Answer
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Hint: Transistor is a current control and voltage source device.
Complete step by step solution:
The Field Effect Transistor is a device controlled by voltage because the drain current depends on the negative voltage applied at the gate. On the other hand, the BJT (Bipolar Junction Transistor) is a current-controlled device, as the current from the collector depends on the base current.
Bipolar junction transistors are "Current Operated Devices" in which a much smaller base current causes a larger Emitter to flow to the Collector current, which is almost equal in itself. The arrow in a transistor symbol stands for conventional current flow.
The base current is very small as compare to the collector current and we get them out in volt. Therefore the ${I_{B\,}}$ is in ${\rm{\mu A}}$ and ${I_C}$ is in ${\rm{mA}}$ and ${V_{CE}}$ in volt. The correct option is B.
Note: Base current is input current which is very small i.e. in the order of ${\rm{\mu A}}$and collector current is much larger then base current i.e. in the order of ${\rm{mA}}$. And we get the output voltage across the collector emitter-base in volt i.e. in ${V_{CE}}$.
Complete step by step solution:
The Field Effect Transistor is a device controlled by voltage because the drain current depends on the negative voltage applied at the gate. On the other hand, the BJT (Bipolar Junction Transistor) is a current-controlled device, as the current from the collector depends on the base current.
Bipolar junction transistors are "Current Operated Devices" in which a much smaller base current causes a larger Emitter to flow to the Collector current, which is almost equal in itself. The arrow in a transistor symbol stands for conventional current flow.
The base current is very small as compare to the collector current and we get them out in volt. Therefore the ${I_{B\,}}$ is in ${\rm{\mu A}}$ and ${I_C}$ is in ${\rm{mA}}$ and ${V_{CE}}$ in volt. The correct option is B.
Note: Base current is input current which is very small i.e. in the order of ${\rm{\mu A}}$and collector current is much larger then base current i.e. in the order of ${\rm{mA}}$. And we get the output voltage across the collector emitter-base in volt i.e. in ${V_{CE}}$.
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