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NCERT Solutions For Class 7 Maths Chapter 1 Integers Exercise 1.2 - 2025-26

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NCERT Solutions For Class 7 Maths Chapter 1 Integers Exercise 1.2 - 2025-26

NCERT Class 7 Maths Exercise 1.2 Solutions can be revised online at Vedantu's website to get all the relevant solutions at one go. The class 7 maths Ch 1 Ex 1.2 solutions are made up by the expert members of Vedantu. Through Vedantu's web portal, NCERT Solution Class 7 Chapter 1 can be best prepared to keep the topics at your fingertips. Exercise 1.2 Class 7 Maths Solutions PDF is now published and students can easily get it through Vedantu's website. Students can also download the study material and prepare for the syllabus offline.  

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Glance on NCERT Solutions Maths Chapter 1 Ex 1.2 Class 7 | Vedantu

  • Integers are whole numbers, including positive numbers, negative numbers, and zero. They don't involve fractions or decimals.

  • Perform basic arithmetic operations like addition (+), subtraction (-), multiplication (*) and division (/). Note that division with integers might have limitations depending on getting a whole number result.

  • Use integers all the time in real life for Counting objects, representing temperatures (Celsius or Fahrenheit) are just a couple of examples.

Access NCERT Solutions for Class 7 Maths Chapter 1 – Integers Exercise 1.2

1. Find each of the following products:

a. $3\,\,\times \,\,\left( -1 \right)$

Ans: While multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product i.e., 

$3\times \left( -1 \right)=-3$


b. $\left( -1 \right)\,\,\times \,\,225$

Ans: While multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product i.e., 

$\left( -1 \right)\times 225=-225$


c. $\left( -21 \right)\,\,\times \,\,\left( -30 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., 

$\left( -21 \right)\times \left( -30 \right)=630$


d. $\left( -316 \right)\,\,\times \,\,\left( -1 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., 

$\left( -316 \right)\times \left( -1 \right)=316$


e. $\left( -15 \right)\,\,\times \,\,0\,\,\times \,\,\left( -30 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., 

$\left( -15 \right)\times \,0\times \left( -18 \right)=0$


f. $\left( -12 \right)\,\,\times \,\,\left( -11 \right)\,\,\times \,\,\left( 10 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., 

$\left[ \left( -12 \right)\times \left( -11 \right) \right]\times \left( 10 \right)=132\times 10=1320$


g. $9\,\,\times \,\,\left( -3 \right)\,\,\times \,\,\left( -6 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., 

$9\times \left[ \left( -3 \right)\times \left( -6 \right) \right]=9\times 18=162$


h. $\left( -18 \right)\,\,\times \,\,\left( -5 \right)\,\,\times \,\,\left( -4 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product i.e., $\left[ \left( -18 \right)\times \left( -5 \right) \right]\times \left( -4 \right)=90\times \left( -4 \right)$   ….. (1)

While multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product i.e., from (1), 

$\left[ \left( -18 \right)\times \left( -5 \right) \right]\times \left( -4 \right)=-360$


i. $\left( -1 \right)\,\,\times \,\,\left( -2 \right)\,\,\times \,\,\left( -3 \right)\,\,\times \,\,4$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product and while multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product i.e., 

$\left[ \left( -1 \right)\times \left( -2 \right) \right]\times \left[ \left( -3 \right)\times 4 \right]=2\times \left( -12 \right)=-24$


j. $\left( -3 \right)\,\,\times \,\,\left( -6 \right)\,\,\times \,\,\left( 2 \right)\,\,\times \,\,\left( -1 \right)$

Ans: While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product and while multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product i.e., 

$\left[ \left( -3 \right)\times \left( -6 \right) \right]\times \left[ \left( 2 \right)\times \left( -1 \right) \right]=\left( 18 \right)\times \left( -2 \right)=-36$


2. Verify the following:

a. $18\,\,\times \,\,\left[ 7+\left( -3 \right) \right]=\left[ 18\times 7 \right]+\left[ 18\times \left( -3 \right) \right]$

Ans: Given expression, $18\times \left[ 7+\left( -3 \right) \right]=\left[ 18\times 7 \right]+\left[ 18\times \left( -3 \right) \right]$.

Simplifying the given expression by first solving the square brackets.

While multiplying a negative integer and a positive integer, multiply them as whole numbers and then put a minus sign $\left( - \right)$ before the product.

$\Rightarrow \,\,18\times \left[ 4 \right]=\left[ 126 \right]+\left[ -54 \right]$ 

$\Rightarrow \,\,72=72$

$\Rightarrow \,\,\text{L}\text{.H}\text{.S}\text{.}=\text{R}\text{.H}\text{.S}\text{.}$

Hence verified.


b. $\left( -21 \right)\times \left[ \left( -4 \right)+\left( -6 \right) \right]=\left[ \left( -21 \right)\times \left( -4 \right) \right]+\left[ \left( -21 \right)\times \left( -6 \right) \right]$ 

Ans: Given expression, $\left( -21 \right)\times \left[ \left( -4 \right)+\left( -6 \right) \right]=\left[ \left( -21 \right)\times \left( -4 \right) \right]+\left[ \left( -21 \right)\times \left( -6 \right) \right]$

Simplifying the given expression by first solving the square brackets.

While multiplying two negative integers, multiply them as whole numbers and then put a plus sign $\left( + \right)$ before the product

$\Rightarrow \,\,\left( -21 \right)\times \left( -10 \right)=84+126$

$\Rightarrow \,\,210=210$

$\Rightarrow \,\,\text{L}\text{.H}\text{.S}\text{.}=\text{R}\text{.H}\text{.S}\text{.}$                                                                     


Hence verified.


