rightarrow v= 3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}
\]
The relationship of velocity, distance traveled, and time period of gamma radiation at any time instant t is expressed as:
\[
v = \dfrac{d}{t}\\
\Rightarrow t = \dfrac{d}{v}
\]
Here v is the velocity of gamma radiation, and d is the distance traveled by gamma radiation.
Substitute \[1.5 \times {10^{11}}{\rm{ m}}\] for d and \[3 \times {10^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}\] for v in equation (1) to get the value of time taken by gamma radiation to reach earth starting from the sun.
\[
t = \dfrac{{1.5 \times {{10}^{11}}{\rm{ m}}}}{{3 \times {{10}^8}{{\rm{m}} {\left/
{\vphantom {{\rm{m}} {\rm{s}}}} \right.
} {\rm{s}}}}}\\
\therefore t = 500{\rm{ s}}
\]
Therefore, the time taken by gamma radiation to travel from the sun to earth is equal to \[500{\rm{ s}}\].
Note: In the solution, we need the velocity of gamma radiation, which is unknown, so do not confuse how to find it as it is equal to the speed of light because gamma radiation is a part of the electromagnetic spectrum of light.
Recently Updated Pages
Master Class 12 Social Science: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
The gas that burns in oxygen with a green flame is class 12 chemistry CBSE

The probability that a leap year will have only 52 class 12 maths CBSE

Describe the poetic devices used in the poem Aunt Jennifers class 12 english CBSE

And such too is the grandeur of the dooms We have imagined class 12 english CBSE

What does the god that failed refer to class 12 english CBSE

Which country did Danny Casey play for class 12 english CBSE
