5 Digit Addition Explained with Step by Step Method

A 5-digit number contains a 5-digit in which the first digit must be one or greater than one, 5-digit numbers start from 10,000 and go up to 99,999. E.g- 24567,90876,34567 etc. We are going to add two or more two 5-digit numbers.

Positive integers with five digits are shown on a number line as values between 10,000 and 99,999. These numbers have five digits in total. The greatest five-digit number is 99,999 and 10,000 is the smallest five-digit number.

What is Addition?

Addition is the process of finding the total amount of two or more numbers. The result of adding two or more numbers is called the sum or addition. E.g

1. 2+3=5

2. 26+35=61

Addition of 6 and 4

In this above image we can see that we have six apples and four bananas. Then how many total numbers of apples and bananas do we have? Let's add 6 apples + 4 bananas , 6 + 4 = 10. Therefore, we have a total of 10 fruits with us.

5-Digit Numbers

5-digit numbers contain 5-digit and have ones, tens, hundred, thousand, or ten thousand

We use all these when we do five-digit addition with regrouping. Remember that the first digit of a 5-digit number must be greater than or equal to one. E.g

1. 50035- This is a five-digit number in which at ones we have 5, at tens we have 3, at hundred we have 0, at thousand we have 0, at ten thousand we have 5.

2. 04567- This is not a five-digit number because at the start of the number we have 0.

5 digit Number

5-Digit Addition with Regrouping

Regrouping:- In addition, regrouping is a type of addition that involves a sum of digits higher than 9 at any of the place values. To add two numbers using regrouping, first find the total of the digits, then write only the unit place digit in the appropriate column, while taking the tens place digit in the column to the immediate left.

Assume the numbers are 15 and 26 then: Here the sum of 5 and 6 is 11 which is more than 9 so we have written only 1 at the unit’s place and took 1 carryover then added carry to the sum of 1 and 2. So the sum occurs as 41.

E.g Addition of 5-digit numbers with regrouping

Regrouping

Solved Examples

1. Add 34396 and 58124.

Solution:

Step I: Add the ones. 6 + 4 = 10 ones = 1 ten and 0 one. Write 0 in one column and carry 1 to the tens column.

Step II: Add the tens. 9 + 2 + 1 (carry over) = 12 tens. 12 tens = 1 hundred and 2 tens. Write 2 in the tens column and carry 1 to the hundreds column.

Step III: Add the hundreds. 3 + 1 + 1 (carry over) = 5 hundreds. Write 5 in the hundreds column.

Step IV: Add the thousands column. 4 + 8 = 12 thousands. 12 thousands = 1 ten thousand and 2 thousands. Write 2 in the thousands column.

Step V: Add the ten thousand columns. 3 + 5 + 1 (carry over) = 9 ten thousand. Write 9 in ten thousand columns.

Hence, 34396 + 58124 = 92520

2. Add 11821, 60924, and 10200.

Solution

Step I: Add the ones. 1 + 4 + 0 = 5 ones. Write 6 in one column.

Step II: Add the tens. 2 + 2 + 0 = 4 tens. Write 4 in the tens column.

Step III: Add the hundreds. 8 + 9 + 2 = 19 hundreds. 19 hundred = 1 thousand and 9 hundreds. Write 9 in the hundreds column and carry 1 to the thousands column.

Step IV: Add the thousands. 1 + 0 + 0 + 1 (carry over) = 2 thousands. Write 2 in the thousands column.

Step V: Add the ten thousand column. 6 + 1+1 = 8 ten thousand. Write 7 in ten thousand columns. Hense sum become 82945

3. Add 20931 and 85694

Step I:-Add the ones 1+4=5. Write 5 in one column.

Step II:-Add the tens,3+9=12 tens=1 hundred and 2 tens. Write 2 in the tens column and carry 1 over the hundred column

Step III:-Add the hundreds 9+6+1(carry over)=16 hundreds=1 thousand and 6 hundreds. Write 6 in hundreds of columns and 1 carries over a thousand columns.

Step IV:-Add the thousand 0+5+1(carry over)=6 thousand. Write 6 in a thousand columns.

Step V:-Add the ten thousand, 2+8=10 ten thousand. Write 10 in ten thousand columns.

Hence 20931+85694=106,625

4. Add the given numbers:

(i) 20129 and 58992

(ii) 38496 and 59837

(iii) 40128, 21397 and 22588

(iv) 1340, 21980 and 16748

(v) 25908, 256 and 9817

(vi) 44201, 32004 and 8173

(vii) 6415, 386 and 90281

(viii) 11028, 33015 and 48100

Answers

(i) 79121

(ii) 98333

(iii) 84113

(iv) 40068

(v) 35981

(vi) 84378

(vii) 97082

(viii) 92143

5-Digits Addition Word Problems

1. Mike purchased a vehicle for Rs 59425 and spent Rs 86520 on repairs. How much did the vehicle cost him?

Sol. Here first mike gives money for a vehicle and after that for its repair so the total cost of the vehicle =vehicle cost+repair cost

Total costs of vehicle =Rs 145,945.

2. If Raju initially has Rs5000 in his account, his father transfers Rs 45000 to his account. Now, what amount does Raju have?

Sol.

Total amount in Raju bank account =Rs 5000+Rs 45000=Rs 50000.

Word Problems Practice Sheet

1. 82317 people watched the semi-final of the world cup football match, but 31896 more people watched the finals. Find the number of people who watched the finals.

2. Two brothers bought a new television set and gave their old television in exchange. Their old television is valued at Rs 7850. They had to pay the dealer Rs 29375. What was the cost of the new television set?

3. There are 45678 males, 32257 females, and 59179 children in the town. Find the total population of the town.

Answers

1. 114213

2. 37225

3. 137114

Conclusion

In this article we understand about 5- digit numbers in simple words the addition of five-digit numbers to each other is the 5-digit number addition. And we have also studied how to add them by regrouping and also understand how to solve word problems involving numbers.