Answer
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Hint:First we have to see what is meant by color coding of a resistor: The color coding of a resistor provides an identification value for their tolerance along with their resistive value. There are a wide range of sorts of Resistor accessible which can be utilized in both electrical and electronic circuits to control the progression of flow or to create a voltage drop from various perspectives. In any case, so as to do this the real resistor needs to have some type of "resistive" value. Resistors are accessible in a scope of various resistance values from parts of an Ohm ( $\Omega $ ) to a large number of Ohms.
Complete step by step answer:
The resistance value, tolerance and wattage rating are for the most part imprinted onto the body of the resistor as numbers or letters when the resistors body is sufficiently large to peruse the print, for example, enormous power resistors. Yet, when the resistor is little, for example, a $\dfrac{1}{4}$ watt carbon or film type, these determinations must have appeared in some other way as the print would be too little to even think about reading.
So to solve this, little resistors utilize shaded painted groups to show both their resistive worth and their resilience with the physical size of the resistor demonstrating its wattage rating. These hued painted groups produce an arrangement of distinguishing proof commonly known as a Resistors Color Code.
The resistor shading code markings are constantly perused each band in turn beginning from the left to one side, with the bigger width tolerance band arranged to the correct side showing its tolerance. By coordinating the shade of the primary band with its related number in the digit segment of the shading outline underneath the main digit is distinguished and this speaks to the principal digit of the resistance value.
Once more, by coordinating the shade of the second band with its related number in the digit segment of the color chart we get the second digit of the resistance value, etc. The tolerance for silver color is $ \pm 10\% $ .Numbers attached for brown, black, green and silver are $1,0,5, \pm 10\% $. Therefore, the resistance of the given resistor is $ = 10 \times {10^5}\Omega \pm 10\% = 1.0 \times {10^6} \pm 10\% $.
Hence, option C is correct.
Note:The tolerance for gold and silver is a fixed value, the only change being in the sign convention. If there are no silver or gold bands present, then the value is $ \pm 20\% $. So, if we change the values of silver tolerance and colour codes then our answer would be wrong.
Complete step by step answer:
The resistance value, tolerance and wattage rating are for the most part imprinted onto the body of the resistor as numbers or letters when the resistors body is sufficiently large to peruse the print, for example, enormous power resistors. Yet, when the resistor is little, for example, a $\dfrac{1}{4}$ watt carbon or film type, these determinations must have appeared in some other way as the print would be too little to even think about reading.
So to solve this, little resistors utilize shaded painted groups to show both their resistive worth and their resilience with the physical size of the resistor demonstrating its wattage rating. These hued painted groups produce an arrangement of distinguishing proof commonly known as a Resistors Color Code.
The resistor shading code markings are constantly perused each band in turn beginning from the left to one side, with the bigger width tolerance band arranged to the correct side showing its tolerance. By coordinating the shade of the primary band with its related number in the digit segment of the shading outline underneath the main digit is distinguished and this speaks to the principal digit of the resistance value.
Once more, by coordinating the shade of the second band with its related number in the digit segment of the color chart we get the second digit of the resistance value, etc. The tolerance for silver color is $ \pm 10\% $ .Numbers attached for brown, black, green and silver are $1,0,5, \pm 10\% $. Therefore, the resistance of the given resistor is $ = 10 \times {10^5}\Omega \pm 10\% = 1.0 \times {10^6} \pm 10\% $.
Hence, option C is correct.
Note:The tolerance for gold and silver is a fixed value, the only change being in the sign convention. If there are no silver or gold bands present, then the value is $ \pm 20\% $. So, if we change the values of silver tolerance and colour codes then our answer would be wrong.
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