
Explain the principle of potentiometer.
Answer
608.4k+ views
Hint: In this question use the concept that potentiometer helps establish the relationship between the potential drop (say emf) and the length across which the potential drop is to be measured. This will help understand the principle on which potentiometer works.
Complete Step-by-Step solution:
Principle of potentiometer:
The principle of potentiometer is that, for a wire having uniform area of cross section, the potential drop in the wire is directly proportional to its length.
The above principle is valid only when the potentiometer is used in comparing the EMF of two cells.
For example:
Consider two potentiometers the length of the first potentiometer is 10 cm and another potentiometer is 20 cm if the EMF of the first potentiometer is 5 V then what is the EMF of another potentiometer.
So according to above information we have,
$ \Rightarrow EMF \propto {\text{length}}$
$ \Rightarrow \dfrac{{{{\left( {EMF} \right)}_1}}}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{{L_1}}}{{{L_2}}}$
$ \Rightarrow \dfrac{5}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{10}}{{20}}$
$ \Rightarrow {\left( {EMF} \right)_2} = 10$ V.
So the EMF of another cell is 10 V.
So this is the required answer.
Note – There is always a great bit of confusion between a potentiometer and a rheostat. A potentiometer is a three terminal device used for current control and a rheostat is an electromechanical device designed so that the resistance values can easily be changed. A rheostat is used in potentiometer assembly so as to vary the resistance across specific lengths of potentiometer.
Complete Step-by-Step solution:
Principle of potentiometer:
The principle of potentiometer is that, for a wire having uniform area of cross section, the potential drop in the wire is directly proportional to its length.
The above principle is valid only when the potentiometer is used in comparing the EMF of two cells.
For example:
Consider two potentiometers the length of the first potentiometer is 10 cm and another potentiometer is 20 cm if the EMF of the first potentiometer is 5 V then what is the EMF of another potentiometer.
So according to above information we have,
$ \Rightarrow EMF \propto {\text{length}}$
$ \Rightarrow \dfrac{{{{\left( {EMF} \right)}_1}}}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{{L_1}}}{{{L_2}}}$
$ \Rightarrow \dfrac{5}{{{{\left( {EMF} \right)}_2}}} = \dfrac{{10}}{{20}}$
$ \Rightarrow {\left( {EMF} \right)_2} = 10$ V.
So the EMF of another cell is 10 V.
So this is the required answer.
Note – There is always a great bit of confusion between a potentiometer and a rheostat. A potentiometer is a three terminal device used for current control and a rheostat is an electromechanical device designed so that the resistance values can easily be changed. A rheostat is used in potentiometer assembly so as to vary the resistance across specific lengths of potentiometer.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

