Question

How ${{H}_{2}}S{{O}_{4}}+NaOH$ could be $N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O$ and how to balance it?

Answer 1

Hint: Sulphuric acid is a strong acid and Sodium hydroxide is a strong base, so consider the reaction between a strong base and strong acid. And balancing a chemical equation refers to the method by which we balance the number of atoms present in the reactant side and in the product side.

Complete answer:
So in the question it is asked that how $N{{a}_{2}}S{{O}_{4\,}}$ and ${{H}_{2}}O$ is formed, when ${{H}_{2}}S{{O}_{4}}$ and NaOH reacts together. And we have to balance out the equation. First we should have the idea about the reactants that are undergoing the chemical change and the products formed.
Here the reactants in the reaction are sulphuric acid which is one of the strongest acids and the other reactant is NaOH which is a strong base. And the product formed is salt and water, salt formed by the combination of sodium ion and sulphate ion.
Since the reaction is happening between a strong base and the strong acid, the product formed will be salt and water and we call this type of reaction a neutralization reaction.
And the equation for the reaction is as follows:
${{H}_{2}}S{{O}_{4}}+NaOH\to N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O$
Now we have to balance the chemical equation.
First let first make a table with the number of atoms on both sides of the reaction i.e. reactant side and product side.

Atoms	Reactant side	Product side
Na	1	2
S	1	1
O	5	5
H	3	2

So here we have to balance Na and H let us first start with Na, give 2 as the coefficient for NaOH.
${{H}_{2}}S{{O}_{4}}+2NaOH\to N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O$
Now in the reactant side there is 4 H atoms, for balancing H give 2 as coefficient value for ${{H}_{2}}O$
${{H}_{2}}S{{O}_{4}}+2NaOH\to N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O$
Now the equation is a balanced chemical equation.

Note:
The above given neutralization also can be considered as a displacement reaction, in which the ions are exchanged between the reactants to form the new species. Caution should be taken care while balancing the equation which has polyatomic species, and the subscript associated with the atoms should not be changed, since it changes the stoichiometry of the molecule.