3. Solve the following:

i.  For any integer $a$, what is $\left( -1 \right)\,\,\times \,\,a$ equal to?

Ans: $\left( -1 \right)\times a=-a,\,\text{ where }a\text{ is an integer}\text{.}$


ii. Determine the integer whose product with $\left( -1 \right)$ is:

a. $-22$

Ans: The integer whose product with $-1$ is \[-22\] is $22$ i.e., $\left( -1 \right)\times \left( 22 \right)=-22$.


b. $37$ 

Ans: The integer whose product with $-1$ is \[37\] is $-37$ i.e., $\left( -1 \right)\times \left( -37 \right)=37$.


c. $0$ 

Ans: The integer whose product with $-1$ is \[0\] is $0$ i.e., $-1\times 0=0$.


4. Starting from $\left( -1 \right)\,\,\times \,\,5$ write various products showing some patterns to show $\left( -1 \right)\,\,\times \,\,\left( -1 \right)=1$.

Ans: Consider the product, $\left( -1 \right)\times 5=-5$

Also, $\left( -1 \right)\times 4=-4$, $\left( -1 \right)\times 3=-3$, $\left( -1 \right)\times 2=-2$, $\left( -1 \right)\times 1=-1$, etc.

Thus, we can observe that the product of one negative integer and one positive integer is a negative integer.

Similarly, $\left( -1 \right)\times \left( -1 \right)=1$ i.e., the product of two negative integers is a positive integer.


Conclusion

NCERT Solutions for Class 7th Maths Exercise 1.2 offers a thorough explanation of how to add and subtract integers. This practice is essential because it fortifies the basis for increasingly complex mathematical ideas. Students can gain confidence in integer operations—which are crucial for many mathematical applications. Vedantu can enhance comprehension and problem-solving skills. Pay attention to the step-by-step solutions provided, grasp the underlying principles, and ensure clarity on the concepts before moving forward. Students who attentively study through this exercise and comprehend the answer strategies will be able to solve problems more effectively and do better on tests.


Class 7 Maths Chapter 1: Exercises Breakdown

Exercise

Number of Questions

Exercise 1.1

4 Questions and Solutions

Exercise 1.3

7 Questions and Solutions



CBSE Class 7 Maths Chapter 1 Other Study Materials



Chapter-Specific NCERT Solutions for Class 7 Maths

Given below are the chapter-wise NCERT Solutions for Class 7 Maths. Go through these chapter-wise solutions to be thoroughly familiar with the concepts.




Important Related Links for NCERT Class 7 Maths

Access these essential links for NCERT Class 7 Maths, offering comprehensive solutions, study guides, and additional resources to help students master language concepts and excel in their exams.


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FAQs on NCERT Solutions For Class 7 Maths Chapter 1 Integers Exercise 1.2 - 2025-26

1. What topics are covered in the NCERT Solutions for Class 7 Maths Chapter 1, Integers?

The solutions provide detailed, step-by-step answers for all questions in the chapter. They cover key concepts like the properties of integers (closure, commutative, associative, distributive), operations like addition, subtraction, multiplication, and division of integers, and solving word problems based on these concepts.

2. How can I find the correct method to solve problems from all exercises in Class 7 Maths Chapter 1?

The NCERT Solutions provide a systematic, step-by-step methodology for all problems across every exercise in Chapter 1, Integers. Each solution demonstrates the correct application of integer properties and formulas as per the CBSE guidelines, making it easy to understand the logic behind each step.

3. How do the NCERT Solutions for Class 7 Maths Chapter 1 help in preparing for exams?

These solutions are designed to build a strong conceptual foundation. By following the detailed, step-by-step methods, students learn the correct way to present answers in exams. Practising with these solutions helps in identifying common mistakes and understanding the application of integer properties, which is crucial for scoring well.

4. Why is it important to master the sign rules for integers (e.g., negative × negative = positive) as explained in the Chapter 1 solutions?

Mastering sign rules is fundamental because a single error can change the entire result of a calculation. The NCERT solutions repeatedly demonstrate the correct use of sign rules in multiplication and division. This ensures students build the accuracy needed for more advanced topics in algebra, where integers are used extensively.

5. How does understanding integer properties like the distributive property help in solving problems faster?

The distributive property, such as a × (b + c) = (a × b) + (a × c), is a powerful tool for simplifying complex calculations. The NCERT solutions often illustrate how to use this property to break down difficult multiplication problems into simpler steps, which not only saves time but also reduces the chance of calculation errors.

6. What is a common mistake students make when dividing integers, and how do the solutions address this?

A common mistake is getting the sign of the quotient wrong, especially when dividing a negative integer by a negative integer. Students often forget that the result should be positive. The NCERT solutions for Chapter 1 carefully show the sign conversions in each step of a division problem, reinforcing the rule: (-a) ÷ (-b) = a/b.

7. How do the NCERT Solutions for Chapter 1 explain the use of integers in real-life situations?

The solutions for word problems in Chapter 1 demonstrate how integers represent real-world values like temperature above/below zero, elevation above/below sea level, financial transactions (profit/loss), and scores in a game. The step-by-step answers show how to translate these scenarios into mathematical expressions and solve them accurately.

8. Are the NCERT Solutions for Class 7 Maths Chapter 1 updated for the latest 2025-26 syllabus?

Yes, the NCERT Solutions for Class 7 Maths Chapter 1 are fully aligned with the latest CBSE 2025-26 syllabus. The methods and concepts explained in the solutions strictly follow the current NCERT textbook guidelines to ensure students are preparing with the most relevant and accurate material.